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Posts by steve

Total # Posts: 50,439

Math
?(16^2-4^2) = ?(256-16) = ?240 = 15.49 So, it is 15.5

Math
200 is not a perfect square! It is 2*10^2 7. READ THE QUESTION: How tall is the utility pole, to the nearest tenth? Not an integer! What calculation did you do?

Math
1. ok 2. if the number terminates as shown, then it is rational 3. 250 is not a perfect square. It is 10*5^2 5. ok 7. nope. 16 is not even the closest integer.

Math 10
9?2 = ?(81*2) 2?6 = ?(4*6) 8?3 = ?(64*3) 4?5 = ?(16*5) 6?2 = ?(36*2) I'll let you finish off.

math
I am shocked to see your first try. v(t) is a function. it is v of t, not v times t!

SCIENCE
KE gained = PE lost

maths
f(x) = (1+3x^2)^(1/3) / x f'(x) = ((1/3)(1+3x^2)^(-2/3) * 6x)(x) - (1+3x^2)^(1/3)(1) ---------------------------------------------------- x^2 -(x^2+1) ------------------------- x^2 (1+3x^2)^(2/3)

Math geometry
1) the base angles are equal, so (50-x)^6 = (30x-12)^6 50-x = 30x-12 ... Find x, evaluate the angles, and subtract them from 180 2) I assume you mean lengths. If they are b and B, 8(b+B)/2 = 52 3)The medians of a triangle meet 2/3 of the way from a vertex to the opposite side...

physics
horizontal distance or vertical distance? You need to provide a bit more context. For a nice discussion of any trajectory, see https://en.wikipedia.org/wiki/Trajectory

math
1:5 = 2:10

Math
h = 1/f h' = -1/f^2 f'

Math
the slope of the line is 1. So, you want the slope of the tangent to be 1. f'(x) = 6x^2-24x+19 = 1 x = 1,3 check: f(1) = 9 f(3) = 3 So the tangent lines are y-9 = x-1, or y=x+8 y-3 = x-3, or y=x the graphs are at http://www.wolframalpha.com/input/?i=plot+y%3D2x%5E3%E2%88%...

Calc
dy = (2x-7) dx so, ?x ? (2x-7) ?x

Maths, triangle trigonometry
draw a diagram. If the two lighthouses are at S and N, and the ship moved from A to B, then let the east-west distance moved by the ship be x. x = 5cos20° SN = x tan50° - x tan10°

Maths, triangle trigonometry
It's handy to think of P,R and Q as complex numbers, with P=(0,0). Find Q-R and then convert to polar form.

Physics
the horizontal speed is constant: 20 cos39° The vertical position is (20 sin39°)t - 4.9t^2 so, figure how long it takes to go 55m, then use that to get the relative height at that time.

Physics
If the height is h, then the vertical position y at time t is y = h - (9.4 sin21°)t - 4.9t^2 y(6) = 0, so you can find h. the horizontal speed is constant: 9.4 cos21° Now you can answer the questions.

math
First off, your distance is wrong. You must have used some bogus formula. d^2 = (5+3)^2 + (2+4)^2 = 100 d = 10 Since that is the distance from the center to a point on the circle, it is the radius. ...

math NEED HELP ASAP
add up the juice amounts: .65x + .90(150-x) = .75(150) ...

math
add up the vinegar in each part: .06x + .11(250-x) = .09(250) ...

Math
the coefficient of x^5 is negative. So, for x large negative, f(x) is large positive for x large positive, f(x) is large negative The lower powers don't matter for end behavior.

math
make a table for t=1 to 5. The annual cost is 1: 300-5 = 295 2: 300-10 = 290 3: 300-15 = 285 4: 300-20 = 280 5: 300-25 = 275 just add them up. Hmm. Maybe you just use t=5 for all 5 years. In that case, the annual cost is 275, so the total would be 5*275 = $1375 How did you ...

Math
recall that cos^2 x = (1+cos2x)/2 so, cos^4 x = (1+cos2x)^2/4 now cos^2 2x = (1+cos4x)/2 and so on. In the end, you get sin^8(x) = 1/128 (cos8x - 8cos6x + 28 cos4x - 56cos2x + 35)

Pam
x^2 is never less than zero, so f(x) is never less than -3. The vertex is at (0,-3) In general, f(x) = ax^2+bx+c has its vertex at x = -b/2a f(x) = a(x-h)^2 + k has its vertex at (h,k). In this case, h=0 and k = -3, so the vertex is at (0,-3)

Pam
The 3 is tiny, but the curve does not approach the line y=x. It gets arbitrarily close to the line y=x+3.

