Saturday

March 28, 2015

March 28, 2015

Total # Posts: 30,131

**Algebra 1**

my answer is 42 feet
*February 11, 2015*

**Algebra 1**

A ball is thrown into the air with the in initial upward velocity of 60 ft/s. It's height (h) in feet after t seconds is given by the function h=- -16t^2+60t+6. What will the height be at t=3 seconds?
*February 11, 2015*

**Algebra 1**

my answer is 3 seconds
*February 11, 2015*

**Algebra 1**

A ball is thrown into the air with the in initial upward velocity of 45 ft/s. It's height (h) in feet after t seconds is given by the function h=- -16t^2+45t+6. After about how many seconds will the ball hit the ground?
*February 11, 2015*

**Algebra**

the acceleration is (41m/s)/(.28s) = 146.43 m/s^2 F = ma
*February 11, 2015*

**math**

for the horizontal asymptote, as x gets large, only the highest powers matter. So, what is x^2/9x^2 ? For vertical asymptotes, they can only occur where the denominator is zero. 9x^2-44x-5 = (9x+1)(x-5) so, when is that zero?
*February 11, 2015*

**Icp**

F = ma
*February 11, 2015*

**math**

Seems like you'd have to know the various amounts of debt and interest, doncha think?
*February 11, 2015*

**math**

see the 1st related question below
*February 11, 2015*

**Geometry**

42° = 1/2 (large-small) so, large-small=84° but, large = 7/3 * small 7/3 * small = small+84 4/3 * small = 84 small = 63 large = 147 So, since the three arcs add up to 360°, 63+147+x = 360 x = 150° A nice discussion of the topic is found at http://www....
*February 11, 2015*

**Maths**

Hmmm. Looks like 20 to me, too. There aren't any fractional laps to worry about.
*February 11, 2015*

**Geometry**

Suppose the sides were exactly 3,10,12. The perimeter would be 25. But, the actual perimeter is 400 = 16*25 So, the sides are 16*3,16*10,16*12 = 48,160,192
*February 11, 2015*

**math**

blue beads are 3,6,9,12,15,18 green ones are 7,14 so, what do you think?
*February 11, 2015*

**math**

a = pi r^2 = 38.5 r^2 = 38.5/pi r = 3.50 c = 2pi r = 22.06 Now, for the square: s = 22.06/4 = 5.515 a = 30.42
*February 10, 2015*

**math**

(.05*540 + .80*(720-540))/720 = 23.75%
*February 10, 2015*

**9th Grade Math**

(4πx^2)/(3x^2) = 4π/3 = 4.19
*February 10, 2015*

**math**

2(q^2-3q) = 2q^2-6q So, you want to add up 2q^2-6q+q+10+q^2 Keep like powers together, and you end up with (2+1)q^2 + (=6+1)q + 10 3q^2-5q+10
*February 10, 2015*

**Math**

7/15 - 6/15 = ?
*February 10, 2015*

**Math**

you are correct
*February 10, 2015*

**geometry**

90+62+x = 180
*February 10, 2015*

**vectors**

Looks good to me.
*February 10, 2015*

**Math**

x^6 z^-1/3 / -125 y^-9 z^8/3 = x^6y^9/-125z^3 (x^6y^9/-125z^3)^-1/3 = -5z/x^2y^3
*February 10, 2015*

**messy systems**

n+q = 50 5n+25q = 1030 Now just solve for n and q.
*February 10, 2015*

**Math**

20% of 20 quarts is 4 qt. Adding 5 qt of red will make 9/25 = 36% red
*February 10, 2015*

**math**

If the boys average n points each, then just add up the total points g = 3b 18g + nb = 17(g+b) 54b + nb = 17(3b+b) 54b + nb = 68b 54+n = 68 n = 14
*February 10, 2015*

**Algebra 1**

thank you
*February 10, 2015*

**Algebra 1**

A carpenter is putting a skylight on a roof. If the roof measures 10x +89 by 7x+7 and the skylight measures x+5 by 3x+3, what is the area of the remaining roof after the skylight is built?
*February 10, 2015*

**Algebra 2**

a good long division site is http://calc101.com/webMathematica/long-divide.jsp
*February 10, 2015*

