Sunday

May 24, 2015

May 24, 2015

Total # Posts: 31,355

**algebra**

since time = distance/speed, 325/(59+x) = 265/(59-x)
*April 23, 2015*

**Math 7th Grade**

#1 ok #2 Nope. Check your signs carefully. #3 Nope. Plot a point and fold the paper along the x-axis. Where does the point go?
*April 23, 2015*

**Analytic Geometry**

Since all three medians meet there, finding where two intersect is enough. AB has midpoint P at (5,0) BC has midpoint Q at (6,5) The lines CP and AQ are y-6 = (0-6)/(5-2) (x-2) y+4 = (5+4)/(6-4) (x-4) Now just find where the two lines intersect.
*April 23, 2015*

**Geometry**

conguent refers to two objects length describes properties of the objects two polygons are congruent if all their sides and angles have equal measure. Saying two objects are congruent is a short way of saying that all their properties are the same. Saves a lot of time.
*April 23, 2015*

**algebra**

Man, that's over three years ago!
*April 23, 2015*

**algebra**

well, just plug in the values! g(9) = |9-1| = 8 f(g(9)) = f(8) = √(8+1) = 3
*April 23, 2015*

**College algebra**

The fonts mangled your symbols, but if I manage to get it right, we have i = √-1 (i+1)(6i-10) = 6i^2 + 6i - 10i - 10 = -6+6i-10i-10 = -16-4i
*April 23, 2015*

**College Algebra**

just solve -0.01x^2 + 0.27x + 8.60 = 9.7 -0.01x^2 + 0.27x - 1.1 = 0 -0.01(x^2-27x+110) = 0 -0.01(x-5)(x-22) = 0
*April 23, 2015*

**College math**

depending on the precision of the numbers involved, your result might more correctly be written as 8.300
*April 23, 2015*

**History**

Viisit: http://www.myassignmenthelp.net/history-assignment-help.php You will get your all answers
*April 23, 2015*

**precalculus**

well, what are the discriminants? That is easy, and we can go from there.
*April 22, 2015*

**Calc 2 Indefinite Integrals**

Hmmm. dx/(x√(x^3-1)) as you suggest, let x^3 = 1/z^2 x = z^(-2/3) dx = -2/3 z^(-5/3) dz 1/x = z^(2/3) √(x^3-1) = √(1/z^2 - 1) = √(1-z^2)/z so now you have an integrand of -2/3 z^(-5/3) dz z^(2/3) z ------------------------------- √(1-z^2) = -2/3 ...
*April 22, 2015*

**Calculus Indefinite Intergral**

#1 makes no sense #2 dx/(1-x^2)^(3/2) If you let x = 1/z dx = -1/z^2 dz 1-x^2 = 1 - 1/z^2 = (z^2-1)/z^2 Now you have -dz/z^2 z^3/(z^2-1)^(3/2) = -z dz/(z^2-1)^(3/2) and the integral is simply 1/√(z^2-1) = x/√(1-x^2)
*April 22, 2015*

**precalculus**

The general form is r = k/(1 ± e cosθ) or r = k/(1 ± e sinθ) so, you need to massage what you have into that form 2/(3+2sinθ) = (2/3)/(1 + 2/3 sinθ) so, e = 2/3 do the others in like wise.
*April 22, 2015*

**math**

If we started with a in A and b in B, then we are told: a-25 = b+25 (a+100)/(b-100) = 7/2 a = 250
*April 22, 2015*

**Algebra**

it's easier to see what you have if you let u = x+5 Then you have 5u^2+2u-7=0 (5u+7)(u-1) = 0 so, u = -7/5 or u=1 That means x+5 = -7/5 x = -32/5 x+5 = 1 x = -4
*April 22, 2015*

**Algebra Help**

(x^2-9)(x^2+5) = 0 (x-3)(x+3)(x^2+5) = 0 . . .
*April 22, 2015*

**Art please help me :)**

visit: http://www.myassignmenthelp.net/arts-assignment-help.php
*April 22, 2015*

**Algebra**

(x^2-9)(x^2+5) = 0 (x-3)(x+3)(x^2+5) = 0 . . .
*April 22, 2015*

**Algebra**

16x - 8√x = 35 16x - 8√x - 35 = 0 (4√x + 5)(4√x - 7) = 0 . . .
*April 22, 2015*

**Math**

x^2 = 4.5^2 + 6^2 - 2(4.5)(6)cos148° x = 10.1 km
*April 22, 2015*

**Science**

you will get lots of help using google.
*April 22, 2015*

**Math**

Nope. How does y change when x increases by 1?
*April 22, 2015*

**Math**

yes, but b is the divisor For it to divide the big number above (the dividend), there must also be a 5 there.
*April 22, 2015*

