chemistry
Sleep is a bit of a luxury.....unfortunately I'm one of those students that doesn't have an option of taking a lighter load or working less....luckily I graduate in a few weeks. In the meantime I need to finish these problems so that I can go to bed....but they are due...
chemistry
Another attempt I made gave me relatively "reasonable" answers...but still doing something wrong. I converted the minutes to days and used that in the rate to find k via k= rate/N ; N being 3.25E18 atoms. this calculated k to be .00145. I plugged this into N'=Ne^...
chemistry
Oh and when I try to put this into my calculator I get 0... sorry if I am not catching on fast enough for some....I worked graveyard last night and Haven't slept in over 35 hours...
chemistry
A radioactive sample contains 3.25 1018 atoms of a nuclide that decays at a rate of 3.4 1013 disintegrations per 26 min. (a) What percentage of the nuclide will have decayed after 159 d? % (b) How many atoms of the nuclide will remain in the sample? atoms (c) What is the half-...
Chemistry
A sample of pure cobalt-60 has an activity of 8 µCi. (t1/2 cobalt-60 = 5.26 a) (a) How many atoms of cobalt-60 are present in the sample? atoms (b) What is the mass in grams of the sample? g The way I approached part a was to first convert the microCi into Bq (for a valu...
Chemistry
A certain Geiger counter is known to respond to only 1 of every 1000 radiation events from a sample. Calculate the activity of each radioactive source in curies, given the following data. 580 clicks in 104 s My text barely attempts to explain how to do this problem, and there ...
Chemistry
A certain Geiger counter is known to respond to only 1 of every 1000 radiation events from a sample. Calculate the activity of each radioactive source in curies, given the following data. My text barely attempts to explain how to do this problem, and there is no example. I am ...
Chemistry
no problem :)
Chemistry
Think of the equations you have learned and which variables you have been given. It helps to keep a list of them in front of you so you can quickly figure it out. Then just plug in. If you have P, V, mass, and T....you're going to use PV=nRT...just solve for P PV=nRT is an...
Chemistry
Nevermind...I realized that the problem I was using as an example called for 1 g of the reactant used....this didn't....so I have my correct answer now. Thanks! Still stumped on my earlier question though...
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