Physics
An crate weighing 510 N is resting on a plane inclined 30° above the horizontal. (a) Calculate the magnitude of the acceleration (ignore friction). m/s2 (b) After 3.00 s, how fast will the crate be moving?
argosy
Hello, you should review the materials collected at the orientation. Unless you tell us briefly what you learnt at the orientation, we can not guide you in the right direction as to what ideas you need to express.
algebra
Hi Mary, It is not clear what parts of the equation are under the radical sign, but I will guess from the type of problems I have seen. [] sqrt sign [y + 5] -1=2: Isolate the variable to one side by moving over numbers. [y + 5] = 3. Solve for y by removing the square root sign...
art
Hello, there is no question listed above. Please repost.
math
This is a logic problem. I will write out the steps below. Ja= Jack Ji= Jill Jill gives 50 to Jack, so she has 50 less and he has 50 more. And, this quantity of 50 more is equal to 5 times Jill's amount. So, now Jill has Ji-50 and Jack has Ja + 50 So, now just think how to...
Math
In Grade 8, the teacher probably expects you to research median, mode, mean, or range and apply this to the data you have presented. Show how it relates to your data and explain its significance. Hope this helps!
science
Hello, you can not add vectors by just looking at the numbers. Vectors have magnitude and direction. So, you can only add North and South together, and you can also add East and West vectors together. So, think about vectors on an x-y plane. X is positive in Quadrants 1 and 4,...
math
I think that you have given the distance between the two planks to be 2 feet, but I am not quite sure on this one. I think the technique would be to determine the surface area of that disc that would come in contact with the plank upon reaching the floor. I am quite intrigued ...
Pre-calculus--EDIT TO POST ABOVE
Oh. I realized that you must also pay attention to signs, which I failed to do. In the fourth Quadrant, sin is negative, while cos is positive. So, your new solution will be: So Sin(X + Y)= Sinx Cos y + Cosx Sin y So, Sin x= sin 36.9=-0.60 Cos y= 12/13=0.92 Cos x= 4/5=0.80 Sin...
Pre-calculus
So, since you know Cos x= 0.8, plug in to the calculator Cos inv of 0.8. Do the same for Cos Y= 12/13. X=36.9 degrees Y=22.6 degrees I think that where you are in precalculus, you have to know these trig identities. You MUST memorize them as they are the basis of good foundati...
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