Construct triangle xyz such that x=z=45degree and xz=8cm
I don't know how to construct XYZ <X=Z 45° and /XZ/8cm
I don't understand it please teach me
I don't know how I will construct the two
Pliz help me
Aren't we supposed to get answers or something
I don't know how to bisect ∆ such that ^X=^Z=45°
Yes
ok
now what?
Surely you can bisect a 90-degree angle...