Wednesday

October 1, 2014

October 1, 2014

Total # Posts: 25,427

**math**

since the ratio of height-to-shadow is the same for both objects, h/29,2 = 3,5/5,2 Now just solve for h.
*July 16, 2014*

**Math**

well, that would naturally be 0.02 * 5270
*July 16, 2014*

**mathematics**

the figure is really just a sphere of radius r and a cylinder of radius r and height 4r. So, the volume is V = 4/3 π r^3 + πr^2 (4r) = 16/3 π r^3 So, dV/dt = 16πr^2 dr/dt That means that dr dt = dV/dt / (16πr^2) The surface area is A = 4πr^2 + 2&#...
*July 16, 2014*

**Math Help**

just list the digits as given, moving the decimal point 9 places to the right, adding zeroes as needed.
*July 15, 2014*

**Calculus Help**

the domain is 260 <= x <= 410 the price per chair is 88.00 - 0.02(x-260) revenue is price * quantity, so R(x) = x(88.00-.02(x-260)) = 93.2x - .02x^2 For maximum revenue, just find the vertex of the parabola. For minimum, figure the revenue at the two ends of the domain, ...
*July 15, 2014*

**Calculus Help**

revenue is price * quantity, so R(q) = 551q profit is revenue minus cost, so P(q) = 551q - (q^3-60q^2+1200q+760) You should probably graph P(q) to find the max. Take a look here: http://www.wolframalpha.com/input/?i=551q+-+%28q^3-60q^2%2B1200q%2B760%29 If you have calculus as ...
*July 15, 2014*

**Calculus Help**

profit P(q) = R(q)-C(q), so P(q) = 510q - (9400+3q^2) dP/dq = 510 - 6p P is maximized when dP/dq = 0, so ...
*July 15, 2014*

**maine s**

well, 500 is 25% of 2000, so ...
*July 15, 2014*

**trig**

Just review the definitions of the basic trig functions. Check the diagram, and you can see that the height h can be found using h/220 = sin 36°
*July 15, 2014*

**Lisa**

your answer looks correct to me. There must have been a typo in the problem, with a spurious "root" tossed in.
*July 15, 2014*

**math**

assuming that "no students of school A and B would get mixed up" means that each row contains only students from one school, let's find the largest number that divides both 336 and 432. GCF(336,432) = 48 So, school A has 7 rows of 48 and school B has 9 rows of 48
*July 15, 2014*

**drivers' ed.**

Judging from your experience, I would have to say, YES!
*July 15, 2014*

**Algebra**

since your speed is 5 km/hr, all the distances must be multiples of 5, since you start counting at the fountain. Or, if the somewhat vague description means that you want the total distance covered, starting at the fountain, then you have to start with 2, and after that, all ...
*July 15, 2014*

**physics**

how about ÿ ok
*July 15, 2014*

**physics**

i mean #&255; ok
*July 15, 2014*

**physics**

finally #&255 ok
*July 15, 2014*

**physics**

and also ẏ ok
*July 15, 2014*

**physics**

i mean ẍ ok
*July 15, 2014*

**physics**

i also get Ẍ ok
*July 15, 2014*

**physics**

i get ẋ ok
*July 15, 2014*

**math**

An equilateral triangle of side s has area √3/2 s^2 You have four triangles of side 8.
*July 15, 2014*

**math**

the slope of the line is (-4-2)/(1+2) = -2 So, use the point-slope form of the line, using either of the given points.
*July 15, 2014*

**maths**

Since time = distance/speed, 1.5/(8-s) + 1.5/(8+s) = 0.4 s = 2
*July 15, 2014*

**math (help please)**

review your "standard angles." sin π/3 = √3/2 sine is negative in QIII and QIV. That means that sin(π+π/3) = sin(2π-π/3) = -√3/2 Now you can add any multiple of 2π to those values, and you get all real numbers as required. If...
*July 14, 2014*

**math**

Recall that if A takes A hours, and B takes B hours, 1/A + 1/B = 1/2 So, if B does the task in x hours, A takes x+3 hours: 1/(x+3) + 1/x = 1/2 Now just solve for x.
*July 14, 2014*

**math**

Assuming you meant √(x-6)=√3-√x, we square both sides and get x-6 = 3-2√(3x)+x -9 = -2√(3x) 9/2 = √(3x) 81/4 = 3x x = 27/4 Check: √(3/4) = √3-√(27/4) √3/2 = √3(1-3/2) √3/2 = -√3/2 Nope. If you meant...
*July 14, 2014*

