Saturday

July 23, 2016
Total # Posts: 42,025

**math**

the radius i 7, so its circumference is 14π. Now just divide the length rolled by the circumference.
*June 14, 2016*

**Calculus- PLEASE HELP**

xy = 1334, so y = 1334/x 3(x-6)(y-6) = 2760 3(x-6)(1334/x - 6) = 2760 solve that and you get x = 29 or 46 so, the original sheet was 29 by 46 in. v(x) = (24012+4110x-18x^2)/x = 6(x-6)(667-3x)/x for v>0, we have 6 < x < 667/3 Makes sense, since we can't cut two 3&...
*June 14, 2016*

**Math , new Oxford public school.**

1/6 y = 3 - 1/7 x so, 1/3 y = 6 - 2/7 x Now use that in the other equation: 1/2 x - (6 - 2/7 x) = 5 11/14 x = 11 x = 14 or, you can use elimination. since 1/3 = 2/6, 2/7 x + 1/3 y = 6 1/2 x - 1/3 y = 5 Now add the two equations to get rid of the y: 11/14 x = 11 so, x = 14 Now ...
*June 14, 2016*

**Maths**

If there were p to start with, p(1-0.20-0.05)(1-0.45) = 33 p = 80 check: 20% of 80 is 16 gone 5% of 80 is 4 dead so, that leaves 60 45% of 60 is 27 sold That leaves 33
*June 13, 2016*

**Math**

depends on what the amount was at the start. But, 2^10 = 1024
*June 13, 2016*

**Math**

the rolling area of the cylinder is 84*120π cm^2 = 3.17 m^2 now just divide.
*June 13, 2016*

**Math**

7km/25min * 60min/hr = 420/25 km/hr = 16.8 km/hr If he says the speed is 28km/hr, he's working on some other problem. if there are various speeds, the average speed is the total distance divided by the total time.
*June 13, 2016*

**math**

just multiply 150 by the number of minutes in an hour or day.
*June 13, 2016*

**Algebra**

-11√112 = -11√(16*7) = -11√16√7 = -11*4√7 = -44√7
*June 13, 2016*

**Algebra**

if all you want to do is expand the factors, then recall that (x^m)^n = x^(mn) so, that gives you (4ah^2)^3(ah)^5 = 4^3 a^3 h^6 a^5 h^5 = 64 a^8 h^11
*June 13, 2016*

**math - eh?**

it would be nice if you asked a question, instead of just posting gibberish. At first I thought you wanted to solve two simultaneous equations: 1/2 (2x+3y )+12/7 (3x -2y )=1/2 7/(2x +3y )+4/(3x -2y )=2 but that became unwieldy fast. Are you trying to clear fractions? 1/2 (2x+...
*June 13, 2016*

**algebra**

recall that the line through (h,k) with slope m is y-k = m(x-h) Now just plug in your values.
*June 13, 2016*

**Algebra**

assuming direct variation, y = kx so, k = 2/3
*June 13, 2016*

**Math**

If C is the circumference of the earth, in inches, then that would be 6.7*10^9 * 12 / C So, look up C.
*June 13, 2016*

**math**

That would be correct.
*June 13, 2016*

**math**

ok, the next step is (x-6)(x+1) = 0 x = 6 or -1 Now just find y for each of those x values.
*June 13, 2016*

**math**

equate y and you have x^2-6x+7 = -x+13 x^2-5x-6 = 0 and I think you can take it from there, yeah?
*June 13, 2016*

**Math**

N = kA/P That mean that NP/A = k, a constant So, you want to find N such that 50N/65 = 50*12/50 where we have expressed A and N in thousands
*June 13, 2016*

**math**

p(1+18(r/12)) = 10450 p(1+2r) = 10600 (1 + 3r/2)/(1+2r) = 10450/10600 r = 0.03 now use that in either equation to find p.
*June 13, 2016*

**Calc**

using l'Hospital's Rule, the limit is the same as that of 2√x / √(1+2x) --> 0
*June 13, 2016*

**rout**

maybe they're separate problems. In that case, just use the normal formula v = π/4 d^2 h and use your numbers
*June 13, 2016*

**Science**

I assume you mean the number doubles every 20 minutes. In that case, after n periods of 20 minutes, there will be 100*2^n bacteria. So, how many times have they doubled in 2 hours?
*June 13, 2016*

**Mathematics**

just look at the information given: 7s+3h = 50 3s+2h = 24 now you take over...
*June 13, 2016*

**math**

sure looks like C to me did you try dividing dollars by months for some rows? They are all the same.
*June 12, 2016*