**Trig**

From the graph, I get about θ=1.3
*April 22, 2015*

**computer programs**

int x[6] = (9,17,20,19,20,23); int y[6] = (46,70,58,66,86,64); int i; sumx=0; for (i=0;i<6;i++) sumx+=x[i]; ...
*April 22, 2015*

**Algebra**

P(x) = .4x-10 so, P(x)=350 when x=900 Looks like D is the likely answer
*April 22, 2015*

**Algebra**

f(x) x:-3, y:3 g(x) x:5/2, y:-5 so, which is farthest from (0,0)?
*April 22, 2015*

**Geometry**

20x=140 x=7 so, the sides are 56,35,14,35 The bases are 56 and 14, so the area is (56+14)/2 * 20 The problem is, that if the sides are 35, the height is not 20. Fix that to get the true area.
*April 22, 2015*

**Trigonometry**

h/60 = sinθ, so h = 60 sinθ 60 sin20 <= h <= 60 sin36 now just plug and chug
*April 22, 2015*

**math**

do we know PQ? and 100m is not much distance between towns.
*April 22, 2015*

**Math**

depends on the dimensions
*April 22, 2015*

**Math**

-1/((-3+1)/(2-(-2)) = 2
*April 22, 2015*

**Math**

m = -2
*April 22, 2015*

**math**

If there were a adults, there were (440-a) children. So, the money collected. 42a + 18(440-a) = 12264
*April 22, 2015*

**Math**

given the various dimensions, I'd say it holds more water because it is bigger. Of course, that is always true :-) ...
*April 22, 2015*

**Math**

I think you are leaving something out. I assume they all have the same height. The area of a polygon increases with the number of sides, if the perimeter is constant. A square has more area than a triangle, and has the most area of any rectangle. A circle has the maximum area ...
*April 22, 2015*

**Math**

true only if 2P(A) = P(U)
*April 22, 2015*

**math**

clearly, it must be zero
*April 22, 2015*

**geometry**

no. it says that all squares are quadrilaterals That is, if a figure is a square, then it is a quadrilateral. after all, "quadrilateral" means four-sided...
*April 22, 2015*

**ipc**

if the rock is completely submerged, then its volume is 28.9-13.7 mL That's how much more stuff is in the cylinder after the rock is covered up.
*April 22, 2015*

**Math**

Good answer. By definition, √p is positive. In fact 1 is an extraneous solution.
*April 22, 2015*

**Math**

Not sure what you mean by saying that its elevation was 8850m "in 1998-2000" since it is always changing. From 1954 to "1998-2000" it rose 2 meters, or 200 cm. Not sure why the average lift rate is given, since we were given the final measurement. Question ...
*April 22, 2015*

**Analytic Geometry**

easy with vectors, but they are not usually a tool used in analytic geometry. slope of AB is -3/7 slope of CD is -3/7, so AB||CD slope of BC is 7/3 slope of AD is 7/3, so BC||AD since slopes are negative reciprocals, the pairs of sides are perpendicular So, ABCD is a rectangle.
*April 22, 2015*

**Analytic Geometry**

P = (x,2x) (x+3)^2 + (2x-1)^2 = (x-8)^2 + (2x+2)^2 ...
*April 22, 2015*

**algebra**

you know it is a factor if the remainder is zero.
*April 22, 2015*

**math**

this describes a line. what else do you need to know?
*April 22, 2015*

**math**

a + (a+24) = 164
*April 22, 2015*

**scale math**

since the scale is constant, (1/4)/1 = x/44
*April 22, 2015*

**Calculus**

-12 sinx/cos^2x = -12 secx tanx so, the integral is -12 secx + c -12 sec(0)+c = 4, so c=16
*April 22, 2015*

**integral calculus**

Try writing the fraction like this (3-x^7)/√(7+x^2) dx or something. I can't parse your text. I just know that √dx is meaningless, so your fraction is garbled. Use "/" for fractions, as formatting in the browser is problematic at best.
*April 22, 2015*

**math**

1/(2n) + 1/(2n+2) = 5/12
*April 22, 2015*

**Math**

.82/2.7 * 4.99
*April 22, 2015*

**Math**

#1 800*600*2250 ----------------- = 640,000 25*11.25*6 1s = 1/3600 hr = 0.0002777777... 4*162 = 648, so .04*.0162 = 648/(100*10000) = .000648 .2 = .04^0.5, so .2^3 = .008 = .04^1.5 1/.008 = 125 = .04^-1.5 11^2 = 121, so 10^3 = 1000
*April 22, 2015*

