Tuesday

March 31, 2015

March 31, 2015

Total # Posts: 511

**General chemistry ligand**

Hello. I have a question about ligands. How do you figure out how many ligands a central metal cation can have? For example, Cu^2+ and NH3. When they combine, it forms Cu(NH3)4^2+ Why does it form 4 ligands oppose to 6? A general rule, which isn't always followed, is to ...
*April 26, 2007*

**Calculus**

Please.... I need your help! I posted this question yesterday and no one has answered it yet. Can anyone help me please? My question was: The Taylor series about x=5 for a certain function f converges to f(x) for all x in the interval of convergence. The nth derivative of f at...
*March 18, 2007*

**calculus-- need help desperately!**

The Taylor series about x=5 for a certain function f converges to f(x) for all x in the interval of convergence. The nth derivative of f at x=5 is given by f^(n) (5)= (-1)^n(n!)/((2^n)(n+2)), and f(5)=1/2. Write third degree Taylor polynomial for f about x=5. Then find the ...
*March 17, 2007*

**earth science**

Info on the largest earthquakes http://earthquake.usgs.gov/regional/world/historical.php
*March 13, 2007*

**Watershed?**

the watershed comes from your booty it flows out of your mouth to your ass
*November 1, 2006*

**word unscramble**

lrecilac ecprepiont
*September 28, 2006*

**Lattice method/math**

329 times 4????????????????
*September 19, 2006*

**math**

Solve for b2: A=1/2h(b1+b2)
*August 15, 2006*

**Math help!**

I dont understand this. Solve -5x - 6 = -6x^2 Rearrange to 6x^2-5x-6=0 (3x + 2)(2x - 3)= 0 Set each factor equal to zero and solve for x. I hope this helps.
*June 25, 2006*

**Math help 2**

And this one is troubling me. 3x^0 - 2(x - 3^0) - |-11 - 2| = 4x(2-5^0) - 7x please help. Thanks I don't know if you are aware of this, but anything to the "zero power" = 1 and the vertical lines indicate absolute value (regardless of sign). So this translates to...
*June 22, 2006*

**Math Help**

How is this problem done? it's not coming out right for me. solve for c: x = p(1/a + m/c) cax=pc+ ma c(ax-p)=ma then divide by ax-p check my thinking.
*June 22, 2006*

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