**Math**

recall your basic equation of motion: y = 300 + 500t - 4.9t^2
*June 12, 2016*

**math**

the values are correct. As the number of iterations grows, so does the f value, either positive or negative. And that's 2^x 2x means 2 times x: 2,4,6,8,...
*June 12, 2016*

**math**

irrational, real
*June 12, 2016*

**math**

it is integer, rational, real as to why, you'd better review the categories.
*June 12, 2016*

**Calculus**

since pi/x < pi/2 for this limit, tanθ will be positive so the limit is +∞
*June 12, 2016*

**Math**

well, where does sinx = cosx? Divide by cosx, and you have tanx = 1 Look familiar?
*June 12, 2016*

**math**

No way to tell. At most 36 runners, though.
*June 12, 2016*

**math**

not quite. You have to watch the units. 10 seconds is 1/360 hours.
*June 12, 2016*

**math**

well, how far does the hare go? distance = speed * time
*June 12, 2016*

**math**

probably the latter, as the previous post used half-angle formula. So, eku, I guess that gives a clue to this one, too, eh?
*June 12, 2016*

**maths**

x+y+z = 26 y = 3x You want minimal x^2+y^2+z^2, so check out a few possibilities: x y z ∑*^2 1 3 22 488 2 6 18 332 3 9 14 208 ... I think you can figure it out.
*June 12, 2016*

**math**

use your half-angle formula: tan(A/2) = (1-cosA)/sinA you can easily find cosA, and then just plug and chug.
*June 12, 2016*

**Maths**

Draw the unit circle. Draw a right triangle in standard position (right angle on the x-axis). Now label the sides. The hypotenuse is 1 The height is x Let angle A be at (0,0) So, sin(A) = x/1 = x That is, A = sin^-1(x) csc(A) = 1/sin(A) = 1/x So, A = csc^-1(1/x)
*June 12, 2016*

**math**

so, what's the problem? Get out your protractor and ruler.
*June 12, 2016*

**math**

upstream time is m/(r-s) downstream time is m/(r+s)
*June 12, 2016*

**Math**

something is messed up. I suspect a typo. In particular, I think 4.6 cakes will take a lot more than 3/5 lb of flour, unless they are very small cakes. Hmmm. 2/3 lb is about 3/5 cup. I know I can't make 4 cakes with that much flour!
*June 12, 2016*

**Math**

suppose you know how much you need to make 3 cakes. To make one cake, you just divide by 3, right? So here, just divide by 4 3/5. (2/3)/(4 3/5) = (2/3)/(23/5) = 2/3 * 5/23 = 10/69 All fractions work the same way.
*June 12, 2016*

**Algebra**

Usually people don't talk about "prime factors" of polynomials, but a complete factorization should do the job. Here are a few: a. 2a^2 - 2b^2 = 2(a^2-b^2) = 2(a-b)(a+b) b. 6x^2 - 6y^2 = 6(x^2-y^2) = 2*3(x-y)(x+y) c. 4x^2 - 4 = 4(x^2-1) = 2*2(x-1)(x+1) d. ax^2 - ...
*June 12, 2016*

**Physics**

so, did you draw the path? where did you end up? Hint: label the start (0,0) Distance covered is just the sum of all the line segments. Final displacement is found using the normal distance formula, which is just the Pythagorean Theorem.
*June 12, 2016*

**Trigonometry**

nothing to do but convert to x-y form, add them up, and then convert back. Luckily, they can be treated as complex numbers, making the job easier, using polar form. And, you can let wolframalpha.com do all the work (or any other handy calculator you know). You can check your ...
*June 11, 2016*

**Mathematics**

Nope. The A+B+C=180 Note that the sides AC = b AB = c Use the law of cosines to get a^2 = b^2+c^2-2bc cosA Now, having a, you can use the law of sines to get A: sinA/a = sinC/c
*June 11, 2016*

**Math - Year 10 - Simult. equations**

you know that 4y = -3x, so use that in 16x^2 + 16y^2 = 400 16x^2 + (4y)^2 = 400 16x^2 + 9x^2 = 400 and I think you can take it from there, right?
*June 11, 2016*

**pre-algebra**

Interesting. As a position relative to the surface, the value is -550. But, as you say, the depth is indeed 550 ft. "Depth" carries with it an implied negative value. I'd check to see just how they want you to interpret positive and negative quantities.
*June 11, 2016*

**Math**

best bet is to convert all to decimals. The it will be easy. SO, 2/3 = 0.6666 0.2 = 0.2000 and so on
*June 11, 2016*

