Wednesday

July 27, 2016
Total # Posts: 42,116

**weber state university**

when an action is to be completed in the future. For example, By noon I will have eaten six doughnuts. By the time you read this post, you will have already figured it out. The FP tense is formed by will + have + past_participle Never mind the distinction between "will&...
*July 9, 2016*

**geometry**

most likely a rectangle, if the cuts are made parallel to the sides
*July 9, 2016*

**Trigonometry**

No spherical trig here. The balloon problem might have qualified, but it says "level ground." (a) tanθ = 5/4 (b) review your tangent function. If the balloon travels a distance d, then d = 110 tan31°50' - 110 tan19°20'
*July 9, 2016*

**Maths**

did this yesterday: http://www.jiskha.com/display.cgi?id=1467998179
*July 9, 2016*

**Math**

The line segment touches bot the x- and y-axes at all times. So, the point p is 3 units away from the x-axis, along the line. So, let the line make an angle θ with the x-axis (measured clockwise). Then picture point P as being at the end of a rod of length 7, which slides...
*July 9, 2016*

**math**

20-6-5 = 9 P(yellow) = 9/20
*July 9, 2016*

**math**

well, 5^2 = 25
*July 9, 2016*

**discrete math**

(g◦f) = g(f) = f^2-2 = (2x+1)^2-2 (f◦g) = f(g) = 2g+1 = 2(x^2-2)+1 x=4f/(2f-1) 2xf-x = 4f f(2x-4) = x f = x/(2x-4) So, the range of f is all reals except x=2. The domain is all reals except 2 and 1/2. The domain of f^-1 is the range of f. The range is all reals ...
*July 9, 2016*

**number magic(math)**

The length plus the width = 6 so, how many pairs of integers add up to 6? If you are not restricted to integer values, then there is no limit to how many you can draw.
*July 9, 2016*

**math**

usually quantities are not negative values, right?
*July 9, 2016*

**algebra**

Add: x-2y+3z = 7 -x+y-2z = -4 --------------- -y+z = 3 Add #2 and 4*#3: 4x+5y+z = -1 -4x+4y-8z = -16 ------------------- 9y-7z = -17 Now you know that z = y+3,so 9y-7(y+3) = -17 9y-7y-21 = -17 2y = 4 y = 2 so, z = 5, x = -4
*July 9, 2016*

**Maths**

same as always: clear the fractions to get nr = (r+20)(n-10) nr = (r-4)(n+10) nr = nr + 20n - 10r - 200 nr = nr - 4n + 10r - 40 20n-10r = 200 4n-10r = -40 or, 2n-r = 20 2n-5r = -20 So, r = 2n-20 2n-5(2n-20) = -20 2n-10n+100 = -20 -8n = -120 n = 15 so, r = 10 15 students share ...
*July 8, 2016*

**Maths**

If each of n students gets r rupees, nr/(n-10) = r+20 nr/(n+10) = r-4 Now just solve for r and n.
*July 8, 2016*

**Math**

there is no average cost. The cost of the items does not change. 3s+8c = 29 8s+3c = 15 11s+11c = 44 Multiply by 2/11 and you have 2s+2c = 8
*July 8, 2016*

**Chemistry**

convert each to moles. Write the balanced equation. The reagent with the smaller moles used will limit the reaction. So, figure the moles produced, and convert back to grams.
*July 8, 2016*

**Math**

well, x is 4, so just substitute 4 for x and evaluate, to get y. y = 2*4+3
*July 8, 2016*

**Maths**

3/2 (2a + 2d) = 48 (a)(a+2d) = 252 a = 16-d, so (16-d)(16-d + 2d) = 252 Now just solve for d
*July 8, 2016*

**Algebra**

h+2s = 5.40 3h+s = 8.70 Now just solve for h and s.
*July 8, 2016*

**Science**

You need 0.1 moles for 1L of diluted acid. The concentrated acid has 1.15 moles per liter. So, you need 0.1/1.15 = 0.087 liters of the concentrate. or, 87 ml
*July 8, 2016*

**English**

how can one letter indicate an order?
*July 8, 2016*

**Science**

h/(500*15) = 1/2 Review the properties of a 30-60-90 right triangle.
*July 8, 2016*