Pam
While the asymptote is a sloping line, and it looks like it ought to be x+11, it is not. (x^2+11x+16)/(x+8) = x+3 - 8/(x+8) So, the asymptote is actually the line y=x+3

Pre-algebra
If the cut is x inches, then the length and width are reduced by 2x, and the height is x. So the volume is v = x(40-2x)(20-2x) = 4x^3-120x^2+800x I can't believe that finding the maximum value of such a function is a topic for pre-algebra! It requires either analysis of a ...

math
?r^2h = 2800, so h = 2800/(?r^2) So, the cost function is c = 2*3?r^2 + 4*2?rh = 6?r^2 + 22400/r now just find r when dc/dr=0 and use that.

@Ms algebra
No "|" key on your keyboard, Ms?

Algebra
well, start with time = distance/speed

math
L(L-2) = 20

math
clearly, r = 2/5 now just use your formula.

Maths
If you meant to solve 18m^2-8m = 0 just factor out 2m: 2m(9m^2-4) = 0 2m(3m-2)(3m+2) = 0 your steps make no sense; you have discarded factors, changed signs, etc. Pay attention to what you're doing!

maths
find the angle between the headings (not bearings!) use the law of cosines for the third side.

Maths
sorry, that's n(n+1)/2 So, you have (n+1)(n+2)/2

Maths
I expect the differences are 3,4,5,6,7,... Did you know that 1+2+3+...+n = n(n-1)/2 ?

MATH NEEDS HELP NOWw
Did you take a look at the terms? 1, 1, 0, 0, ...

maths
consecutive angles add to 180. Looks to me like the two acute angles are 70° each.

physics
h(t) = 5t - 4.9t^2 max height at t=5/9.8 so, figure h at that value of t. Total distance is that height up, then back down.

maths
If you have a protractor, this should be easy.

calculus
arctan x = x - x^3/3 + x^5/5 - ... so, x-arctan(x) = x^3/3 - x^5/5 + x^7/7 - ... divide by x^3 and you get 1/3 - x^2/5 + x^5/7 - ... as x->0, that -> 1/3

calculus
surely you recognize the sequence 1, 3, 6, 10, ... as n(n+1)/2 it is the sequence of partial sums of 1+2+3+4+...

Calculus
a = xy da/dt = y dx/dt + x dy/dt d^2 = x^2+y^2 Now just plug in your numbers (I used x and y instead of w and l, since the l looks like a 1)

Calculus
xy = 12 y dx/dt + x dy/dt = 0 Now just plug in your numbers and solve for dy/dt

Algebra 2
Since the domain of ?x is x>=0, you will need (x-3) >= 0. That is, x >= 3. So, plug in some values of x and plot the points for y=-?(x-3): x y 3 0 4 -1 7 -2 12 -3 ... It will look like the bottom half of a horizontal parabola with vertex at (3,0). The equation could ...

Algebra
well, 7.5 is 3/4 * 10, so ...

College Algebra
if x at 5% then the rest (10000-x) is at 6%. So, add up the interest: .05x + .06(10000-x) = 550

math
24 = 8^(log_8(24)) 24^x = 8^(x log_8(24)) = (8^x)^(log_8(24)) = 12^(log_8(24)) = 12^1.52832 = 44.6

Algebra 2
geez, what's with all the words? f(x) = x^2 + 3x + 6 g(x) = (x-3)/2 g(1) = (1-3)/2 = -1 f(-1) = (-1)^2+3(-1)+6 = 1-3+6 = 4 or, f(g(x)) = g^2+3g+6 = ((x-3)/2)^2 + 3(x-3)/2 + 6 = (x^2+15)/4 f(g(-1)) = ((-1)^2+15)/4 = 16/4 = 4

math
well, is f(1)=19? yes. So, f-1(19) = 1

math
sorry - not much specific information here.

