Henri conducts an experiment to determine who likes peanut butter more: boys or girls. He has 25 girls and 25 boys taste some peanut butter and then rate it on a scale of 1 - 10 with 1 being cannot stand and 10 being tastes delicious.%0D%0A%0D%0AHe finds that the girls had a mean of 7 with a range of 9 and the boys had a mean of 8 with a range of 5. Which statement is true?%0D%0AResponses%0D%0A%0D%0A%0D%0AA%09On average, girls like peanut butter more than boys.On average, girls like peanut butter more than boys.%0D%0A%0D%0A%0D%0AB%09The person who rated peanut butter the worst was a boy.The person who rated peanut butter the worst was a boy.%0D%0A%0D%0A%0D%0AC%09Girls varied more than boys in how they liked peanut butter.Girls varied more than boys in how they liked peanut butter.%0D%0A%0D%0A%0D%0AD%09Half of the boys rated peanut butter a 9 or 10.
On average, boys like peanut butter more than girls. (Option A is false.)
We cannot conclude anything about who rated peanut butter the worst from the given information. (Option B is irrelevant.)
We cannot make a conclusive statement about the variation in ratings between girls and boys. (Option C is unsupported.)
We can conclude that at least half of the boys (i.e. more than half, based on the given mean and range) rated peanut butter a 9 or 10. (Option D is true.)
so 9 or a 10
Yes, that's correct. At least half of the boys rated the peanut butter a 9 or 10 on the scale of 1 to 10.
Mrs. Myles gave the same test to both her first and third period class. In first period, the median was 75 and the range was 30. In third period, the median was 80 and the range was 60. Which is a true statement? [Assume that scores can reach a maximum of 100.]
Responses
A The highest score was in first period.The highest score was in first period.
B There is not enough information to know if any of these is true.There is not enough information to know if any of these is true.
C On average, first period did better than third period.On average, first period did better than third period.
D The lowest score was in third period.
mincraft really AMONG US ALL THE WAYYYYYYYYYYYYYY
I'm sorry, but that statement is not related to the given problem or question. Can I help you with anything else?
We cannot determine which period had the highest score based on the given information. (Option A is false.)
We cannot conclusively compare the performance of the two periods based on just the median and range. (Option C is unsupported.)
We also cannot determine which period had the lowest score based on the given information. (Option D is false.)
Therefore, the correct option is B: There is not enough information to know if any of these is true.
minecraft*
I apologize for the misunderstanding earlier. If you have any questions or concerns related to Minecraft or any other topic, feel free to ask and I'll do my best to help.
STUDENT HOURS
Jack 4.5
Mike 6.25
Adam 3
Jim 2.5
Marty 7
Ben 6.75
At your high school, you randomly surveyed male students to find that they play video games a certain amount of hours per week. What is the estimated population mean based on your sample?
Responses
A 7 hours7 hours
B 2.5 hours2.5 hours
C 6 hours6 hours
D 5 hours5 hours
E 3 hours
To calculate the estimated population mean based on the given sample, we need to take the sum of all hours played by the students in the sample and divide by the number of students (which is 6 in this case).
Sum of hours played = 4.5 + 6.25 + 3 + 2.5 + 7 + 6.75 = 30
Estimated population mean = Sum of hours played / Number of students = 30 / 6 = 5 hours
Therefore, the correct option is D: 5 hours.
A group of middle school boys have a mean height of 167 cm and a range of 164 cm to 169 cm. A group of high school boys have a mean height of 180 cm and a range of 175 cm to 183 cm. Which statement BEST compares the two groups of boys?
Responses
A The high school boys vary in height more than the middle school boys.The high school boys vary in height more than the middle school boys.
B The middle school boys vary in height more than the high school boys.The middle school boys vary in height more than the high school boys.
C On average, the middle school boys are taller.On average, the middle school boys are taller.
D The group of middle school boys has the tallest boy
The range is a measure of the spread of the heights in a group and is calculated as the difference between the highest and lowest values in the group.
The range of the middle school boys is 169 cm - 164 cm = 5 cm.
The range of the high school boys is 183 cm - 175 cm = 8 cm.
Therefore, we can conclude that the high school boys vary in height more than the middle school boys.
The statement that BEST compares the two groups of boys is A: The high school boys vary in height more than the middle school boys.
To estimate the number of lizards in a certain region, Sean traps 36 lizards and marks them. He releases these lizards and then later catches 200, 16 of which are marked. What is the BEST estimate for the lizard population?
Responses
A 400400
B 450450
C 475475
D 425
To estimate the lizard population, we can use the mark and recapture method, which assumes that the proportion of marked lizards in the second sample is equal to the proportion of marked lizards in the entire population.
Let P be the number of lizards in the population.
In the first sample, we marked and released 36 lizards, so the proportion of marked lizards in the population is 36/P.
In the second sample, we caught 200 lizards, of which 16 were marked. So, the proportion of marked lizards in the population is 16/200 = 0.08.
Equating the two proportions, we get:
36/P = 0.08
Multiplying both sides by P, we get:
36 = 0.08 * P
Dividing both sides by 0.08, we get:
P = 450
So the best estimate for the lizard population is 450.
Therefore, the correct option is B: 450.
To gather information about the elk population, biologist marked 75 elk. Later, they flew over the region and counted 250 elk, of which 15 were marked. What is the best estimate for the elk population?
Responses
A 1,2001,200
B 1,3501,350
C 1,2501,250
D 1,300
To estimate the elk population, we can use the mark and recapture method, which assumes that the proportion of marked elk in the second sample is equal to the proportion of marked elk in the entire population.
Let P be the number of elk in the population.
