simplify 10P4
210
360
5,040
151,200
I think 360
Speaking of people keeping their mouths shut until they know the situation... there's no reason for you to tell me to grow up. I was just trying to inform Damon of what I thought had been told were the rules. I apologized and admitted I was wrong, all while being polite. You didn't need to be rude. I normally avoid losing my temper, but just because you're a tutor doesn't mean that you can go around making unkind assumptions about people. For your information, most people would consider me very mature. Also, I'm sure you'll delete this comment because you don't want to be embarrassed, but I'm still saying this because someone has to.
So you deleted the other person's comment but not mine? That hardly seems fair...
thx Damon!
YOU ACT LIKE WE ARE SUPPOSED TO KNOW THAT!!!!
I'm sorry Ms. Sue, but I didn't know that and was simply saying what I thought were the rules (and what another tutor told me).
bruh Ms. Sue had no right to be so rude
10! /(10-4)! = 10!/6! = 10*9*8*7 = 5040
Damon is correct.
just gonna mention, tho, that normally you shouldn't give them the direct answer
I don't mean to be rude Ms. Sue BUT HOW ARE WE SUPPOSED TO KNOW THAT PLZ EXPLAIN!!!!!!!
THAT'S SO TRUE. (I just was spectating)
15. Simplify 10P4. (1 point)
O210
O 360
O 5,040
O 151,200
The answer is 5,040.
Simplify 15C3. (1 point)
O 182
O 455
O2,730
0910
The answer is 455.
You and 5 friends go to a concert. In how many different ways can you
sit in the assigned seats?
(1 point)
O 720
O 120
O 30
O 15
We can use the formula of permutation. The number of arrangements of n distinct objects taken r at a time is given by the formula:
nPr = n! / (n-r)!
Here, n=6 (you and 5 friends) and r=6 (number of seats).
So, the number of ways you can sit in the assigned seats is:
6P6 = 6! / (6-6)! = 6! / 0! = 6 x 5 x 4 x 3 x 2 x 1 = 720
Therefore, the answer is 720.
You own 5 pairs of jeans and want to take 2 of them with you on vacation. In how many ways can you choose 2 pairs of jeans?
(1 point)
10 ways
O 15 ways
O 4 ways
O 20 ways
We can use the combination formula. The number of combinations of n distinct objects taken r at a time is given by the formula:
nCr = n! / r!(n-r)!
Here, n=5 (number of pairs of jeans) and r=2 (number of pairs to be chosen).
So, the number of ways you can choose 2 pairs of jeans is:
5C2 = 5! / (2!3!) = 10
Therefore, the answer is 10 ways.