the perimeter of a rectangle is 42cm and its length is xcm find its width in terms of x
Let the width be 'w'.
Perimeter (P) = 2(L + w) = 42
Substituting L = x, we get:
2(x + w) = 42
x + w = 21
w = 21 - x
Therefore, the width of the rectangle in terms of 'x' is (21 - x) cm.
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Perimeter of a rectangle is 2(L+B) perimeter is 42cm Lenght is Xcm
The perimeter of a rectangle is 42cm and it's length is xcm find the width.
Swer
Answee
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formula for perimeter of a rectangle is: 2(L+B) =42 since L and B is x and x , then 2(x+x)=42 :4x= 42 :x=10.5, l=10.5 ×2=21. and b=21
formula for perimeter of a rectangle is: 2(L+B)
since L and B are x then
2(x+x)=42 : 4x=42 ,2x=21
What is the answer
2(w+x) = 42
w+x = 21
Now finish up