**Algebra**

decaying to 10% takes log0.10/log0.5 = 3.32 half-lives So, A's half-life is 33/3.32 = 9.94 days B's half-life is 43/3.32 = 12.95 days Looks like (a) is the answer
*July 14, 2014*

**math**

each line describes the previous line. So, the next line is 311211 BTW, the last entry in your post should have been 111221, making the real next line 312211
*July 14, 2014*

**Math**

Draw the triangle. One leg is 1, and the hypotenuse is 4. So, the other leg is √15 the cosine of the angle is √15/4
*July 14, 2014*

**Differential Equations**

(x^2+1)dx + x^2y^2dy=0 x^2y^2 dy = -(x^2+1) dx y^2 dy = -(x^2+1)/x^2 dx 1/3 y^3 = -x + 1/x + C ...
*July 14, 2014*

**Algebra**

log0.900.6 - log0.850.6 = 1.7 or, since you probably don't have a button for log0.9x, log(0.6)/log(0.9) - log(0.6)/log(0.85) or even log(0.6)(1/log(0.9)-1/log(0.85))
*July 14, 2014*

**Geometry**

I didn't see where the solid was a pyramid. Usually a prism is a right prism, so the v = (area of base)*height
*July 14, 2014*

**science**

Name it analogously with table salt, which is Sodium Chloride. That -ide suffix indicates that there are just the two elements. Ever heard of the ointment Zinc Oxide? Same deal.
*July 14, 2014*

**math**

the x-coordinate is halfway between the two end x-values: (-3 + -8)/2 = -11/2 Do the y-value the same way.
*July 14, 2014*

**math**

after n cuts, the thickness is 0.1 * 2^n mm. so, evaluate when n=30.
*July 14, 2014*

**algebra**

just solve for t when the height is zero: -16t^2 + 112t + 128 = 0 just a normal quadratic equation.
*July 14, 2014*

**Alegbra**

how many times is this going to be posted? Review the point-slope form of a line: a line with slope m, through the point (h,k) has the equation y-k = m(x-h) So, look at the equation above, and read off m and (h,k)
*July 14, 2014*

**Alegbra**

The point is clearly (-5,4) Now since the slope is 3/2, a second point is up 3 and right 2.
*July 14, 2014*

**Trigonometry**

just figure s(5)-s(1)
*July 14, 2014*

**physics**

The tank weighs the same, regardless of its contents. Figure the volume of material, and multiply that by the material's density. :-)
*July 14, 2014*

**physics**

figure the volume: .18 * .78 * .44 m^3 now multiply that by the density, in kg/m^3
*July 14, 2014*

**Pre algebra**

(5*62 + 50)/6
*July 14, 2014*

**math**

let the numbers be x-1,x,x+1 The sum is 3x = 39 so, the middle number is 13
*July 14, 2014*

**Math**

log740353607 = log40353607/log7 = 9 so, 40353607 = 7^9
*July 14, 2014*

**math**

x = 2^(1/2) since log √x = 1/2 log x, log x = -2 x = 10^-2 lnx = ln(e*(x+1)) x = e*(x+1) ...
*July 14, 2014*

**Physic**

1W = 1J/s 1 kwh = 1000 Wh = 1000J/s * 3600s/h
*July 14, 2014*

**Math**

(9+1)/(9+1+6)
*July 14, 2014*

**physics**

750 + 750 + 625
*July 14, 2014*

**Calculus 2**

actually, the integral isn't so bad if you recognize that the integrand is just x^4 + 1/x^4 http://www.wolframalpha.com/input/?i=arc+length+of+x^5%2F10%2B1%2F%286x^3%29+from+3+to+6
*July 14, 2014*

**Physics**

well, you have the mass of 1 liter. So, what is the mass of 2 liters? Now just look up the conversion factor for kg to lb. A handy site is http://www.onlineconversion.com/weight_common.htm On the home page there, you can find many other conversion calculators.
*July 14, 2014*

**mqr/117**

rewrite f(x) as 5(x + 3/10)^2 + 11/20 and then you can just read off the coordinates of the vertex.
*July 13, 2014*

**Math**

you want the set of elements common to your two sets. So, which numbers are in both lists?
*July 13, 2014*

**Math**

The number of people taking something is 23+32-9 So, that leaves how many taking nothing?
*July 13, 2014*

**Alegbra**

They are perpendicular if the product of their slopes is -1. So, is (-7)(-7) = -1 ?
*July 13, 2014*

**Math**

think of the calendar as units of 24 hours So, 5:44 am on day 10 is the same as 29:44 on day 9. So, subtract 14 from 29 and you have 15:44 of the previous day, or 3:44 pm. Or, you could just subtract 24 hours, giving you 5:44 am of the previous day. But you only wanted to ...
*July 13, 2014*

