Chemistry
Which one of the following combinations of reagents will result in a spontaneous reaction? A) Al(s) + CuCl2(aq) B) Al(s) + CaCl2(aq) C) Zn(s) + CaCl2(aq) D) Cu(s) + ZnCl2(aq) I know the answer is A, but what I don't know is why, or how to figure this out. Thanks!
Chemistry
You know it's second order so your rate=k[NO2]^2 All you do is like you said, find moles, use that to find molarity (convert mL to L) and then plug the concentration into the equation. You're given the k. Same thing with part B, just changing the concentration :)
Chemistry
All you have to do is find the concentration of OH- and solve for pH (pOH= -log [OH-] nad then 14-pOH=ph [OH-} = Ksp/[M+}
Chemistry
NVM i was using the pKA instead of pH....i had it right afterall...guess it's jsut time for bed....
Chemistry
I figured out the correct new pH for each respective part, but apparently the initial pH i found for the buffer solution is incorrect. I just need help in figuring that so I can calculate the change. I initially thought the buffer pH was 7.38. Thanks!
Chemistry
for part a I tried using the HH equation, found moles of NaOH and used that for [base] and moles Na2HPO4 as [acid]...i used pKa 7.21...that was incorrect. For part b I used a similar method...plugging in HNO3 as the [acid] and Na2HPO4 moles as [base] the other pka values for H...
Chemistry
A buffer solution of volume 100.0 mL is 0.150 M Na2HPO4(aq) and 0.100 M KH2PO4(aq). Refer to table 1. (a) What are the pH and the pH change resulting from the addition of 80.0 mL of 0.0500 M NaOH(aq) to the buffer solution? pH pH change (include negative sign if appropriate) (...
Chemistry
I'm confused how I would use the Ka equation in the HH equation??? I thought HH was just pH=pka + log([base]/[acid]) ...
Chemistry
Calculate the pH of the solution that results from mixing the following reagents. Refer to table 1. mix 0.189 L of 0.019 M (CH3)2NH(aq) with 0.327 L of 0.011 M (CH3)2NH2Cl(aq) I tried using the Henderson-Hasselbach equation by finding the pKa but it didn't work....I am sti...
Chemistry
Nevermind I got it...I just mixed up my variables a little. thanks!
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