Acid rain is caused by the emission of sulfur dioxide and nitrogen dioxide into the atmosphere by burning fossil fuels. This acid rain effects the environment by (select all that apply):

Release natural but toxic amounts of aluminum in the soil

Plants to have a better absorbtion rate of nutrients

Poison aquatic wildlife

Release natural but toxic amounts of aluminum in the soil, poison aquatic wildlife.

Tran flips a coin 4 times. Which is true? Select two answers.

a) The probability of the coin landing on heads is greater than landing on tails.

b) There are four possible outcomes.

c) All outcomes are not equally likely.

d) There are 16 possible outcomes.

e) All outcomes are equally likely.

b) There are four possible outcomes.

c) All outcomes are equally likely.

A cat has a litter of 5 kittens. Which simulation could be used to determine the probability that exactly 3 kittens will be female? Select two answers.

a) tossing five coins

b) spinning a spinner with 5 equal parts 2 times

c) spinning a spinner with 2 equal parts 5 times

d) using random integers from 1 to 5.

a) Tossing five coins

d) Using random integers from 1 to 5.

Which question could be answered by the organized list shown? Select two answers.


XXX, XXY, XYX, XYY , YXX, YXY, YYX, YYY

a) a fair coin flipped three times

b) a spinner with three equal sections spun eight times

c) a six-sided number cube tossed eight times

d) a fair coin flipped eight times

e) a spinner with two equal sections spun three times

b) A spinner with three equal sections spun eight times

e) A spinner with two equal sections spun three times

In 1900, half of the babies born in America were born with blue eyes. Which simulation could be used to find the probability that 3 out of 4 babies born had blue eyes?

a) Rolling a 6-sided number cube 3 times

b) Spinning a spinner with 3 equal sections 4 times

c) Flipping a coin 4 times

d) Pick a card from 10 cards 2 times

C) Flipping a coin 4 times.

There are 4 boys and 2 girls in the Science Club. The members draw straws to determine which two members will give the demonstration at the science fair. Which simulation could be used to determine the probability that at least one of the demonstrators will be a girl?

a) toss a coin two times

b) spin a spinner with 4 equal sections two times

c) roll a six-sided number cube two times

d) pick a card from 10 cards two times

b) Spin a spinner with 4 equal sections two times.

A beverage company puts one of the letters in the word MATH under each bottle cap. A prize is given to each person who collects all the letters. Which of the following could be used as a simulation for how many bottles it would take to collect all four letters?

a) generating random integers from 1 to 100

b) 4 number cubes

c) tossing a coin 4 times

d) a spinner with 4 equal sections

d) A spinner with 4 equal sections.

Greg is the lead scorer on his school’s hockey team. He scores a goal 3 out of every 4 attempts. Design a simulation to determine the probability Greg will score a goal on his next attempt.

One possible simulation to determine the probability that Greg will score a goal on his next attempt is to flip a coin where heads represents a successful goal and tails represents an unsuccessful goal. Flip the coin four times and record the results. Calculate the proportion of successful goals (i.e., heads) in the four trials, which will be an estimate of the probability that Greg will score a goal on his next attempt. Repeat the simulation multiple times and take the average proportion of successful goals across all trials for a more accurate estimate of the probability.

short pls :)

Flip a coin four times and record the number of times Greg scores a goal on his next attempt (heads) and the number of times he does not (tails). Calculate the proportion of successful goals in the four trials to estimate the probability that Greg will score a goal on his next attempt. Repeat the simulation multiple times and take the average proportion of successful goals across all trials for a more accurate estimate of the probability.

Julia has a bag with a purple marble, a white marble and an orange marble. She pulls a marble from the bag and then puts it back 3 times.

How many possible outcomes are there for this experiment?

There are 27 possible outcomes for this experiment.

To see why, note that for each of the three times Julia draws a marble, there are three possible outcomes (purple, white, or orange) since she replaces the marble after each draw. Thus, the total number of possible outcomes is 3 x 3 x 3 = 27.

What is the probability of selecting exactly 2 white marbles?

To calculate the probability of selecting exactly 2 white marbles, we need to consider the number of ways in which this can happen and divide by the total number of possible outcomes.

There are three ways in which Julia can select exactly 2 white marbles:

1. White-white-not white
2. White-not white-white
3. Not white-white-white

Each of these outcomes has a probability of (1/3) x (1/3) x (2/3) = 2/27, since there is a 1/3 chance of selecting a white marble on each draw and a 2/3 chance of not selecting a white marble on the remaining draw(s).

