An elastic cord can be stretched to it's elastic limit by a load of 2n.if a 35cm length of the cord is extended 0.6cm by a force of 0.5n.what will be the length of the cord when the stretching force is2.5n

the ans is 352.8cm

It cannot be determined from the data given

K = 0.5N/0.0.6cm = 0.833 N/cm.

Length = 35 + 2N*1cm/0.833N = 37.40 cm.

Increasing the force above 2N do
not increase length further.

Henry is correct

What about the 2.5N

It cannot be determined at all

Cannot be determined from the data given.

Pls for the length, am not sure you calculated well

pls amy show ur workings๐Ÿฅบ๐Ÿฅบ๐Ÿ˜ž

Cannot be determined from the data given.

The answer is 2000000000000000000000000000000000000000000000000000000000000004000000000000000000000000000000000000003000000000000009999900/00000000000000984747473+4+483;32828+33+37373737337838228(23++373-37374-37374+3737373737373373773737374474747474747474743737382929291001012982733773737373382829191910101018272626268283849494949949484(44!448448848483883939392928283+37373737337377374849494949484747447473882822+2+2(2(2828387337737373737377338373737733733738389220020100191711+3-3+37377373373737373737. I hope you got the answer above.

i dont understand how u got to that answer 37.40

Cannot be determined with the give data.

Dumb

Already, the spring has reached it's elastic limit at 2N so increasing the stretching force to 2.5N will not yield any good result further. So I think the correct answer is that the length can not be determined

It cannot be determined from the data given

Pls i hope this answer is the correct one plz

it cannot be determined from the given data

8.33

Pls is dat the correct answer ๐Ÿ™๐Ÿ™๐Ÿ™๐Ÿ™

Pls for the length,am not sure you calculated it well

anybody should snd d workings with d answer