see the fine article in wikipedia on trajectory and range. But, who wants to shoot a cannon? Much more effective to shoot a ball.
just pick any value for y, and evaluate x=1-y^2 y x -3 -8 -2 -3 -1 0 0 1 1 0 2 -3 3 -8 If you can figure the domain and range, that's good work. Not sure where youir problem is. The "this" has many possible antecedents.
math that comes before calculus, usually 2nd year algebra and trigonometry. Geometry comes into play as well.
Math - Trig
Looks like you need to review the basic trig functions and draw useful diagrams. #1 h/15 = tan 46.48° #2 h/17.2 = tan 73.5°
math(check answers please)
all correct good work
evaluate the expression inside the || and then throw away any negative sign. |-2-2| = |-4| = 4 |3+5-10| = |-2| = 2 if f(x) = |x-2| then f(-2) = |-2-2| = 4 f(10) = |10-2| = 8 f(-5) = |-5-2| = |-7| = 7
when multiplying, add exponents. when dividing, subtract exponents. x^5 * x^7 = x^12 x^-3 / x^-5 = x^(-3-(-5)) = x^(-3+5) = x^2 just take it a step at a time. Negative numbers are just like positive numbers. They add and subtract in the usual way. Just remember that 1/x^n = x^...
x-2 || are just like (). Evaluate what's inside first.
no. Even with no stops, it'd take 7 hours.
at t=0, let the 1st boat be at (0,0) The 2nd boat is at (-c,c) So, at time t, the 1st boat is at (0,6t) and the 2nd boat is at (-c+5t,c) The distance is thus d^2 = (-c+5t)^2 + (c-6t)^2 = c^2 - 10ct + 25t^2 + c^2 - 12ct + 36t^2 = 2c^2 - 22ct + 51t^2 2d dd/dt = -22c + 102t dd/dt...