The 9th And 22nd Term Of An A.P Are 29 And 55 Respectively. Find The Sum Of It's First 60 Terms
That method is soo incorrect for solving sum on an AP
You didn't even find the first term and common difference
Is the answer correct because my teacher did not teach me like this. Please answer me
That's nice and correct,gud!!!!!
Correct that's nice,gud!!!!!!!!!
i'm in doubt of it correctness
can u make the answer more simplified? it a bit mesmerising.
Answer
Nearest
incorrect
You are out of point
The method is so incorrect I don't know how you got your answers
your answer is correct, because i am a mathematician
T(9)=29.............9th term
T(22)=55............22nd term
If the AP is T(n)=T(n-1)+d, then
d=(T(22)-T(9))/(22-9)=26/13=2
T(1)=T(9)-(9-1)d = 13
and therefore
T(n)=11+2n
T(1)=13
T(60)=11+120=131
To find the sum of the 1st to the 60th term, we use Little Gauss's method:
T(1)+T(2)+....T(30)
T(60)+T(59)+...T(31)
-----------------------(add)
T(1)+T(60) + T(2)+T(59) + ...(30 times)
=30(13+131)=4320