**Algebra 2**

wolframalpha.com is a good graphing site. Just type in your function or equation.
*February 10, 2015*

**calculus**

<mumble>
*February 10, 2015*

**Algebra 1**

A sports team is building a new stadium on a rectangular lot of land. If the lot measures 6x by 10 x and the sports field will be 1x by 4x, how much land will be left over>? My answer is 56x^2
*February 10, 2015*

**Algebra 1**

A garden will be on a rectangle lot 5x by 10x. The garden will be circular with a radius of 3x. How much land will be left over after the garden is built?
*February 10, 2015*

**math**

surely you know how many lb/kg and in/cm. If not, look them up to do the conversions.
*February 10, 2015*

**Math**

because the order or arrangement matters. Otherwise, it'd just be a combination.
*February 10, 2015*

**math**

s = t^3-3t^2-8t+c use s(1) = 10 to find c, then evaluate s(2)
*February 10, 2015*

**Math**

because ((x+10)*4+200)/4-x = 60 for any x
*February 10, 2015*

**Math - eh?**

no idea. You need to provide a little more context. Also a little better grammar.
*February 10, 2015*

**math**

you want arcsin(4/5) in QI and QII, where sine is positive.
*February 10, 2015*

**Math**

The only one I get is 1+2+3-4+5+6+7*8-9 = 60
*February 10, 2015*

**Math**

If there are x at 40 cents, and y at 16 cents, then you know that x = 2y 40x+16y=576
*February 10, 2015*

**Math**

k = 9/2 s s = k-28 Now just solve for k and s and figure k+s
*February 10, 2015*

**algebra**

the slope is (1/2 - 2/5)/(-4/5 - 1/3) = -3/34 So, now you can use the point-slope form to get the equation for the line as y = -3/34 (x - 1/3) + 2/5 You can massage that into the form you want. I assume you can get rid of the fractions.
*February 10, 2015*

**maths please help and explain**

Using somewhat more conventional notation, we have 4((1/2)x+2) = 2((2/3)x-3) 2x+8 = (4/3)x-6 (2/3)x = -14 x = -21 (3x-6)/(2y) = 4 3x-6 = 8y 3x-8y = 6 (2y+3)/4 = 2x 2y+3 = 8x 8x-2y = 3 Doing a little scaling, that's the same as 3x-8y = 6 32x-8y = 12 Now subtract and you ...
*February 10, 2015*

**math**

Clearly, the nth branch produced 2^(n-1) oranges.
*February 10, 2015*

**Trigonometry**

if the height matters, then you need to give some indication of the angles of elevation. Just knowing the direction tells us nothing about the buildings' locations. The N8°W and N10°E are angles measured on the ground. Apparently the 10m is a straight line on the ...
*February 10, 2015*

**Math**

the bedroom is 12*12 = 144 ft^2 the living room is 12*18 = 216 ft^2 so, the bedroom's area is 144/(144+216) of the total. The price of the carpet is irrelevant.
*February 10, 2015*

**math**

5/6 < 1 (5/6)^2 is (5/6)(5/6) < 5/6 so, what do you think?
*February 10, 2015*

**Math**

h(t) = 8t - 2.5t^2 so, just find the vertex of that parabola.
*February 10, 2015*

**Math**

clearly, x=3 and y=2
*February 10, 2015*

**Math**

I get 2x = y+2 2z = x+1 so, t=7
*February 10, 2015*

**Geometry**

well, surely you must recognize that ∠TUS ≅ ∠SUT, so that means that 4x+16 = 2(18x-8) 4x+16 = 36x-16 x = 1 So, ∠SUT = 20° ∠RUS = 10° No idea what ∠RUT is, since you haven't said anything about the relative locations of the points...
*February 10, 2015*

**Pre-Calculus**

oops. wrong vertex. Should be (0,628.0925) y = -0.007015x^2+628.0925
*February 10, 2015*

**Pre-Calculus**

you can do all the graphing stuff. Lots of online places for that. Given the definition of cosh(x), you have the arch as c(x)=693.8597-68.7672(e^0.0100333x+e^-0.0100333x)/2. The vertex of the arch is at c(0) = 693.8597-65.7672 = 828.0925 the arch meets the ground where c(x) = ...
*February 10, 2015*