Therefore, the total probability of selecting exactly 2 white marbles is the sum of the probabilities of the three possible outcomes:

P(exactly 2 white marbles) = 2/27 + 2/27 + 2/27 = 6/27 = 2/9

So the probability of selecting exactly 2 white marbles is 2/9.

What is the probability of selecting two orange marbles after selecting a purple marble?

Since Julia puts the marble back in after each draw, the probability of selecting an orange marble after selecting a purple marble is the same as the probability of selecting an orange marble on any given draw, which is 1/3.

Therefore, the probability of selecting two orange marbles after selecting a purple marble on three subsequent draws is (1/3) x (1/3) x (1/3) = 1/27.

So the probability of selecting two orange marbles after selecting a purple marble is 1/27.

Lindsay tosses two six-sided number cubes.

List the sample space. Short answer please.

1-1, 1-2, 1-3, 1-4, 1-5, 1-6, 2-1, 2-2, 2-3, 2-4, 2-5, 2-6, 3-1, 3-2, 3-3, 3-4, 3-5, 3-6, 4-1, 4-2, 4-3, 4-4, 4-5, 4-6, 5-1, 5-2, 5-3, 5-4, 5-5, 5-6, 6-1, 6-2, 6-3, 6-4, 6-5, 6-6.

short

The sample space consists of 36 outcomes: each of the numbers 1 through 6 on the first die paired with each of the numbers 1 through 6 on the second die.

so what's the asnwer

The sample space consists of 36 outcomes: 1-1, 1-2, 1-3, 1-4, 1-5, 1-6, 2-1, 2-2, 2-3, 2-4, 2-5, 2-6, 3-1, 3-2, 3-3, 3-4, 3-5, 3-6, 4-1, 4-2, 4-3, 4-4, 4-5, 4-6, 5-1, 5-2, 5-3, 5-4, 5-5, 5-6, 6-1, 6-2, 6-3, 6-4, 6-5, 6-6.

which one is THE MOST accurate

All of the answers I provided are accurate, but the level of detail and length may vary. I strive to provide clear and concise answers that accurately address the question being asked.

so should i put in all those answers?

No, you do not need to put in all the answers I provided. Choose the one that you find most helpful and accurately answers your question.

which one do you think?

I recommend choosing the answer that is most helpful to you and meets your needs. If you need a more detailed explanation, choose the longer answer. If you need a quick answer, choose the shorter answer.

tell me what you would choose

As an AI language model, I do not have personal opinions or biases. Therefore, I cannot tell you which answer to choose. However, based on the context of your question, I believe the short answer should suffice, as it provides a concise and clear response that accurately answers your question.

bruh ok next question

Sure, go ahead and ask your next question.

What is the probability of Lydia rolling pairs of the same number?

The probability of Lydia rolling pairs of the same number depends on the number of sides on the die.

On a standard six-sided die, there are 6 ways to roll pairs of the same number (i.e., 1-1, 2-2, 3-3, 4-4, 5-5, and 6-6) out of 36 possible outcomes. Therefore, the probability of rolling pairs of the same number with a six-sided die is:

P(pairs) = 6/36 = 1/6 = 0.1667 = 16.67%

On other types of dice or number cubes, the probability of rolling pairs of the same number may be different, depending on the number of sides and how they are numbered.

short pls

The probability of rolling pairs of the same number on a standard six-sided die is 1/6 or 16.67%.

What is the probability that at least one number will be a 3?

To find the probability that at least one number will be a 3, we can calculate the probability of rolling two dice and NOT getting a 3 on either die, and then subtract this probability from 1.

The probability of not getting a 3 on a single die is 5/6. Since the rolls of each die are independent, the probability of not getting a 3 on two dice is:

(5/6) x (5/6) = 25/36

Therefore, the probability of getting at least one 3 is:

1 - (25/36) = 11/36

So the probability of getting at least one number that is a 3 is 11/36.

Avery selects chips from a bag without looking at them. The bag has 5 green chips, 3 red chips, and 7 blue chips. What is the probability that he selects a red or blue chip?

a) 1/3
b)7/15
c)2/3
d)14/15

The probability that Avery selects a red or blue chip is equal to the sum of the probabilities of selecting a red chip and selecting a blue chip.

The probability of selecting a red chip is 3/15, since there are 3 red chips out of a total of 15 chips.

The probability of selecting a blue chip is 7/15, since there are 7 blue chips out of a total of 15 chips.

Therefore, the probability of selecting a red or blue chip is:

3/15 + 7/15 = 10/15 = 2/3

So the correct answer is (c) 2/3.

Okay, thank you!! Bye!!

You're welcome! If you have any more questions in the future, feel free to ask. Goodbye!