The probability of winning a game is 20%. If you play 20 times, how many times should you expect to

win?

Well I purposefully failed this test for answers so here they are

A
B
C
C
B
A
B
A
C
B

Your welcome

i just wanna say something not many people noticed? connexus coward i wanna say Thank you. i mean you purposely failed just to give a stranger correct answers. so much thank yous! you did a kind thing for no reason. i hope you and your family are doing okay in this pandemic :)

Thanks connexus coward 100%!

100% thank you Connexus coward

thank you connexus coward

A
B
C
C
B
A
B
A
C
B
100% don't thank me thank connexus coward
thank you connexus coward!!

You're welcome

I REALY NEED ALL THE ANSWERS PLEASE SEND HALP IM NOT JOKING

Thx

The probability of winning a game is 20% if you play 20 times how many times should you expect to win

thank you guys sooo much im just happy to help!!

Using data to make predictions practice:

1) First two are percentages so do 20% minus 20 and what do you get? The answer is..
1) 4 times
2)6 tickets
3)32 people
4)400 flashlights
5)36 students
6)5 questions
7)150 students
8) 320 bags
9)600 families
10)160 diners

ty

Yeah thanks connexues coward

Thanks Steve for answering

Aubrey this test is not graded

That wasn't funny

1. 4 times

2. 6 tickets
3. 32 people
4. 400 flashlights
5. 36 students
6. 5 questions
7. 150 students
8. 320 bags
9. 600 families
10. 160 diners

1.A

2.B
3.C
4.C
5.B
6.A
7.B
8.A
9.C
10.B
I really hope this helps y'all πŸ’―πŸ’―πŸ’―πŸ’―πŸ’―πŸ’―πŸ’―πŸ’―πŸ’―πŸ’―πŸ’―πŸ’―
HAVE A GREAT DAYπŸ˜€πŸ˜€πŸ˜€πŸ˜€πŸ˜€πŸ˜€πŸ˜€πŸ˜€πŸ˜€

You guys should try to figure it out yourselves. It’s actually real easy.

All you have to do it grab two of the numbers and multiply them and you got your answer.

Example: 0.20 x 20 =4

Example: 0.40 x 80 =32

Just use a calculator.

Practice

A
B
C
C
B
A
B
A
C
B
Quick Check
B
A
A

I hope this helps :p
Bye!

Thank you Brights1174 and ConnexusCoward

number 4 is C

the probability of winning a game is 20% how many times should you expect to win if you play 40 times

You would expect to win 8 times if you play 40 times.

20% of 40 games = 0.20 x 40 = 8

A survey showed that 36% of car owners prefer two-door cars, 52% prefer four door cars and 12% have no preference. you ask 300 people. How many do you think will prefer the two-door car?

A.108 people
B.192 people
C.253 people
D.300 people

We can use the percentage of people who prefer two-door cars to find the expected number of people among 300 who prefer two-door cars as follows:

Expected number =
(Percentage of people who prefer two-door cars) x (Total number of people surveyed)
= 0.36 x 300
= 108

Therefore, we can expect 108 people to prefer two-door cars among a survey of 300 people.

The answer is A) 108 people.

Sally works in a factory that produces 1,000 televisions each day. When 40 televisions were sampled, it was found that 6 were defective. Estimate how many defective televisions are made each day.

A.17
B.96
C.150
D.360

We can use proportion to estimate how many defective televisions are made each day.

The proportion of defective televisions in the sample is:

6/40 = 0.15 or 15%

We can use this proportion to estimate the number of defective televisions among the total production as follows:

Number of defective televisions =
(Proportion of defective televisions) x (Total number of televisions produced each day)
= 0.15 x 1000
= 150

Therefore, we can estimate that 150 defective televisions are made each day.

The answer is C) 150.

The spinner is divided into equal parts. use a tree diagram to find the probability that the spinner will land on a consonant both times if the spinner is spun twice.

1/9
1/3
5/9
3/4

Assuming that the spinner has 6 equal parts - 4 parts with consonants and 2 parts with vowels, the tree diagram can be constructed as follows:

```
C V
/ \ / \
C V C V
/ \ / \
C V C V
```

The four possible outcomes of spinning the spinner twice are CC, CV, VC, and VV, where C represents a consonant and V represents a vowel.

The probability of landing on a consonant the first time is 4/6 or 2/3. The probability of landing on a consonant the second time, given that a consonant was spun the first time, is also 4/6 or 2/3.

Therefore, the probability that the spinner will land on a consonant both times is:

(2/3) x (2/3) = 4/9

The answer is not one of the options given. It is 4/9.

The spinner is divided into equal parts. use a tree diagram to find the probability that the spinner will land on a consonant both times if the spinner is spun twice. NEU

1/9
1/3
5/9
3/4

The answer is not one of the options given. It is 4/9. I apologize for the confusion in my previous response.

An ice cream shop offers 5 different flavors of ice cream and 12 different toppings how many choices are possible for a single serving of ice cream with one. topping

To find the total number of choices possible for a single serving of ice cream with one topping, we can use the multiplicative principle of counting, which states that if there are m ways to perform one task and for each of these ways, there are n ways to perform another task, then there are m x n ways to perform both tasks.

