4. Which equation would you use to find out if the two lines in the graph are parallel? (1 point)

LINE #1:
point a: 1, 4
point b: -2, 1

LINE #2:
point c: 3, 3
point d: -1, -1

a. 4 - 1/-2 - 1 = 3 - 1/3 - 1
b. 4 - 1/-2 - 1 = 3 - (-1)/3 - (-1)
c. 4 - 1/1 - (-2) = 3 - (-1)/3 - (-1)
d. 1 - (-2)/4 - 1 = 3 - 1/ 3 - 1

i did my best-_-
i know, its confusing. but the graph lines are parrallel. (at least i think they are)
can someone help me? at least tell me how to do this cause my book and lesson DOES NOT.
i might post another one so.....

thanx

The answer is:

1. A = 2:3
2. C = The slopes of the two triangles are the same
3. D = No, the slopes of the new triangle would be 3:5
4. C = 4-1/1-(-2) = 3-(-1)/3-(-1)
5. D = determine if the product of their slope is -1
5/5 100%

Thank you so much mili

thx mili!

Read my name.

Mili is right.

Thanks Mili

Thank you so much Mili!! ;D

A

C
D
C
D
100% Guaranteed! Thanks Mili!

Mili thank you so much! It took you a long time to do that its so nice of you to take out the time to do that!

I just like how it spells ACDC

Thanks so much Mili!!! I got 100% thank you for helping!!

I bet you 12 year olds are going to dislike.

5. How can you determine if the given lines are perpendicular? (1 point)

LINE #1:
point a: 3, 3
point b: -3, 0

LINE #2:
point c: -1, 3
point d: 3, -3

determine if they have slopes with opposite values
determine if they have the same slope
determine if the product of their slopes is 1
determine if the product of their slopes is –1

theyre perpendicular.
so, same goes for this: if u can answer these 2, THANK YOU.
but if u cant (which is understandable) can u tell me how to do both of these questions???

thank you so much

How do you figure out how to format it though? Like what goes where? Is it (y1 - y2)/(x1 - x2) = (y3 - y4)/(x3 - x4) where y/x 1 and 2 are the first line and y/x 3 and 4 are the second?

this is so confusing.

ACDC IS THE ANSWER TO EVERYTHING