simplify 10p4
A. 210
B. 360
C. 5,040
D. 151,200
simplify 9c4
A. 126
B. 15,120
C. 5
D. 3,024
The answer is 5,040
Dark dream is not correct I only got 50%
the answer to 10p4 is 5,040
We know that:
10P4 = 10! / (10 - 4)!
= 10! / 6!
= (10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / (6 × 5 × 4 × 3 × 2 × 1)
= 10 × 9 × 8 × 7
= 5,040
Therefore, the answer is 5,040.
Sure, we know that:
10P4 = 10! / (10 - 4)!
= 10! / 6!
= (10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / (6 × 5 × 4 × 3 × 2 × 1)
= 10 × 9 × 8 × 7
= 5,040
Therefore, the answer is 5,040.
I need answer
@Reiny could you explain to me how to solve the equation? What does the "C" mean?
Bot can you simplify 10p4
Bot can you please simplify 9c4
We know that:
9C4 = 9! / (4! × (9 - 4)!)
= 9! / (4! × 5!)
= (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / [(4 × 3 × 2 × 1) × (5 × 4 × 3 × 2 × 1)]
= (9 × 2 × 3 × 7)
= 378
Therefore, the answer is 378.
bot can you please . Simplify 10P4
.
bot please Simplify 8C5
Sure, we know that:
8C5 = 8! / (5! × (8 - 5)!)
= 8! / (5! × 3!)
= (8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / [(5 × 4 × 3 × 2 × 1) × (3 × 2 × 1)]
= 8 × 7 × 2
= 112
Therefore, the answer is 112.
bot what does the ! mean in 8!
In mathematics, the exclamation mark (!) symbol is used to denote the factorial of a non-negative integer.
For example, 8! means the product of all positive integers from 1 to 8:
8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40,320.
thanks bot
You're welcome! Let me know if you have any other questions.
bot, can you simplify 15C3?
Sure, we know that:
15C3 = 15! / (3! × (15 - 3)!)
= 15! / (3! × 12!)
= (15 × 14 × 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / [(3 × 2 × 1) × (12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)]
= (15 × 14 × 13) / (3 × 2 × 1)
= 455
Therefore, the answer is 455.
bot…
You and 3 friends go to a concert. In how many different ways can you sit in the assigned seats?
If you and your 3 friends go to a concert and want to sit in the assigned seats, then there are 4 people in total who need to be seated.
The first person can sit in any of the 4 seats. After the first person chooses a seat, there are only 3 seats left for the second person to choose from. Once the second person chooses a seat, there are only 2 seats left for the third person to choose from. Finally, the last person will have only 1 seat left to choose.
So, the total number of different ways that you and your 3 friends can sit in the assigned seats is:
4 × 3 × 2 × 1 = 24
Therefore, there are 24 different ways that you and your 3 friends can sit in the assigned seats.
bot, you own 6 pairs of jeans and want to take 2 of them with you on vacation. In how many ways can you choose 2 pairs of jeans?
If you own 6 pairs of jeans and want to take 2 of them with you on vacation, then you need to choose 2 pairs of jeans from the 6 pairs that you own.
The number of ways to choose 2 pairs of jeans from 6 pairs is given by the formula for combinations:
6C2 = 6! / (2! × (6 - 2)!)
= 6! / (2! × 4!)
= (6 × 5 × 4 × 3 × 2 × 1) / [(2 × 1) × (4 × 3 × 2 × 1)]
= 15
Therefore, there are 15 different ways that you can choose 2 pairs of jeans from 6 pairs.
Bot can you simplify 9c4-
We know that:
9C4 = 9! / (4! × (9 - 4)!)
= 9! / (4! × 5!)
= (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) / [(4 × 3 × 2 × 1) × (5 × 4 × 3 × 2 × 1)]
= (9 × 2 × 3 × 7)
= 378
Therefore, 9C4 is equal to 378.
Note that the second part of your question (the dash) could not be interpreted as it is missing a value or operation after the dash.
Hey bot I need helllppppp
Sure, I'm here to help! What do you need help with?
How many ways can 4 students be chosen from a class of 12 to represent their class at a banquet
The total number of ways that 4 students can be chosen from a class of 12 to represent their class at a banquet is given by the formula for combinations:
12C4 = 12! / (4! × (12 - 4)!)
= 12! / (4! × 8!)
= (12 × 11 × 10 × 9) / (4 × 3 × 2 × 1)
= 495
Therefore, there are 495 different ways that 4 students can be chosen from a class of 12 to represent their class at a banquet.
Can you help with this too?
you and 5 friends go to a concert. In how many different ways can you sit in the assigned seats?
Sure, if there are 6 people (you and 5 friends) who want to sit in the assigned seats at the concert, then the number of ways that they can sit can be calculated using the formula for permutations:
6P6 = 6!
= 6 × 5 × 4 × 3 × 2 × 1
= 720
Therefore, there are 720 different ways that you and 5 friends can sit in the assigned seats at the concert.
and this is the last one.
You own 5 pairs of jeans and want to take 2 of them with you on vacation. In how many ways can you choose 2 pairs to take with you
If you own 5 pairs of jeans and want to take 2 of them with you on vacation, then the number of ways that you can choose 2 pairs to take with you is given by the formula for combinations:
5C2 = 5! / (2! × (5 - 2)!)
= 5! / (2! × 3!)
= (5 × 4 × 3 × 2 × 1) / ((2 × 1) × (3 × 2 × 1))
= 10
Therefore, there are 10 different ways that you can choose 2 pairs of jeans to take with you on vacation.
okay! Thank you Bot!
You're welcome! Feel free to ask if you have any more questions.
Are dark dreams answers correct or not?????
so is dark dreams right?
Use your definitions and evaluate
e.g.
11C5 (not your question)
= 11! / (5!6!)
= 462
Test answers
1. D
2. D
3. C
4. A
5. A
6. C
7. D
8. A
9. D
10. B
11. C
12. B
13. C
14. A
15. C
16. B
for probability unit test part 1, i might post the part 2 answers