Math
A: If the red line has slope m1, then your line is y-5 = m1(x-3) B: If the blue line has slope m2 then your line is y = (-1/m2)(x+4) So, use the needed slopes, and massage the equations into the form y = mx+b

math
drop an altitude to KM. Note that you now have two 5-12-13 right triangles. ...

Maths
just use your GP sum formula. You have a/(1-r) = 243 a (1-r^5)/(1-r) = 242 Now divide and you have 1-r^5 = 242/243 = 1 - 1/243 . . .

math
the student walked on a heading, not a bearing. use the law of cosines. The distance d is found via d^2 = 50^2 + 200^2 - 2*50*200*cos115°

math
you should have remembered the 5-12-13 right triangle. The altitude is 12. So, the area is 5*12 = 60

High School Geometry
If SU?TP, SU=8 (think 3-4-5 triangle) Since the area is 1/2 bh using any side as a base, the other two altitudes can be found via 8*12 = 10h

High School Geometry
AC=BC = ?(3+9) = ?12 so, the perimeter is 6+2?12 or 6+4?3

Math
(68+72)/2 = 70 Or, since 70 is the average, 72 = 70+2 68 = 70-2

maths
well, 2b-3a = -(3a-2b) so you have 4(x+y)(3a-2b)-(6x+y)(3a-2b) ...

math
so, where does the slope begin, and does it drop lower when moving away from the tower, or what?

Math
The numbers in your LaTeX don't seem to agree with the "regular" section, so I'll ignore them. You want A with rows (a b) and (c d) such that 6a-b = 13 6c-d = -26 a+4b = 23 c+4d = 4 I get rows (3 5) and (-4 2) Check: http://www.wolframalpha.com/input/?i=%7B%...

math
g = b+25 b+g = 101

MaTHS
think of tan(A-B)

Algebra 2
I agree. I assume you did some math to get that idea...

Maths
L1: y = 2x+1 L2: y = (bx+5)/7 assuming that b/7 > 2, we have, using tan(A-B) = (tanA-tanB)/(1+tanAtanB) we want to find b such that (b/7 - 2)/(1+(b/7)(2)) = 1 b = -21, and we have L2: -3x + 5/7 or any parallel line with slope -3. check: arctan(-3) = 108.43° arctan(2) = ...

Math
hello ?? kitty

MATHS
well, one way is (x-h)^2 + (y-k)^2 = r^2 now plug in your values and solve for (h,k)

math 4th grade
to find the average, add up the total points and divide by the number of students: (6*100 + 4*90 + 3*80 + (26-6-4-3)*80)/26 = 86.15 I suspect a typo, since a score of 80 appears twice in the description. If so, just fix it in the expression above, and recalculate.

Algebra
x^4 = 1 = 1 cis 2? x = 1 cis 2?/4 = 1cis ?/2 Now add multiples of 2?/4 to that till you get all 4 roots. You can verify, knowing that 1^4 = (-1)^4 = i^4 = (-i)^4 = 1 Do the others in like wise.

Calculus
k is an odd name for a variable, but your answer is correct. Way to watch the integration limits.

Math
f(x) = 8-4x A f(2) = 8-4(-2) B 8-4x = 8 C Now you have two points. Draw the line connecting them D all real numbers. Think about it. Pick any x you want, and y is defined. A line goes out forever in both directions. E,F now use the graph. If it's you who has posted this ...

Math
#1. |z-1|=|z+3| |z-i|=|z+3| are both straight lines. This can be seen since |z-(a+bi)|=|z-(c+di)| |(x+yi)-(a+bi)|=|(x+yi)-(c+di)| |(x-a)+(y-b)i|=|(x-c)+(y-d)i| (x-a)^2 + (y-b)^2 = (x-c)^2 + (y-d)^2 x^2-2ax+a^2+y^2-2by+b^2 = x^2-2cx+c^2+y^2-2dy+d^2 (2c-2a)x + (2d-2b)y = c^2+d^2...

Calculus II
nope. consider {an} = 1/n The harmonic series diverges.

Science
well, you surely know that the moon is a choice. If only one choice is allowed, that must be it. If you really aren't sure about the others, you need to do some reading. google is your friend.

math
well, 2^-2 = 1/4, so -3x = -2

Mathematics
uh, which square?