**math**

If the amounts invested are x,y,z then we have x+y+z = 5000 x+y = z .02x + .03y + .04z = 145 Hmmm. I get -500 for y. Sure there's no typo in the problem?
*February 10, 2015*

**Calculus**

a = ∫[-1,1] y dx
*February 9, 2015*

**Math**

I see six dimensions. That's some room!
*February 9, 2015*

**math**

no idea what you mean when you say you have some numbers "on a prism."
*February 9, 2015*

**Vectprs and Scalars**

if a and b are vectors, a•b is a scalar. a×b is a vector. the dot product • is only defined for two vectors. The cross product × is only defined for two vectors. So, 1,3,5,11 are scalars 6,8,9,10 are vectors 2,4,7,12 are undefined
*February 9, 2015*

**math**

180° is completely straight.
*February 9, 2015*

**Algebra 2**

I have an idea. Why don't you show your work? To start, square both sides, then collect terms and square again. √(2x+1) + √(2x+6) = 5 (2x+1) + 2√(4x^2+14x+12) + (2x+6) = 25 √(4x^2+14x+12) = 9-2x . . .
*February 9, 2015*

**Algebra 2**

x^4-x = 0 x(x^3-1) = 0 x(x-1)(x^2+x+1) = 0 do the other the same way. Factor it out. Each of the factors may be zero.
*February 9, 2015*

**Algebra 2**

enter your function or equation at wolframalpha.com
*February 9, 2015*

**physics**

the range of the ball is R = (v^2 sin2θ)/g so just find v such that (v^2 sin(102°))/9.8 = 14
*February 9, 2015*

**Vb**

well, Integer is misspelled.
*February 9, 2015*

**Math**

1x4 = 4x1 commutative property of multiplication?
*February 9, 2015*

**math**

X and Y are 80° apart. Each time zone is 15° wide. So, the towns are 5 1/3 time zones apart. Depending on their proximity to the zone lines, they could be 6 or 7 hours apart. The rest I'm sure you can do with normal trig operations. If not, show how far you got, so...
*February 9, 2015*

**Math**

7/8 - 5/6 = 21/24 - 20/24 = 1/24
*February 9, 2015*

**Math**

The sum from 1 to n where n is even (2k) is (2^2-1^2) + ... + ((2k)^2-(2k-1)^2) = (2+1)(2-1) + (4+3)(4-3) + ... + (2k+2k-1)(2k-2k+1) = 3+7+...+4k-1 = k/2 (3+4k-1) = k(2k+1)
*February 9, 2015*

**maths**

we want F such that Fx = 3ye^(3x) - 2x Fy = e^(3x) Clearly F = ye^(3x)-x^2
*February 9, 2015*

**algebra**

d = 1.22√(50+5)
*February 9, 2015*

**mathematics**

d/1200 = cot 28°
*February 9, 2015*

**trig - eh?**

Hard to tell, but I am assuming that you meant to say that the taller building is 6/5 as far away as the shorter building. If so, then the shorter building is 5/6 as far away, or 20/3 m. Something tells me the heights matter, but I can't see how, from the data. The ...
*February 9, 2015*

**trig**

Draw a diagram. You will see that the distance d is given using the law of cosines: d^2 = 415^2 + 120^2 - 2*415*120*cos 100°10'
*February 9, 2015*

**maths**

since you have only provided a single value for each coordinate, and the planes are all perpendicular to an axis, the intersection must clearly be (-2,8,5).
*February 9, 2015*

**maths**

there are lots of matrix calculators online. wolframalpha shows that the calculation is http://www.wolframalpha.com/input/?i=solve+{{12%2C4%2C17%2C11}%2C{14%2C8%2C9%2C4}%2C{3%2C7%2C2%2C5}%2C{5%2C12%2C9%2C7}}*{{p}%2C{q}%2C{r}%2C{s}}+%3D+{{5}%2C{8}%2C{12}%2C{7}}
*February 9, 2015*