**discrete math**

Get out your atlas and look them up. (c) Miri is located in Sabah false, since both are cities in Malaysia
*July 8, 2016*

**math**

You have y^2 = 4x This is just the standard equation y^2 = 4px with p=1. Check your book or online for properties of parabolas. You can start here if you wish: http://www.wolframalpha.com/input/?i=parabola+y%5E2+%3D+4x
*July 8, 2016*

**Math**

use the distributive property 8a+2a = (8+2)a = 10a just as 8 books + 2 books = 10 books $8 + $2 = $10 and so on.
*July 8, 2016*

**Physics**

distance is just 5+8 Use the distance formula (Pythagorean Theorem) to figure the displacement.
*July 8, 2016*

**Maths**

done http://www.jiskha.com/display.cgi?id=1467924046 You might check your previous posts before wasting everyone's time posting it all over again...
*July 8, 2016*

**Chemistry**

well, how many moles of CH4 is 16g? clearly, 4 times that many atoms of H. But, hydrogen comes as H2, not just H, so divide that by 2.
*July 8, 2016*

**math**

apparently you have a 5-digit number xxxxx my tens digit is 7 xxx7x My hundreds digit is 4 less than my tens digit xx34x Now just work your way from there, using the facts given.
*July 8, 2016*

**physics**

since R varies as L/A, changing L to 2L requires that we also change A to 2A, since L/A = 2L/2A
*July 8, 2016*

**math**

84/(4*60) = 84/240 you can reduce that if you want
*July 8, 2016*

**math**

R = {(2,3),(2,9),(3,2),(3,4),(4,3),(4,9),(9,2),(9,4)}
*July 8, 2016*

**chem**

google is your friend. Type in your question and you can read many explanations of why this is so.
*July 8, 2016*

**VECTOR HELP URGENT**

|a × b| = |a| * |b| * sinθ just plug in your numbers!
*July 7, 2016*

**PreCalculus 1**

(a) since Coco can be anywhere on the line y=3, you want the closest that the spider can get to that line. Since sin(t) has a minimum value of -1, y(t) has a minimum of 4.5, so Coco can never get closer than 1.5 ft to the spider. (b) The spider's distance is z^2 = x^2+y^2...
*July 7, 2016*

**precalc**

(fog) = f(g) = 2g^2-5 = 2(x+4)^2-5 now just expand that out Now just plug in x=3 for (b).
*July 7, 2016*

**precalc**

this is very like the others. By this time you should have some idea how to do them. If you get stuck, some back with your work.
*July 7, 2016*

**precalc**

yes, it is.
*July 7, 2016*

**Math**

v(t) = v - 9.8t v(0.35) = 0, so initial v = 3.43 Her height y = 10 + 3.43t - 4.9t^2 So, solve for t when y=0
*July 7, 2016*

**physics**

the horizontal force is 58 cos27° F = ma so, plug in your numbers and solve for a.
*July 7, 2016*

**Algebra**

since distance = speed * time if x is the boat's speed and y is the water's speed, we have 4(x+y) = 48 6(x-y) = 48 Hint: 48 = 4*12 = 6*8
*July 7, 2016*

**Algebra**

count the tickets: g+s = 215 count the dollars: 10g+6s = 1990 Now crank it out.
*July 7, 2016*

**Geometry**

rewrite as y = 2x-3 and you can read off the slope and intercept
*July 7, 2016*

**Pre-Cal**

oops sinx = 8/17 so, cosx = 15/17 sin2x = 2 sinx cosx = 2 * 8/17 * 15/17 = 240/289
*July 7, 2016*

**Pre-Cal**

sinx = 8/17 so, cosx = 15/7 sin2x = 2 sinx cosx = 2 * 8/7 * 15/7 = 240/49 do the others similarly.
*July 7, 2016*

**Algebra**

Huh? It's already written out. That's how I got the equation. Can you not solve the equation? If you find x, that's how many lbs of worms you need. The rest (30-x) is bears.
*July 7, 2016*

**Algebra**

If x lbs of worms, then 7x + 3(30-x) = 4.60*30 This is just like the interest problem, which is also a mixture problem.
*July 7, 2016*

