# Posts by yuuka

Total # Posts: 7

**Math**

There are two points: (8,45000) and (11,84000) a, the rate of change is (84000-45000)/(11-8) = 28000/3 b, use the slope 28000/3 and a point, you can plug into the formulas c, once you have the equation, plug in 16 then you will get the answer

**calculus (limits)**

Graph the function and you will see it

**math problem**

Let's say we want to eliminate 's' So multiply 5 to the first equation and multiply 3 to the second equation we get: 25r - 15s = 80 9r + 15s = 90 use the elimination method by adding those two equation -15s and 15s cancels out we get: 34r = 170 Then r = 5

**math**

1) set the two equations equal to each other: 3x-1 = x^2-5x+6 Combine like terms: x^2-8x+7 = 0 Factor: (x-1)(x-7)=0 x = 1, 7

**Calculus 12**

what are you solving for? What is the question?

**math/calculus**

f'(x) = [ln(6)][6^x^2][2x] follow the rules and do f''(x)

**math-calculus**

3x-2 = 2x+5+1 x = 8

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