**Alegbra**

If you mean y = -3/2 (x+5) you can see easily that y=0 when x = -5. So, that's where the graph crosses the x-axis. Now, since the slope -s -3/2, just mark a second point, 3 down and 2 to the right from there. Join those two points with a line, and that's the graph.
*July 13, 2014*

**math**

I'd say that would be 17+3=20 assuming the ladder is laid vertically against the wall -- an unusual placement, to be sure.
*July 13, 2014*

**math**

the grade would be 15/5280 = 0.284%
*July 13, 2014*

**Math 221**

as with most problems involving fractions, work first with the denominators. They cannot be added or subtracted unless they all have the same denominator. 5/12 + 7/9 The GCD(12,9) = 36. So, what you have is 15/36 + 28/36 Now all the "units" are the same. Just as you ...
*July 13, 2014*

**maths - oops**

Err, I mean one leg=2. So half the chord has length √21
*July 13, 2014*

**maths**

Draw a diagram, including the radii to the ends of the chord. Draw the radius perpendicular to the chord. You now have two right triangles with one leg=1 and hypotenuse=5. Half the length of the chord is √24.
*July 13, 2014*

**Algebra II**

no, since 2x^2+x-15 = (2x-5)(x+3) Just multiply both sides by (2x-5)(x+3) The thing to watch out for is to be sure to note that 5/2 and -3 must be excluded from the domain.
*July 13, 2014*

**mat/117**

you want where P < 0 P(x) = 750x(20-x) You know that P=0 when x=0 or 20 Since the graph is a parabola opening downward, P>0 between the roots. So, P<0 if x>20
*July 13, 2014*

**mat/117**

translating upward just means add 11 to g.
*July 13, 2014*

**mat/117**

f(x) = -5(x - 3/10) + 29/20 If that doesn't tell you the answer, review your forms of quadratics.
*July 13, 2014*

**mat/117**

(fg)(x) = f(x)*g(x) = (-6x-1)(4x^2)
*July 13, 2014*

**mat/117**

(f+g)(x) = f(x) + g(x) so, just add the two polynomials together.
*July 13, 2014*

**phi 208**

life is like a simile.
*July 13, 2014*

**Math**

ok. now what?
*July 13, 2014*

**math**

Surely this treated in your text. You want A/(v-1) + B/(v+2) = 1/(v-1)(v+2) A(v+2) + B(v-1) = 1 Av + 2A + Bv - B = 1 (A+B)v + (2A-B) = 0v + 1 For those polynomials to be identical, all of the coefficients must match. So, we have A+B = 0 2A-B = 1 solve those and you get A = 1/3...
*July 12, 2014*

**math**

You use partial fractions. 1/(v+2)(v-1) = 1/3 (1/(v-1) - 1/(v+2))
*July 12, 2014*

**science**

light is reflected from both sides of the glass.
*July 12, 2014*

**algebra**

set x=0 and evaluate y. That's the y-intercept. Ax+By=C has slope -A/B because By = -Ax+C y = -A/B x + c/B In this case, A=9 and B=5
*July 12, 2014*

**math**

look at your functions. They indicate that the ball rises as time goes on, and never comes back down. h1(t) = 156 - 16t^2
*July 12, 2014*

**MATH**

IF UNIT IS 1, HOW ABOUT 9871 ?
*July 12, 2014*

**Math**

oops - I plugged in π/2 instead of π. The solution above is correct if the fan is 1/4 of a circle.
*July 12, 2014*

**Math**

The fan is a sector of a circle. That means that 198 = 1/2 (x+3)^2 θ Unless you know how much of a circle the fan occupies (that is, what is θ, compared to 2π), there's no way to solve for x. If the fan is a half-circle, θ=π, so 198 = 1/2 (x+3)^2...
*July 12, 2014*

**English**

They are all four compound sentences, so there should be a comma after "summer" #1 is probably the best. #2 implies that there is a specific group of people under discussion. #3 and #4 suffer from a mismatch between plural and singular.
*July 12, 2014*

**English**

I think #2 is better. The "still" implies that the study is continuing, rather than having been finished in the past. #1 would be ok if it said something like I studied math for ten years, but never really learned it. #1 is still ok as it is, if you are discussing ...
*July 12, 2014*

**English**

The problem appears to be math, and yes, the sentences seem to mean the same thing. Now it's time to work on your English. That would be Do the three mean the same? Or, Are the three the same?
*July 11, 2014*