**Pre-Cal**

recall that tan(x-y) = (tanx-tany)/(1 + tanx tany)
*July 7, 2016*

**Algebra**

If $x is at 8%, then .08x + .09(10000-x) = 860
*July 7, 2016*

**Physics - tense**

I'm waiting for the answer here... Talk about tension!
*July 7, 2016*

**Maths**

Yeah, I noticed that. I can't figure why the closest answer is so far off. To get 12.2 years, r needs to be 9.58%
*July 7, 2016*

**geometry**

review your basic trig functions, and from a distance of x feet, 1149/x = tan 89° Now just solve for x.
*July 7, 2016*

**Calculus**

recall that the range of an object is R = v^2/g sin2θ so, figure some pairs of value that make that 100 miles. Of course, that formula implies a flat earth, and 100 miles is far enough away that varying gravity and earth's curvature require some modifications.
*July 7, 2016*

**Maths**

For n sides, there are n-2 straight angles, or 2(n-2) right angles. So, n=17
*July 7, 2016*

**MATH Function Transformation**

If you mean a polynomial such as a(x-p)(x-q)(x-r)... then a is the vertical scale value, so a = 1/2 means the y values are half as big: a compression ratio. stretching and compression are just two ways of looking at a scale factor. Usually a compression means a < 1 and a ...
*July 7, 2016*

**Math**

75 min = 1.25 hours, so 15.4mi/1.25hr = 12.32 mi/hr
*July 7, 2016*

**math**

that is one way. The other way is to use the Remainder Theorem and evaluate f(1). That is the remainder R.
*July 7, 2016*

**Math Please Help**

you just want d(t) > -16 t^3-9t^2+6t > -16 t^3-9t^2+6t + 16 > 0 (t+1)(t-2)(t-8) > 0 Now, using what you know about the general shape of cubics, you know that this one will come up from the lower left, then cross the t-axis at -1,2,8. Since it started out negative, ...
*July 7, 2016*

**math**

review your basic trig functions: h/450 = tan 20°
*July 7, 2016*

**algebra2**

If there are x cows and y chickens, you know (counting heads) x+y = 35 Now, counting legs, you know: ??? Work that out, then solve the two equations.
*July 7, 2016*

**AB Calculus**

Assuming all logs are base b (since the base does not matter for this kind of stuff), we have (I think) log ∜(x^7 y^2 / z^4) = 1/4 log(x^7 y^2 / z^4) = 1/4 (7logx + 2logy - 4logz) = 7/4 logx + 1/2 logy - logz or, (b)
*July 7, 2016*

**math**

Since y has an absolute maximum, it must be of even degree, since all the odd-degree polynomials go forever in each direction. And, its leading coefficient must be negative, since the graph opens downward.
*July 7, 2016*

**Maths**

Since multiplying logs is not one of the usual operations, and none of the answers includes (x-6) I'd say you are in trouble from the start. I suspect that you were given -2logb^x -6logb^y + 1/7 logb^z That is choice (a), assuming the usual sloppiness with notation.
*July 7, 2016*

**math**

A little synthetic division shows that the remainders are -9m-92 and 23-4m If they are equal, then m=-23 P(-3) = P(2) = 115
*July 7, 2016*

**Advanced Function**

the volume increases by the cube of the linear scale. So, he needs a scale factor of no more than ∛9 = 2.08
*July 7, 2016*

**geometry**

well, you know that m∠ABE is half of the total, since BE bisects ∠ABD.
*July 7, 2016*

**Maths**

What's to figure out? They gave you the exact formula you need. 9% growth means it grows by a factor of 1.09 each year, so t = ln3/ln1.09 = ?
*July 7, 2016*

**General Mathematics**

8 + 1.5*ceil(x) for x km above 4. where ceil(x) (ceiling function) is the least integer greater than or equal to x.
*July 7, 2016*

**Algebra**

110*55 = ?
*July 7, 2016*

**Science**

30√2 SW is the same as 30S and 30W So, now add up all your distances and see where you end up. The answer will be surprisingly easy.
*July 7, 2016*

**geometry**

(B+b)/2 * h fill in the values
*July 7, 2016*

**math**

Not always. Never for rectangles.
*July 7, 2016*

**AHOOGAAH! Homework Dump**

No ideas on any of these?
*July 7, 2016*

**Math**

(3 + (2/3)(-3-3),(2 + (2/3)(5-2)) = (3-4,2+2) = (-1,4)
*July 7, 2016*

**Math**

well the slope of the line between (-2, -1) and (6, 8) is (-1-8)/(-2-6) = 9/8 now use the point-slope form of the line
*July 7, 2016*