**Algebra**

(a+b)(a+b) Now just expand that us usual
*June 11, 2016*

**maths**

if two polynomials have the same roots, one is a multiple of the other. So, x^2+px+q = 2(x^2-(5/2)x-(3/2)) so, p = -5/2 and q = -3/2
*June 11, 2016*

**maths**

If the roots are p and q, then we have pq = k Since p = 1/q, pq = 1 So, k=1 x^2-5x+1 has roots (5±√21)/2 I leave it to you to verify that the two values are reciprocals.
*June 11, 2016*

**Logarithm**

Your observation appears correct; the right side is 1/√(27^2) (3^x)^3 = 3^(3*x) = 3^(3x) 9 = 3^2, so 9*3^(3x) = 3^2 * 3^(3x) = 3^(3x+2) Now, on the right, for any value n, √(n^2) = n, so we have 1/27 = 3^-2 So, we want x such that 3^(3x+2) = 3^-2 3x+2 = -2 3x = -4 ...
*June 11, 2016*

**Maths**

Actually, the number is 58.
*June 11, 2016*

**Algebra**

reciprocals of equals are equal. Unless the equals are zero...
*June 11, 2016*

**Calculus**

as usual, for a given perimeter (sum), a square has maximum area (product).
*June 10, 2016*

**math**

(50*60 + 25*56 + 25x)/(50+25+25) = 58 now solve for x
*June 10, 2016*

**math (significant digits)**

you only have one s.d. .03 + 0.2 = .23 which becomes 0.2
*June 10, 2016*

**math**

that looks better.
*June 10, 2016*

**math**

since they are of equal weight, their average is just the arithmetic average of the two scores: 87 Why do I suspect that the problem was misstated?
*June 10, 2016*

**Math**

ar^2 = 4 So, you want to know a^5 r^10 = (ar^2)^5 = 4^5 = 1024
*June 10, 2016*

**Math**

a 1-cm thick layer of water has a volume of π*35^2 cm^3 = 3.848 L So, you want to know how long it takes to drain 20cm = 76.97L 76.97L ÷ 10L/hr ≈ 7.7 hr
*June 10, 2016*

**maths**

what does a circular pool is 300 mean?
*June 10, 2016*

**maths**

If 1/3 were bad, then 2/3 were good. So, he made (5 1/4)*(3/4)(712)(2/3) =
*June 10, 2016*

**math**

Just do the division. The remainder is (m-3)y + (n+3) To be divisible, the remainder must be zero, so that means m=3 and n = -3. Check: y^4 + 3y^3 + 2y^2 - 3y - 3 = (y^2-1)(y^2+3y+3)
*June 10, 2016*

**Algebra**

You must group terms with like exponents. For example, #20 3x^2 – [7x- (4x – x^2) + 3] = 3x^2 - [7x-4x+x^2+3] = 3x^2 - [x^2+3x+3] = 3x^2-x^2-3x-3 = 2x^2-3x-3 You can see this at this url: http://www.wolframalpha.com/input/?i=3x^2+%E2%80%93+[7x-+%284x+%E2%80%93+x^2%29...
*June 10, 2016*

**Physical Science**

That would depend on the applied force. F = ma You can take it from there.
*June 10, 2016*

**O98 algebra**

The sum of her first 5 scores is 382 6*77 = 462 6*85 = 510 So the last score must satisfy 462 < 382+x < 510 80 < x < 128 So, any score above 80 will get her a C grade.
*June 10, 2016*

**Math: Inverse Function (Plz help)**

f = 8+√(8+x) to find f^-1, swap variables and solve for f: x = 8+√(8+f) x-8 = √(8+f) x^2-16x+64 = 8+f f = x^2-16x+56
*June 9, 2016*

**analytical math**

no idea. How old is Mary now?
*June 9, 2016*

**Math**

42
*June 9, 2016*

**Math**

.20 * 20 = 4
*June 9, 2016*

**Pre-Cal: Domain (cont.)**

#8 the domain is all real numbers except 0 and -7 While the domain of [5(x+7)]/[7x] excludes only 0, (f/g)(x) requires evaluating both f and g, and since g(-7) is not defined, neither is (f/g)(-7)
*June 9, 2016*

**Math**

just keep adding 11
*June 9, 2016*

**Algebra**

or, since you are given a point and a slope, try using the point-slope form of the line: y-11 = (7/3)(x-3) That's good enough for me. What you want depends on what you mean by "the equation" of a line.
*June 9, 2016*

**math**

the surface consists of three pairs of rectangular faces. You have the length and width of each face, so find the three areas, add 'em up, and double that (since there are two of each size)
*June 9, 2016*