Math- Outcomes and Probability
the question is the same as asking how many ways can 5 of 6 items be arranged. You will recall that that is 6P5 = 720

math
.10+.66+.08+.035 = .875 or 7/8 so, they have 1/8 left. 1/8 * 300000 = ?

Math
for angle x, the complement is 90-x: comp(x) = 90-x for angle x, the supplement is 180-x: supp(x) = 180-x So, supp(comp(x)) = supp(90-x) = 180-(90-x) = 90+x

Math Word Problem
Yes its 297 Thank you Reiny, I had a hard time understanding that one.

Math Word Problem
199 is also wrong :/

Math Word Problem
I am trying to find the exact number of male employees, thats where I am having troubles at. Like I tried, x = the number of employees x - 603 = the number of males x = 603 - x 2x = 603 x = 301.5 and it show that its wrong

Math Word Problem
67% or 603 employees in a company are female. How many are male?

Mat8
(2000*1500*1000)/(10*5*5) = 12,000,000

Math
A. f(-2) = 8-4(-2) B. 8-4x = 9 You have two points now. plot them and draw the line between them A line goes forever in both directions, both horizontally and vertically, so ... now look up the points for E and F

maths(rational numbers)
1/3 + 1/4 + 3/8 = 23/24 so, 9 hectares is 1/24 of the total...

engineering mathematics
8t + 1/2 t^2 = 18 t = 2 ?v = a * t

engineering mathematics
(300-200) = 500a

engineering mathematics
F = ma plug in your numbers

Pre Calculus 30
#1 what about zero? 9*10*10*5 #2 ok #3 as in #1, 1*10^4 #4 1000..9999 = ? #5 6P3 #6 4! * 3! #7 6 (assuming a win means matching a picture to the chosen name)

cal
There are several ways to do this. I'd google the topic. You might start here: http://whistleralley.com/torus/torus.htm

K
Using discs (washers) of thickness dx, v = ?[0,2] ?(R^2-r^2) dx where R=6-y and r=3 v = ?[0,2] ?((6-3e^(-x))^2-3^2) dx = 9?(5e^4+8e^2-1)/(2e^4) using washers of thickness dy, v = ?[3/e^2,3] 2?rh dy where r=6-y and h=2-x v = ?[3/e^2,3] 2?(6-y)(2+ln(y/3)) dy = 9?(5e^4+8e^2-1)/(...

Algebra
first, check the discriminant. If it's negative, there are no real factors. If the discriminant is a perfect square, then there are rational factors, so you can then work on finding them. 2x^2-5x+2 discriminant is 25-16=9, so we can work to find (2x-1)(x-2) the others ...

Trigonometry
you are correct so far. Of course, you have not provided any choices for selection, but the equation you need is tan? = 200/80 ? = tan-1 2.5 ? 68°

Math
#1: 20 + 4x = 140 #2: GCD(24,64,56) = 8 #3: I suspect you meant that there is a remainder of 4 when it is divided by 5. If sol, just list the numbers with these two properties: 2,5,8,11,14,17,... 4,9,14,19,... 14 = 4*3+2 = 2*5+4 #4. There are only 4 such numbers: 105,150,501,510

Math
there are 3 pairs of faces, each a rectangle. So, the area is 2(3.5*1.5 + 3.5*2 + 1.5*2) Of course, that does not include any overlap for taping things shut...

Math
the domain of all polynomials is all real numbers. f(x) = 8-4x. So, for f(-2), replace every x with -1: f(-2) = 8-4(-2) = 8+8 = 16 To graph the function, you just need two points. You already have (-2,16). So, pick any other value for x (0 is an easy one!) and plot (0,f(0)). ...

Math ; Algebra
-2x-6=-12 add 6 to both sides: -2x = -6 divide by -2: x = 3 or, -2x-6=-12 add 2x to both sides: -6 = -12+2x add 12: 6 = 2x divide by 2: 3 = x or, -2x-6=-12 divide by 2: -x-3 = -6 ... Follow the same logic for the other one and see what you get.

Precal
for this kind of problem, draw the right triangle. cos? = 2/3 means that the adjacent side is 2 and the hypotenuse is 3. sin? = ?5/3 means that the opposite side is ?5 and the hypotenuse is 3. But, then you knew that already, since the opposite side would be ?(3^2-2^2) = ?5 Si...

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