**Alegbra**

the slopes are the same, so they are either parallel or the same line. If you multiply the 1st by -3, the constant term is different from 7, so the lines are parallel.
*July 11, 2014*

**Surds**

Hmmm. I get √(4x+1)+√(x+3)=2 4x+1 + 2√(4x^2+13x+3) + x+3 = 4 5x = -2√(4x^2+13x+3) 25x^2 = 4(4x^2+13x+3) 25x^2 = 16x^2 + 52x + 12 9x^2 - 52x - 12 = 0 (9x+2)(x-6) = 0 x = -2/9 , 6 But x=6 does not satisfy the original equation, so -2/9 is the only solution.
*July 11, 2014*

**Math**

.075x = 600
*July 11, 2014*

**Math**

it is the square root of 1500. That is, it is the number which, when multiplied by itself, equals 1500. √16 = 4 because 4*4 = 16 √25 = 5 because 5*5 = 25 √1500 is not a rational number, but it is approximately 38.73 38^2 = 1444 39^2 = 1521 So, you can see ...
*July 11, 2014*

**Math**

√1500 so, now what?
*July 11, 2014*

**electric circuit**

are the cells in series or in parallel?
*July 11, 2014*

**math**

13112221
*July 11, 2014*

**trigonometry**

since there's y^2 but no x^2, it's a parabola, opening to the right: 5x = 4y^2 - 3y - 7 x = 4/5 y^2 - 3/5 y - 7/5 x = 4/5 (y^2 - 3/4 y) - 7/5 x = 4/5 (y^2 - 3/4 y + (3/8)^2) - 7/5 - 4/5 * (3/8)^2 x = 4/5 (y - 3/8)^2 - 121/80 so the vertex is at (-121/80,3/8) http://www...
*July 11, 2014*

**math**

what tools do you have at your disposal? Have you learned l'Hospital's Rule yet? If so, that's what I'd use. The limit is the same as for the derivatives: (1/2 cos(x)^-1/2 - 1/3 cos(x)^-2/3)(-sinx) / (1/2 sin(x)^-1/2 * cosx) Take that sinx^-1/2 out of the ...
*July 11, 2014*

**math**

There are many proofs of this, such as the one here: http://www.wyzant.com/resources/lessons/math/calculus/derivative_proofs/sinx However, it relies on the fact that sinx/x -> 1 as x->0. That is usually proven as given here: http://math.ucsd.edu/~wgarner/math20a/sin%28x%...
*July 11, 2014*

**maths**

divide the sum into 5+6+7=18 equal parts of size x. So, 18x = 3600 x = 200 The shares are thus 5*200 = 1000 6*200 = 1200 7*200 = 1400
*July 11, 2014*

**physics**

well you know that AxB = -(BxA) So, if they are equal, they are zero. That means the angle is zero or 180. They are parallel.
*July 11, 2014*

**maths**

look at what we have: a+b+c+d = 66.5 b = a-2 c = a+1.5 d = c+1.5 Start substituting: a+(a-2)+(a+1.5)+((a+1.5)+1.5) = 66.5 a=16.0 b=14.0 c=17.5 d=19.0
*July 11, 2014*

**PHYSICS**

this just algebra I m1*x = m2*3 - m2*x (m1+m2)x = 3m2 x = 3m2/(m1+m2)
*July 11, 2014*

**PHYSICS**

think back to your Algebra I. Collect all the vf terms and factor it out.
*July 11, 2014*

**PHYSICS**

12t + 1/2 at^2 = 25 12 + at = 0 solve for a. Now you can solve for µ by using the resultant acceleration.
*July 11, 2014*

**PHYSICS**

KE = 1/2 mv^2 work is equivalent to energy.
*July 11, 2014*

**PHYSICS**

just a note: that's "mu sub-k," not "muse of k" µk Your class must be an oral presentation, if you never saw it written. Anyway, convert mgh=2.0 * 9.8 * 1.5 to KE, 1/2 * 2.0 * v^2 Using that v, and the frictional force of deceleration, figure the ...
*July 11, 2014*

**PHYSICS**

mgh + 1/2 mv^2 stays constant, so mgh1 + 1/2 m*2^2 = mg(h1-3) + 1/2 mv2^2 divide out all the m's and you have 9.8*h1 + 2 = 9.8(h1-3) + 1/2 v2^2 2 = -9.8*3 + 1/2 v2^2 v2^2 = 62.8 v2 = 7.92
*July 11, 2014*

**PHYSICS**

KE = 1/2 mv^2, so 0.02 = 1/2 * 2 * v^2 ...
*July 11, 2014*

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