**Math**

visit: www.myassignmenthelp.net For any Kind of Assignment Help or Homework Help.
*April 22, 2015*

**math**

1395(1+.043*7) = ?
*April 22, 2015*

**math**

s^5+s^4+s^3+3s^2+2s = s(s+1)^2(s^2-s+2) I don't see any common factors with (s^2+3) so, what do you mean when you ask G(s) is: ?
*April 22, 2015*

**Algebra IMPORTANT**

Clearly, 10k+2 is 2(5k+1) so, 5k+1 = 2(2k) k = -1 The sequence is -2 -4 -8 ...
*April 21, 2015*

**please answer my question (math)**

You want n/12 = 3/4 since n/12 is the price of one flyboy, and a $3 spinner is the same as 4 flyboys (1/3 dozen)
*April 21, 2015*

**Calc**

h(t) = 625 + 20t - 16t^2 so, what is h(2)?
*April 21, 2015*

**Algebra**

so, did you graph it?
*April 21, 2015*

**accounting 100**

you're obviously embezzling!
*April 21, 2015*

**math**

345 = 3*5*23, so no perfect squares So, what methods of solution have you been given? The value will have to be an approximation, so use some numerical method or graphical method to get the value. interpolation, Newton's method, bisection, or something else.
*April 21, 2015*

**math**

a^3-b^3 - (a+b) (a-b)(a^2+ab+b^2) - (a+b) I suspect a typo. Had it been a^3-b^3 - a + b That would have been (a-b)(a^2+ab+b^2)-(a-b) (a-b)(a^2+ab+b^2-1) a^2-b^2+10a-2b+24 a^2+10a+25 - (b^2-2b+1) (a+5)^2 - (b-1)^2 (a+5+b-1)(a+5-b+1) (a+b+4)(a-b+6)
*April 21, 2015*

**functions**

slope: (600-100)/(2000-1960) = 12.5 Since 1960 is x=0, y = 12.5x
*April 21, 2015*

**Maths**

domain is clearly [0,200] m = 12n-120 so, the range is [-120,2280]
*April 21, 2015*

**maths, functions**

just solve D(p) = S(p) 1100-200p = 100p-100
*April 21, 2015*

**math**

2(8+13)=42
*April 21, 2015*

**math**

clearly d=6, since a6 = a4+12 = a4+2d so, since a4=a+3d=a+18=37, a=19 a1=a=19 a7=a+6d=19+6*6=44
*April 21, 2015*

**Chemistry**

.18/.27 = 2/3 Looks like Mg3O2, but that doesn't exist. So, what is happening?
*April 21, 2015*

**geometry**

1) in a 30-60-90 triangle, the sides are in the proportion 1:√3:2 2) h^2+10^2 = 20^2 3) a^2+4^2 = b^2 unless you know one of the other angles, there are lots of a and b which will work.
*April 20, 2015*

**Calc 1**

let u = 1/x then you have tan(3u)/u as u->0 we know that tan(u)/u -> 0, so tan(3u)/u -> 3
*April 20, 2015*

**calculus**

at height h, tanθ = h/50 sec^2θ dθ/dt = 1/50 so, plug in your numbers and evaluate dθ/dt
*April 20, 2015*

**Programing Logic and design**

days = ("Sunday",...,"Saturday") total=0 for i=1..7 display days[i] read amt[i] total += amt[i] end for for i=1..7 display days[i],amt[i] end for display "TOTAL:",total
*April 20, 2015*

**Math**

if the sides are x,y,z, then the package (surface area) is 2xy + 2xz + 2yz So, the new dimensions will be x=3, y+3, z+3 plug in your numbers to find the area
*April 20, 2015*

**math**

Hmmm. Your question is ill worded. I suspect you mean g(x) is the integral of e^(3t^2)-3t dt from 4 to x. Otherwise, we'd need the integral of e^(3t^2) which is not elementary. So, with that in mind, dg/dx = e^(3x^2)-3x
*April 20, 2015*

**derivatives**

Assuming you meant 5√ and not 5th root, y = (12x-18x^4+3)/(5√(6x^2-11x^4+2)) Using the quotient rule, y' = (12-72x^3)(5√(6x^2-11x^4+2)) - (12x-x^4+3)(5 / 2√(6x^2-11x^4+2))(12x-44x^3) ------------------------------------------- 25(6x^2-11x^4+2) You ...
*April 20, 2015*

