The first and the last term of an AP are 6.7 and 17.1 respectively. If there are 14 terms in the sequence find the common difference
Pls how do i solve it
The 14th term is 13 terms after the 1st.
So, the common difference is
(17.1-6.7)/13 = 0.8
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Solve the question fully from the beginning
I don't understand how you solve the question
The 14th term is 13 terms after the 1st.
So, the common difference is
formular(first term-last term / the number of terms in the squence)
(17.1-6.7)/13 = 0.8
Correct
correct
cf