**algebra 2B**

I suspect a typo g(x) =− 2 −x 2+ 4 is the same as -2 - x^2 + 4 = 2-x^2 Clean it up and show how far you got.
*June 9, 2016*

**algebra**

y = (2x-3)/(7x+1) see http://www.wolframalpha.com/input/?i=%282x-3%29%2F%287x%2B1%29
*June 9, 2016*

**Math**

if you want the height, drop the altitude to the base. It divides the base into two parts, x and 12-x. Now, using the Pythagorean Theorem, you can find the height h using x^2 + h^2 = 8^2 (12-x)^2 + h^2 = 7^2 subtract and you get rid of h, leaving x^2 - (12-x)^2 = 64-49 24x - ...
*June 9, 2016*

**Physics- Help!!**

120 * (1200/100) = ?
*June 9, 2016*

**math**

do you see what a useless response that is? Restrict how? Anyway, I gave you the information you need. How about showing some effort of your own here?
*June 9, 2016*

**math**

infinitely many. Or did you want to restrict the available area? In the first quadrant, (4,4) is on the curve. There will be none to the left of (1,16) or to the right of (16,1). And don't count the lattice points on the curve...
*June 9, 2016*

**Pre-Cal: Domain**

the domains include all real numbers except where the denominator is zero. So, figure the resultant function, and then exclude any places where the denominator is zero. AND, exclude 0 and -7 because at those values f or g is undefined, so even though some mixture of them might...
*June 9, 2016*

**Calculus**

you are correct. 1/(x-1) -> ∞ I tried to pound a round peg into a square hole.
*June 9, 2016*

**Calculus**

note that if u = 1/(x-1) then what you have is sin(u)/u You have probably seen that this limit is 1, so follow the same argument. Or, try google. A good discussion is at math.ucsb.edu/~jcs/SqueezeTheorem.pdf
*June 9, 2016*

**Math/Dosage Calculations**

just add up the amounts (in fl oz): (1/3)(8) + (1/2)(16) + 3 = 41/3 fl oz. Now just convert that to mL. 1 oz = 29.57 mL Hmmm. I get 404 mL
*June 9, 2016*

**Math**

Just take each sentence and place the required digit in for one of the x's. Start with xxxx My hundreds digit is the last odd number. x9xx and move right along.
*June 9, 2016*

**Math**

w*2w = 1250 Now get w, then the length is 2w
*June 9, 2016*

**Math**

that would be the area of the inner cylinder, plus the area of the outer cylinder, plus the area of the two rings at the end. So, if R = outer radius r = inner radius h = length of pipe the total area is 2πrh + 2πRh + π(R^2-r^2) = 2πh(r+R) + π(R+r)(R-r...
*June 9, 2016*

**Math - Year 10 - Simult. Equations**

just plug in y=3x and you get x^2 + (3x)^2 = 10 Now x is easy, and then y=3x.
*June 9, 2016*

**geography**

how many time zones in between? That's the number of hours. Or, if you know the longitudes, since there are 24 hours in a 360° circle, each hour covers about 15°
*June 9, 2016*

**geometry**

since j is in the middle, mn = mj+jn = 6 3/4 + 6 3/4 = ?
*June 9, 2016*

**trigonometry**

If that fails, try cot (x-y)/2 and use your half-angle formula, and more parentheses next time.
*June 8, 2016*

**math**

sure, if so designated
*June 8, 2016*

**Math**

even without calculus, you can do these. Just think of what you know about lines and parabolas. Then you can verify your Algebra I with calculus. What do you think?
*June 8, 2016*

**math(bearing)**

There seems to be a lot of noise here If the bearing of Y from Z is 280, then the bearing of Z from Y is 280-180 = 100
*June 8, 2016*

**Pre-Cal (Help Plz)**

come on. x^2-4 is negative on the interval (-2,2) So, since |x^2-4| is always positive, that little arc below the x-axis is flipped up above it. Everywhere else, the two functions are identical. g(x) = -f(x) if |x| < 2 g(x) = f(x) if |x| >= 2
*June 8, 2016*

**Pre-Cal (Help Plz)**

take a look at the graphs and see what you can say. And why not use || for absolute value? It's not like you don't have the characters... http://www.wolframalpha.com/input/?i=plot+y%3Dx^2-4,+y%3D|x^2-4|
*June 8, 2016*

**math**

ok
*June 8, 2016*

**Trigonometry**

off course as measured how? Actual distance between target and position, or distance perpendicular to the intended course? In the first case, use the law of cosines. Both sides of the included angle are 152*2
*June 8, 2016*

**Trigonometry**

draw the diagram. It should be clear that if the height is h, h cot32° - h cot40° = 12
*June 8, 2016*