**science 8th (:: 1 question**

you are correct.
*April 20, 2015*

**science 8th (::**

R=E/I You did E-I
*April 20, 2015*

**maths**

after t minutes, the temperature T will be T(t) = 300 - 15(t/2)
*April 20, 2015*

**maths**

each cycle advances the drunk 2 meters So, after 4 cycles and 4(5+3)=32 seconds, the drunk has advanced 8 meters. The next 5 steps take him to the end, so it takes 32+5 = 37 seconds.
*April 20, 2015*

**math**

T4 = 3T1 T7 = 2T3 + 1 Now just plug in the values for Tn and you have a+3d = 3a a+6d = 2(a+2d)+1 Now just solve for a and d.
*April 20, 2015*

**math**

if x is at 2%, then the rest (23500-x) is at 7%. So, add up the interest: .02x + .07(23500-x) = 795
*April 20, 2015*

**Math**

#1. Draw the number line -9 is to the left of -4, so -9 < -4 #2 C? Excuse me? You say that -2 = -4? Again, use the number line. #3 Nope again. You want C though I suspect that is an accident. The logic is: |2-5| = |-3| = 3 so, -|2-5| = -3 -3 = 8-11
*April 20, 2015*

**math**

You are correct on all three. A and B could be true with various numbers, but C is only true if p or q is zero.
*April 20, 2015*

**Trig**

as usual draw a diagram. If the height is x, then from distance x, x/h = cotθ so, h cot 48° - h cot 68° = 1
*April 20, 2015*

**Math**

60% = 3/5, so (3/5)(3/5)x = 36 x = 36(5/3)(5/3) = 100 for the boys, we have the average as 16*50.25 + 8*45.15 ----------------------- = 48.55 16+8
*April 20, 2015*

**Business Stats**

well, what value z corresponds to P(Z>z) = .84?
*April 20, 2015*

**chemistry**

depends on the temperature and pressure, no? But at STP, 1 mole fills 22.4 L, so ...
*April 20, 2015*

**Calc 1**

how about I do this one, and you at least try on the others? x^2+3x-18 = (x+6)(x-3) So, everywhere except at x=3, f(x) = x+6 That means we expect the limit to be 3+6=9 Using the suggestion, the limit is (2x+3)/1 = 2*6+3 = 9
*April 20, 2015*

**Math**

Hmmm. xy=50 2(x+y) = 34 The only factor pairs of 50 are 1,50 2,25 5,10 None of those add up to 17, so the sides will not be integers. To find them, you will need to solve a quadratic equation: x+y=17 x + 50/x = 17 x^2-17x+50 = 0 Now just use the quadratic formula.
*April 20, 2015*

**Math**

clearly it is not a square. 192 has several factors: 4x48 6x32 8x24 12x16 ... so, which of those factor pairs adds up to half of 64?
*April 20, 2015*

**Math**

D is indeed correct.
*April 20, 2015*

**Math**

nope. C is what you get if there's a flat fee of 2.19 and each gallon costs 1 more.
*April 20, 2015*

**algebra (urgent help needed)**

see the related questions below.
*April 20, 2015*

**Math**

looks good to me
*April 20, 2015*

**Calculus check and help**

so far, I don't see any of your work, just the answers others have provided. For B, if you have to split the area into two equal parts, and the integration goes from 0 to 1.136, that means that there is some z in that interval which bounds exactly half the area. So, you ...
*April 19, 2015*

**Calculus**

well, 1-sin^2 = cos^2, so you really just have sin/cos^2 = sec tan which I'm sure you recognize.
*April 19, 2015*

**Calculus**

the graphs intersect at (0,1) and (1.136,1.764) A The cross-sections have base of f(x)-g(x) and height 5. So, we add them all up: v = ∫[0,1.136] 5(1+sin(2x)-e^(x/2)) dx = 5(x - 1/2 cos(2x) - 2e^(x/2)) [0,1.136] = 2.1455 B The same thing, but the height is the same as the...
*April 19, 2015*

**Chem**

If the reaction is Pb(NO3)2 + 2NaCl = PbCl2 + 2NaNO3 then each mole of PbCl2 uses one mole of Pb(NO3)2. So, with 3.264/278.11 = 0.0117 moles of PbCl2 produced, the 2.00mL was .0117/.002 = 5.868M 5.868*80.7/100 = 4.735M original concentration
*April 19, 2015*