In this case, we can treat the choice of the ice cream flavor and the choice of the topping as two separate tasks.

There are 5 different flavors of ice cream, so there are 5 ways to choose the ice cream flavor.

For each of these 5 ways to choose the ice cream flavor, there are 12 different toppings to choose from.

Therefore, there are 5 x 12 = 60 choices possible for a single serving of ice cream with one topping.

The answer is 60.

Sammy likes to mix and match her 4 necklaces, 2 bracelets, and 3 hats. The colors are listed in the table. On Monday, she randomly picks a bracelet, a neckless, and a hat. What is the probability of Sammy choosing a red necklace and a yellow bracelet?

Since Sammy has 4 necklaces, 2 bracelets, and 3 hats to choose from, there are a total of:

4 x 2 x 3 = 24 different combinations of necklace, bracelet, and hat.

Out of these 24 combinations, the number of combinations where Sammy chooses a red necklace and a yellow bracelet is 1 (since there is only 1 red necklace and 1 yellow bracelet).

Therefore, the probability of Sammy choosing a red necklace and a yellow bracelet is:

1/24

The answer is 1/24.

Sammy likes to mix and match her 4 necklaces, 2 bracelets, and 3 hats. The colors are listed in the table. On Monday, she randomly picks a bracelet, a neckless, and a hat. What is the probability of Sammy choosing a red necklace and a yellow bracelet?

1/2
1/5
1/9
1/8

The answer is not one of the options given. It is 1/24.

what is equal to 1/24

1/2
1/5
1/9
1/8

1/24 is not equal to any of the options given.

what is closer to 1/24

1/2
1/5
1/9
1/8

The answer that is closest to 1/24 is 1/8.

which event are not independent

A.you draw two colored marbles without replacement and get one red and one blue.
B.you pull a green Tite from a bag tile return it and then pull a yellow tile.
C.you toss two coin and get one head, one tail.
D.you choose two different ice cream flavors for a cone

The event that are not independent are:

A. you draw two colored marbles without replacement and get one red and one blue. This event is not independent because the outcome of the first draw will affect the probability of the second draw. For example, if a red marble is drawn first, there will be one less red marble and one less marble overall for the second draw, which will affect the probability of drawing a blue marble.

B. you pull a green tile from a bag, return it, and then pull a yellow tile. This event is independent because the tile is returned after the first draw, so the probability of getting a yellow tile on the second draw is not affected by the outcome of the first draw.

C. you toss two coins and get one head, one tail. This event is not independent because the outcome of the first toss will affect the probability of the second toss. For example, if the first toss results in heads, the probability of getting tails on the second toss is higher than if the first toss resulted in tails.

D. you choose two different ice cream flavors for a cone. This event is not independent because the choice of the first flavor will affect the probability of choosing the second flavor. For example, if the first flavor chosen is chocolate, the probability of choosing another chocolate flavor will be lower since there are fewer chocolate options available.

A coin tossed and a number cube is rolled. What is the probability that the coin shows heads and the number cube shows? 5?

1/6
1/12
2/3
1/4

Since the coin has two equally likely outcomes (heads or tails) and the number cube has six equally likely outcomes (numbers 1 through 6), the total number of possible outcomes is:

2 (outcomes for coin) x 6 (outcomes for number cube) = 12 possible outcomes

Out of these 12 possible outcomes, only one satisfies the condition of getting a heads on the coin and a 5 on the number cube.

Therefore, the probability of getting a heads on the coin and a 5 on the number cube is:

1/12

The answer is option B: 1/12.

On Friday night the local diner serves three main entrees, each with a choice of vegetables. The entrees are beef chicken and fish the vegetables are spinach broccoli and carrots how many possible dinners entree and vegetables combinations does the diner serve list them

There are 3 main entrees and 3 vegetable choices. To find the total number of possible dinner entree and vegetable combinations, we can use the Multiplication Principle of Counting, which states that if there are m ways to perform one task and n ways to perform another task, then there are m x n ways to perform both tasks.

Using this principle, we can find the total number of possible dinner entree and vegetable combinations as follows:

- For each of the 3 entrees, there are 3 vegetable choices. Therefore, the number of possible dinner combinations for each entree is 3.
- Since there are 3 entrees, we can use the Multiplication Principle of Counting to find that the total number of possible dinner entree and vegetable combinations is:

3 (entrees) x 3 (vegetable choices) = 9

Therefore, the diner serves 9 possible dinner entree and vegetable combinations, which are:

- Beef with spinach
- Beef with broccoli
- Beef with carrots
- Chicken with spinach
- Chicken with broccoli
- Chicken with carrots
- Fish with spinach
- Fish with broccoli
- Fish with carrots

Connexus coward is correct for

6.4.5 - Practice: Using Data to Make Predictions Practice
Math 6 Spring 2020/2021 / 6. Exploring Probability / 6.4. Using Data to Make Predictions

um u ok?

.20 * 20 = ?