For the past five baseball seasons, Miguel had 122, 45, 109, 124, and 115 hits. What is his median number of hits for the past five seasons?
A 103 hits
B
109 hits
112 hits
115 hits
Arranging the hits in order from least to greatest: 45, 109, 115, 122, 124. The middle number is 115, which is the median. Therefore, the answer is 115 hits.
The correct answer is D) 115 hits.
12-3 - 10} =
A
14
B 3
• 1
@ 12
$12-3=9$.
Therefore, $12-3-10=9-10=-1$.
The answer is not one of the given options.
7/11+1/2
We need to find a common denominator to add these two fractions. The least common multiple of 11 and 2 is 22.
So,
$\frac{7}{11}+\frac{1}{2}=\frac{7\cdot2}{11\cdot2}+\frac{1\cdot11}{2\cdot11}=\frac{14}{22}+\frac{11}{22}=\frac{25}{22}.$
Therefore, $7/11+1/2=25/22.$
The diameter of circle O is AC, and mBC = 62.
What is mLAOB?
As $BC$ is tangent to circle $O$, we know that angle $\angle BAC$ is a right angle. Therefore, $\angle BOC$ is a central angle of $\angle BAC$, and $\angle BOC = 2\angle LAOB$.
We are given that $BC = 62$, which means that $OC$ is also $62$, since $BC$ is a tangent to circle $O$. We know that the diameter of a circle is twice the radius, so $AC = 2 \times OC = 124$.
Using the Pythagorean theorem, we can find the length of $AB$:
$AB^2 + BC^2 = AC^2$
$AB^2 + 62^2 = 124^2$
$AB^2 + 3844 = 15376$
$AB^2 = 15376 - 3844$
$AB^2 = 11532$
$AB = \sqrt{11532} \approx 107.3$
Now we can use the Law of Cosines to find $\angle BAC$:
$\cos \angle BAC = \frac{AB^2 + AC^2 - BC^2}{2AB \cdot AC}$
$\cos \angle BAC = \frac{11532 + 124^2 - 62^2}{2 \times 107.3 \times 124}$
$\cos \angle BAC = \frac{39520}{26608.4}$
$\cos \angle BAC \approx 1.484$
Since $\cos \angle BAC$ is greater than $1$, we know that $\angle BAC$ is not a real angle. This means there is no solution to this problem.
Destiny is making scrapbooks for friends. She wants to decorate each scrapbook with 1 yard of ribbon. She has a spool with
§ yard of ribbon
6
g
left on it. She plans to use all of the ribbon on the spool. How many
scrapbooks can Destiny decorate?
A 4
B 1
© 3
D 5
If Destiny has $\frac{1}{6}$ yard of ribbon left on the spool, then she used $1-\frac{1}{6}=\frac{5}{6}$ of the yard of ribbon.
Since each scrapbook needs 1 yard of ribbon, she can make $\frac{\frac{5}{6}\text{ yards}}{1\text{ yard per scrapbook}}=\boxed{\textbf{(C) }3}$ scrapbooks.
The diameter of the planet Saturn is about 70,000 miles. Karen built a model of Saturn. The diameter of her model is 5 inches. Which is the scale of Karen's model?
A
B
C
D
1 inch: 14,000 miles
1 mile: 14,000 inches
1 inch: 350,000 miles
1 mile: 350,000 inches
The diameter of Saturn is about 70,000 miles and the diameter of Karen's model is 5 inches.
To find the scale, we need to determine the ratio of the diameter of Saturn to the diameter of Karen's model:
$\text{Scale} = \frac{\text{actual diameter}}{\text{model diameter}} = \frac{70,\!000}{5} = 14,\!000$.
Therefore, the scale of Karen's model is 1 inch: 14,000 miles, or $\boxed{\textbf{(A)}}$.
Ella has 164 ounces of lemonade. She fills glasses with 8 ounces of lemonade each until all the lemonade is gone.
The last glass is not full. How much lemonade is in the last glass?
(A 3 ounces
B
8 ounces
C 12 ounces
D
• 4 ounces
Since each glass is filled with 8 ounces of lemonade, the number of glasses Ella can fill completely is $\frac{164}{8} = 20$ with $\frac{4}{8}$ (or $\frac{1}{2}$) ounce of lemonade remaining.
The last glass is not full, so it has the remaining $\frac{1}{2}$ ounce of lemonade.
Therefore, the answer is $\boxed{\textbf{(D)}\ 4\text{ ounces}}.$
What is the mixed number of 34/5
A 4/5
B 7 1/5
C 3 4/5
D 4 3/5
We know that $5$ divides into $34$ six times with a remainder of $4$. Therefore, we can write:
$\frac{34}{5} = 6\frac{4}{5}$
So the mixed number form of $\frac{34}{5}$ is $\boxed{\textbf{(B) } 6\frac{4}{5}}$.
A grocery store manager is ordering eggs. She orders a box of eggs with 5 trays. Each tray has 6 packs of 6 eggs each. How many eggs are in the box?
A 84
B 180
© 41
0 27
The number of eggs in each pack is $6$, and there are $6$ packs in each tray. Therefore, each tray contains $6 \times 6 = 36$ eggs.
Since there are $5$ trays in a box, there are $5 \times 36 = 180$ eggs in a box.
The answer is $\boxed{\textbf{(B)}\ 180}.$
Grass seed is going to be spread over a playing field. The number of bags of seed needed depends on the size of the field. The rectangular field is 90 yards long and 54 yards wide. What is the area of the field?
A 4,860 square yards
B
141 square yards
C 144 square yards
D 4,862 square yards
The area of a rectangle is found by multiplying its length and width.
The length of the field is 90 yards and the width is 54 yards, so the area is:
$90\text{ yd} \times 54\text{ yd} = 4,\!860\text{ square yards}$
Therefore, the answer is $\boxed{\textbf{(A)}\ 4{,}860 \text{ square yards}}.$
When a number is increased by 35, the result is 38. What equation fits this statement?
A X-35 = 38
B × + 38 = 35
c x-38 = 35
D
x + 35 = 38
Let $x$ be the number.
The statement "When a number is increased by 35, the result is 38" can be written as:
$x+35=38.$
Therefore, the correct equation is $\boxed{\textbf{(D)}\ x+35=38}.$
On Tuesday, Cyrus bought 5 T-shirts for $11 each. He also bought 4 sports caps for $12 each and a pair of shoes for $28. How much money did Cyrus spend on Tuesday?
A $51
B • $131
© $143
D $103
Cyrus bought 5 T-shirts at $11 each, for a total of $5 \times 11 = 55$ dollars.
He bought 4 sports caps at $12 each, for a total of $4 \times 12 = 48$ dollars.
He also bought a pair of shoes for $28.
Adding all his purchases together:
$55 + 48 + 28 = \boxed{\textbf{(C) }143}$ dollars.
Therefore, Cyrus spent $\boxed{\textbf{(C)}\ 143}$ dollars on Tuesday.
A family eats at a restaurant and leaves a tip that increases the cost of the meal by 20%. The cost of the meal before the tip is $41.27. How much is the cost of the meal with the tip included?
A$33.02
B$74.29
C $49.52
D • $8.25
If the cost of the meal before the tip is $41.27$, then a 20% tip would be:
$0.2 \times 41.27 = 8.254$
So the total cost of the meal with the tip is:
$41.27 + 8.254 = \boxed{\textbf{(C)}\ 49.52}$ dollars.