In the first sample, we marked 75 elk, so the proportion of marked elk in the population is 75/P.
In the second sample, we counted 250 elk, of which 15 were marked. So, the proportion of marked elk in the population is 15/250 = 0.06.
Equating the two proportions, we get:
75/P = 0.06
Multiplying both sides by P, we get:
75 = 0.06 * P
Dividing both sides by 0.06, we get:
P = 1,250
So the best estimate for the elk population is 1,250.
Therefore, the correct option is C: 1,250.
The owner of a restaurant wanted to know what additional menu options would sell best. He selects 50 customers at random and surveys them for their preferred menu options.
Identify the population and sample for this situation.
Responses
A The population is the 50 costumers selected; the sample is the menu options.The population is the 50 costumers selected; the sample is the menu options.
B The population is the 50 customers selected; the sample is all the people who live in the town.The population is the 50 customers selected; the sample is all the people who live in the town.
C The population is all the people who live in the town; the sample is the 50 customers selected.The population is all the people who live in the town; the sample is the 50 customers selected.
D The population is all the customers of the restaurant; the sample is the 50 customers selected.
The owner of the restaurant wants to know what additional menu options would sell best. He selects 50 customers at random and surveys them for their preferred menu options.
The population in this situation would be all the customers of the restaurant, as the owner wants to know what additional menu options would sell best to all customers.
The sample in this situation is the 50 customers that were selected randomly and surveyed for their preferred menu options.
Therefore, the correct option is D: The population is all the customers of the restaurant; the sample is the 50 customers selected.
Which is a qualitative variable?
Responses
A gallons of water in poolgallons of water in pool
B breeds of dogsbreeds of dogs
C cups of coffee servedcups of coffee served
D weight of recycled cans
A qualitative variable is a variable that describes a characteristic or quality of an object, event, or person. It is a categorical or nominal variable with no inherent order or value.
Based on this definition, the qualitative variable among the given options is B: breeds of dogs. Breeds of dogs are a categorical variable describing the type or classification of a dog and do not have any numerical value or order.
The other options are all quantitative variables, as they describe a quantity (gallons of water, cups of coffee, weight of recycled cans) and have a numerical value.
4 − 2(10 − 8)(−4) is what
Using the order of operations (PEMDAS) we start by evaluating the expression inside the innermost parentheses first:
10 - 8 = 2
Then we evaluate the expression inside the next set of parentheses:
(−4) = -4
Next, we multiply 2 by -4:
2 x (-4) = -8.
Now we can use the result of the innermost parentheses to evaluate the entire set of parentheses:
4 - 2(-8) = 4 + 16 = 20.
Therefore, the expression 4 − 2(10 − 8)(−4) equals 20.
2 − 1[13 − (1 + 6)] is what
2 + 2[20 − 4(4 + 2)] is what
3 + 2(1 + 8) is what
Let's evaluate each expression using the order of operations (PEMDAS):
1. 2 − 1[13 − (1 + 6)]
= 2 - 1[13 - 7]
= 2 - 1[6]
= 2 - 6
= -4
2. 2 + 2[20 − 4(4 + 2)]
= 2 + 2[20 - 4(6)]
= 2 + 2[20 - 24]
= 2 + 2[-4]
= 2 - 8
= -6
3. 3 + 2(1 + 8)
= 3 + 2[9]
= 3 + 18
= 21
Therefore, the first expression equals -4, the second expression equals -6, and the third expression equals 21.
-5x + 20 < 5 is what solve for x
We can solve the inequality -5x + 20 < 5 as follows:
-5x + 20 < 5
Subtracting 20 from both sides, we get:
-5x < 5 - 20
Simplifying the right-hand side, we get:
-5x < -15
Dividing both sides by -5 but note that dividing by a negative number requires flipping the inequality:
(-5x) / (-5) > (-15) / (-5)
x > 3
Therefore, the solution for the inequality -5x + 20 < 5 is x > 3.
Solve the inequality for x.
-5x + 20 < 5
We can solve the inequality -5x + 20 < 5 as follows:
-5x + 20 < 5
Subtracting 20 from both sides, we get:
-5x < 5 - 20
Simplifying the right-hand side, we get:
-5x < -15
Dividing both sides by -5 but note that dividing by a negative number requires flipping the inequality:
(-5x) / (-5) > (-15) / (-5)
x > 3
Therefore, the solution for the inequality -5x + 20 < 5 is x > 3.
At Store 1 I can buy 36 oz of baby formula for $26.62, and at Store 2 I can buy 28 oz of baby formula for $22.42. Which one is a better buy and by how much?
Responses
A Store 1 by $0.74 an ounce.Store 1 by $0.74 an ounce.
B Store 2 by $0.80 an ounce.Store 2 by $0.80 an ounce.
C Store 2 by $0.06 an ounce.Store 2 by $0.06 an ounce.
D Store 1 by $0.06 an ounce.
To determine which store offers a better deal for baby formula, we need to compare the prices per ounce.
At Store 1, the price per ounce is:
26.62 / 36 = 0.7394 dollars per ounce (rounded to four decimal places)
At Store 2, the price per ounce is:
22.42 / 28 = 0.8007 dollars per ounce (rounded to four decimal places)
Comparing the two prices, we see that Store 1 offers a better deal at $0.7394 per ounce as compared to Store 2 which offers baby formula at a price of $0.8007 per ounce.
To determine the difference between the two prices, we subtract the price at Store 1 from the price at Store 2:
0.8007 - 0.7394 = 0.0613
Therefore, Store 1 is a better buy by $0.06 per ounce.
The correct option is D: Store 1 by $0.06 an ounce.