2H2(g) + S2(g) ¡ê 2H2S(g)
Analysis of the contents of a 15.0L flask reveals that there are 4.4 moles of hydrogen gas, 2.0 moles of sulfur gas, and 3.7 moles of hydrogen sulfide gas in the flask at equilibrium. Calculate the equilibrium constant K
M each = mols/L = ?
Substitute M of each into the Keq expression for H2 + S2 ==> 2H2S and solve for Keq.
i got an answer of 39.776 because i did [mol/L H2S]^2/ [mol/L H2]^2[mol/L S2]^2 so im not sure what went wrong
What numbers did you substitute for concns H2, S2, H2S?
That should be (H2) = 4.4/15 = ?
(S2) = 2/15 = ?
(H2S) = 3.7/15 = ?
I suspect that's the problem.
i used those exact numbers
And your answers were?
after squaring i ended up with 0.060844444/ (1.529679004 *10^(-3)) = 39.7759555
What numbers do you get for
4.4/15 = ?
2/15 = ?
3.7/15 = ?
4.4/15= 0.293333333
2/15= 0.133333333
3.7/15= 0.246666666
So K = (0.24666)^2/(0.2933)(0.1333) =
Punch in the top numbers and divide by the bottom numbers WITHOUT copying any numbers; i.e., leave everything in the calculatord come up with an answer. I don't get 39.
why don't we square the bottom numbers to?
I forgot the square on H2.
That should be
K = (0.24666)^2/(0.2933)(0.1333)^2
also I got 1.556 but LON CAPA is telling me that is incorrect
okay with the squared H2 it is 11.67414 but again LON CAPA is saying it is incorrect
Sorry. I shouldn't have type the oops in the first place.
The reaction is
H2 + S2 ==> 2H2S
Kc = (H2S)^2/(H2)(S2)
Kc = (0.24666)^2/*0.29333)(0.1333)
You square the H2S because the coefficient is 2.
You raise (H2) and (S2) to the first place since the coefficient for both is 1.
Doing that i get answer to be 1.56 but again it says incorrect
nevermind answer is 5.3 i had to square H2 which was (0.2933) and then multiply. Thank for everything Dr.Bob :)
I typed the wrong equation in so I'm wrong too. Here is how it goes.
2H2 + S2 ==> 2H2S
Kc = (H2S)^2/(H2)^2(S2)
Kc = (0.24666)^2/(0.2933)^2(0.1333)
Kc = 5.3057
You have in the original problem, assuming you typed in all the digits, 4.4, 2.0 and 3.7 and 15.0.
That allows just two significant figures. So the answers should be rounded to 5.3. If the numbers were 4.40 and 2.00 and 3.70 let me know and the number of significant figures will change.