CaCo3+ HCl = CaCl2 + H2CO3
SO 1 mol of CaCO3 will give 1 mol of CaCl2.
mass of CaCO3= 25g
Molar mass of CaCO3= 100g
therefore moles of CaCO3 = 25/100 =0.25
thus 0.25 moles of CaCl2 will be produced
same as moles of CaCO3
CaCO3 = 100 g/mol = 40 + 12 + 48
so we have 0.25 mols of lime and will get 0.25 mols of CaCl2
Calculate the number of moles of calcium chloride (Cacl2) that can be obtained from 25g of limestone (Caco3) in the presence of excess hydrogen chloride (HCl)
Calculate the number of moles of calcium chloride CaCl2 that can be obtained from the 20g linestone CaC3 in the presence of excess hydrogen chloride (Can=40,it=1,C=12 O = 16 ,Cl=35.5)
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yes
Mass of caco3
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Calculate the number of mole of calium chride cacl2 that can be obtaibed from 25g of lime stone. Caco3 in the present of excess of hydrogen chloride hcl (ca 40, (12,o 16, h 1 cl (355)
oyes i know how
I don't understand how to solve it
I don't understand how to solve it
Caco3 +2Hcl(aq)=cacl2+h2o (l)+co2(g)
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Calculate the mole of cacl2 that can be obtained from 30g of caco3 in the presence of excess hydrochloric acid
Don't understand
How is that 48 gotten
Calculate the number of moles of calcium chloride Cacl2, that can beobtained from 25g of lime stone, Caco3, in the presence of excess hydro chloric acid,HCL