**math**

1,33 10,42 100,132 5003,5035 I think you need a bit more information.
*February 9, 2015*

**Math**

d/p = 3/4 p-3 = d p = 4d/3, so 4d/3 - 3 = d d/3 = 3 d = 9
*February 9, 2015*

**Math**

f:j = 3:4 j:s = 7:6 LCM(4,7) = 28, so f:j = 21:28 j:s = 28:24 f:j:s = 21:28:24 so, f:s = 21:24 = 7:8 total candy = 54 pieces. You want a box with only 9 pieces. Each box has 18 pieces now. So, just move 9 from one box to another.
*February 9, 2015*

**math**

cos(x) = √3/2 if x = 30° or 330° So, 3θ+120 = 30, 330, 390, 690, ... θ = -30, 70, 90, 190, ... So, pick the values in your domain.
*February 9, 2015*

**math**

v = 225π*1.2 1/3 πr^2 = 9
*February 9, 2015*

**Calculus**

that's correct. A simple division shows that (x^2-1)/(x^2+1) = 1 - 2/(x^2+1)
*February 9, 2015*

**algebra**

14.7 e^(-.21a) = 12.31 e^(-.21a) = 0.837 -.21a = ln 0.837 = -0.177 a = 0.845 mi = 4462 ft
*February 9, 2015*

**math**

T = a + b√s Now write two equations using the given numbers, and solve for a and b.
*February 9, 2015*

**math**

-(5/7)^(-2/5) = -1/(5/7)^(2/5) = -(7/5)^(2/5) a = 7/5 b = 2/5
*February 8, 2015*

**math**

The exposition is rather garbled, but I take it that A is x below the window The window has height h x/15 = tan 5° (x+h)/15 = tan 35° Now you can answer the questions. (I think)
*February 8, 2015*

**science**

earth's axis tilts. The hemisphere pointing toward the sun receives more light and heat, and experiences summer, while the opposite hemisphere has winter. google is your friend. just look for stiff on "seasons axis tilt" and you will find lots of discussions.
*February 8, 2015*

**Math**

just substitute the first value for y into the second equation: 2x+3 = 3x+5 Now solve for x, and y follows. Same for the other one.
*February 8, 2015*

**math**

If I were to sketch a graph, I'd need more information.
*February 8, 2015*

**Calculus**

f' = 5x^4+1 Looks like f' > 0 for all x.
*February 8, 2015*

**Calculus**

The line joining those two points has slope (65-60) / (10/60) That is the value v'(t) must achieve.
*February 8, 2015*

**Calculus**

so, did you do that, and notice the parallel lines? That means that for some c between 1 and 8, f'(x) = (8.5-5)/(8-1) So, you need to find c where -4/c^2 = 1/2 Eh? Not possible. Looks like (8,8.5) is not on the curve. Better fix you point and redo the steps.
*February 8, 2015*

**Vectors/Scalars?**

What do you get when you cross a mosquito and a mountain climber? Nothing. You cannot cross a vector and a scaler.
*February 8, 2015*

**geometry**

T2+T3 = ar+ar^2 = 3r(r+1) = 60 r=4 ...
*February 8, 2015*

**geometry**

ar^2 = 6 ar^5 = 3/32 r^3 = (3/32)/6 = 1/64 r = 1/4 So, now you can find a and Tn
*February 8, 2015*

**Algebra**

(w+4)(2w+4)-w(2w) = 196 Solve for w, and then you figure the length, 2w.
*February 8, 2015*

**algebra**

If there are x at $5 and y at $50, then we are told that x = 4y 5x+50y = 2870 So, now just solve for y.
*February 8, 2015*

**Vectors and Math**

(2x,-2,8)-(-12,3y,18)-(2,-1,1/2z)=(0,0,0) 2x+12-2 = 2x+10 = 0: x = -5 the equations for y and z work out as desired.
*February 8, 2015*

**Math**

what's all this 121, 122 junk? Guessing? If the numbers are x and y, just write down what they told you: x+y = 243 x/2 = 4y so, x=8y and we have 8y+y=243 9y=243 y=27 so, x=216
*February 8, 2015*

**math**

0+1*2*3*4
*February 8, 2015*

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