Wednesday
December 11, 2013

# Posts by trixie

Total # Posts: 130

Chemistry
A certain Geiger counter is known to respond to only 1 of every 1000 radiation events from a sample. Calculate the activity of each radioactive source in curies, given the following data. My text barely attempts to explain how to do this problem, and there is no example. I am ...

Chemistry
no problem :)

Chemistry
Think of the equations you have learned and which variables you have been given. It helps to keep a list of them in front of you so you can quickly figure it out. Then just plug in. If you have P, V, mass, and T....you're going to use PV=nRT...just solve for P PV=nRT is an...

Chemistry
Nevermind...I realized that the problem I was using as an example called for 1 g of the reactant used....this didn't....so I have my correct answer now. Thanks! Still stumped on my earlier question though...

Chemistry
How much energy is emitted in each α decay of plutonium-234? (234Pu, 234.0433mu; 230U, 230.0339mu; 4He = 4.0026 mu). I tried finding the difference in mass first: (230.0339 + 4.0026) - (234.0433) = -.0068 mu I then converted from amu to kg by multiplying by 1.6605E-27. Th...

Chemistry
Hmm...I don't know. My webassign is telling me it's not a neutron. Thanks

Chemistry
Oh i just realized how you typed the equation has the product flipped. so it's 1,1,H + 1,1P --> 2,1H + ? order is A,Z,X where A is mass and X is the particle or element

Chemistry
neutron was my first answer...i am using +1 e^0 to be a positron though, not electron.

Chemistry
I know they need to balance out on both sides. I am just confused because I am pretty sure it should be 0,+1, e ...e being X. Webassign is telling me this is wrong but if that's true I don't understand why and need that explained....

Chemistry
for A, Z, and X I'm typing it in the form A,Z,X (or X as a particle) since I obviously can't do sub or superscript... 1,1,H + 1,1,p --> 2.1,H + ? I thought initially the missing particle at the end would be either 0,-1,e or 0,1,e (beta emission/decay) but apparently...

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