**Calculus**

Let u = tan(π/4 sin(2x)) du = sec^2(π/4 sin(2x))*(π/4)(2cos(2x)) du So, what you have is just ∫du with some constant factored out.
*July 7, 2016*

**General Math**

since pure juice is 100% juice, add up the amounts of juice: .50(6) + 1.00(x) = .75(6+x)
*July 7, 2016*

**physics PS**

Oops -- v = 2/3 t^3 i + 2/3 t^2 j
*July 7, 2016*

**kashinath palod**

FF = ma = 6t^2i + 4tj Since m=3, a = 2t^2i + 4/3 t j so, v = 2/3 t^2 i + 2/3 t^2 j
*July 7, 2016*

**Calculus**

well, sin^2(x) = 1/2 (1-cos(2x)) that should be easy to integrate, right?
*July 7, 2016*

**maths**

I have never heard of the word kharch, but the apple's share is 5/(6+10+5) = 5/21
*July 7, 2016*

**math**

well, ADB is also an isosceles right triangle with sides of 5. So, its hypotenuse is AB = 5√2 that help?
*July 7, 2016*

**Math**

Well, the 1st term in the rth group is 1,2,4,7,11,... = 1+ 0,1,3,6,10 = 1+ r(r-1)/2 That should get you started.
*July 7, 2016*

**Math**

looks good
*July 7, 2016*

**pre cal**

6(x^2 - 2/3 x + 1/9) = 6(x - 1/3)^2
*July 7, 2016*

**Pre-Cal**

(csc θ − sin θ)/(cos θ) = (1/sinθ - sinθ)/cosθ = (1-sin^2θ)/(sinθ cosθ) = cos^2θ/(sinθ cosθ) = cosθ/sinθ = cotθ
*July 6, 2016*

**Pre-Cal**

(sin^2 + cos^2)/cos = 1/cos
*July 6, 2016*

**java program**

letter = (n>=90) ? "A" : (n>=80) ? "B" : (n>=70) ? "C" : (n>=60) ? "D" : "E";
*July 6, 2016*

**Algebra**

check the slopes. If their product is -1, the lines are perpendicular. That is, if one slope is the negative reciprocal of the other.
*July 6, 2016*

**Math**

Thunk of it using actual numbers. If he can mow the lawn in 4 hours, how much in 2 hours? 2/4 So, it will take him 2/x hours. If it takes him x hours, he does 1/x of the job in 1 hour. So, twice that, or 2/x in 2 hours.
*July 6, 2016*

**math**

ever hear of actual math symbols? 3√5 - 2√7 + √245 - √28 3√5 - 2√7 + √(49*5) - √(4*7) 3√5 - 2√7 + 7√5 - 2√7 10√5 - 4√7
*July 6, 2016*

**MATH HELP**

In 30 minutes, the first bus has gone 39 miles The 2nd bus goes 15 mi/hr faster. So, how long does it take to cover the extra 30 miles? It's the same as if the 1st bus stopped 30 miles away, and the 2nd bus drove 15mph to meet it.
*July 6, 2016*

**Chemistry**

sure looks like D to me twice the value, opposite direction
*July 6, 2016*

**math**

what, you cannot add 600+3200 ?
*July 6, 2016*

**Normal Distribution**

you can play around with Z table stuff at http://davidmlane.com/hyperstat/z_table.html
*July 6, 2016*

**math**

not sure what the scaling has to do with anything, as the scaled polygon is never mentioned. However, it should be easy to convince yourself that such a scaling does not change any of the slopes or angles involved.
*July 6, 2016*

**Math**

yes, it can. Because to be even f(-x) = f(x) This is true only (and always) if all the exponents are even.
*July 6, 2016*

**Math**

the highest exponent is the degree the order of a root is the number of times it appears. So, you have three roots of degree 1. Any polynomial of degree n has exactly n roots, though all may not be unique (order 1).
*July 6, 2016*

**algebra 2-1**

x=42
*July 6, 2016*

**Pre Calculus**

again, only one possible choice, since e^1 = 2.718 e^2 = 7.389 e^3 > 16
*July 6, 2016*