Friday

February 27, 2015

February 27, 2015

Total # Posts: 29,274

**maths**

2/5 * 1/2 = 1/5 1/3 * 3/4 = 1/4 1/4 is 25% more than 1/5
*January 18, 2015*

**Physical Science**

good question. Find the chemical formula for the sweetener, divide the mass of the package by the molecular mass of the formula, and multiply by Avogadro's Number. If that's all gobbledegook to you, then clearly you haven't been presented with the means to do the ...
*January 18, 2015*

**physics**

since v = at, clearly it is 1.1i + 0.56*4.8j
*January 18, 2015*

**Math**

No idea what a pattern of 1,3,5 means. You do know that y = a(x+4)^2 + 5 It opens up, so a > 0. Use that with the weird pattern data to finish it off.
*January 18, 2015*

**Math**

4+5+6+7+9 = 31 So, the new sum will be between 34 and 41 Divide both of those by 6 and match it up with the choices.
*January 18, 2015*

**Math**

I think you can easily fill in the first two. Simple multiplication and division, right? (g◦(h◦f))(-4) = g(h(f(-4))) = g(h(-2)) = g(9) = -33 Note that h(x) = (x-1)^2. So, f(h(a+4)) = f((a+4-1)^2)) = f((a+3)^2) = (a+3)^2+2 You can expand that if you want.
*January 18, 2015*

**Physics**

just plug your numbers into y = tanθ x - g/(2(v cosθ)^2) x^2 and solve for x when y = -125
*January 18, 2015*

**algebra**

64+35-14 = 86 So, two buses can hold the lot. Even chaperones! (A ∪ B) = {6,7,8,9,10,11} So, (A ∪ B) ∩ C = {8,10}
*January 18, 2015*

**algebra**

just recall the rule that total = one + other - both. So, counting just the ones taking something, you have 20+32-6 = 46 So, the other 4 took nothing.
*January 18, 2015*

**Mathematics arithmetic sequence**

a+d + a+5d = 4 a+2d = a+10d + 24 Collect terms and solve for a and d. Then write a,a+d,a+2d
*January 18, 2015*

**Algebra 1a**

just add the exponents. x^2 = xx x^3 = xxx x^4 = xxxx So, adding the exponents just means counting how many times you have x multiplied together.
*January 18, 2015*

**Algebra 1a**

(xy)^-3 = 1/(x^3y^3) (x^-5y)^3 = x^-15y^3 = y^3/x^15 So, you have 1/(x^3y^3) / (y^3/x^15) = 1/(x^3y^3) * x^15/y^3 = x^15/(x^3y^3y^3) = x^15/(x^3y^6) = x^12/y^6
*January 18, 2015*

**Physics**

#1 is correct
*January 18, 2015*

**Algebra**

√(48a^2b^7) recall that √x^2 = x, so factor out all the perfect squares: √(16*3*a^2*b^6*b) √(16a^2b^6)√(3b) 4ab^3 √3b
*January 18, 2015*

**Math Homework Help**

I think that's just sec^2 y - 1, which is tan^2 y cot^2 y * tan^2 y = 1
*January 18, 2015*

**geometry**

since angles E and F are congruent, the sides opposite them (DF and DE) are congruent. That means that 4x-6 = 2x+8 x = 7 Now you can figure the perimeter.
*January 18, 2015*

**chemistry**

Lothium Iodide?
*January 18, 2015*

**geometry**

you know how to find the area of a square, right? So, consider that the sides of the entire area are 12 feet longer than those of the playground. Subtract the area of the playground from the entire area.
*January 18, 2015*

**physics**

1/√2i - 1/√2j
*January 18, 2015*

**physics**

v = dy/dt = b - 2ct now just solve for t when v=0
*January 18, 2015*

**math**

x(1-2/5)(1-1/3) = 56 x = 140 check spent 2/5 of 140 = 56, leaving 84 spent 1/3 of 84 = 28, leaving 56
*January 18, 2015*

**addmath A.P.**

clearly the lengths of the sides are sequential integers, starting with x. The sum of the perimeters is thus 4(10x + 9*10/2) = 40x+180 = 380 ...
*January 18, 2015*

**Algebra**

(f o g)(x) = f(g(x)) g(-6) = 1 f(-1) does not exist (fog)(-18) nope (fog)(-14) nope (fog)(-2) nope For no value does fog exist (gof)(-4) = 9 (gof)(0) = 1 (gof)(-6) = 13 (gof)(2) = -3 So, the domain of gof is the domain of f.
*January 17, 2015*

**calculus**

we have x^2+y^2 = 225 2x dx/dt + 2y dy/dt = 0 Now plug in x=9, y=12, dy/dt=-1/3
*January 17, 2015*

**calculus**

oh, well, you really want it all, eh? The very first one (calculus honor) has slightly different numbers, but it is exactly the same problem. Follow the solution, using your numbers.
*January 17, 2015*

**calculus**

Damon did this. Look at the related questions below.
*January 17, 2015*

**algebra - obfuscation**

pretty confusing, especially where it says mary was six years before the time when . . . Not sure what that is intended to mean.
*January 17, 2015*

**Composite Functions**

Hmmm. (g*f)(x) = g(x)*f(x) = √(x-15)(x^2-2x) The composite function (g◦f)(x) = g(f(x)) = √(f-15) = √(x^2-2x-15) Your factoring is correct, but I see no advantage to it. It ought also to be written as √((x-5)(x+3)) to avoid confusion with √(x...
*January 17, 2015*

**AP Calc (Limits on Piecewise Functions) #2**

well, geez, these are common enough angles . . . the left limit is sin π/3 = √3/2 the right limit is (π√3)/(2π) = √3/2 Looks like f(x) is continuous
*January 17, 2015*

**Algebra 2 - typo**

Go with Reiny on #3. I made a typo in my (x-3) factor.
*January 17, 2015*

**Algebra 2**

In general, it is very difficult to find zeros of polynomials higher than degree 2. So, you have to look for some low-hanging fruit using synthetic division, or try grouping. Graphical methods may also be useful, if it's obvious that the roots are easy ones. I usually ...
*January 17, 2015*

**Physical science**

when they are acting in the same direction.
*January 17, 2015*

**geometry**

ok. now what?
*January 17, 2015*

**math**

everything appears ok down to the last part. 4"/mo for 9 months is 36". Since the average annual amount is 43.2", those 9 months did not exceed the annual average. This is to be expected, since the monthly amount was only a little bit more than the usual monthly...
*January 17, 2015*

**AP Calc (Limits on Piecewise Functions)**

left limit is 1/2 f(pi/6) = 1/√3 right limit is √3/2 So, not only are the left and right limits different, but even if they were the same, f(x) is defined to be something else at x=pi/6!
*January 17, 2015*

**Algebra 1**

Write a scientific notation for .0042 My answer is 4.2 10^-3
*January 17, 2015*

**7th grade math**

You are correct. The total cost is $22.68
*January 16, 2015*

**A big thank you to Ms.Sue☺**

I assume this is relevant to the above topic because we might want to buy stock in such companies? . . .
*January 16, 2015*

**speed**

you want t where 9000t = 10000(t-0.25) Then plug that value for t into either side of the equation. Just recall that distance = speed * time
*January 16, 2015*

**Algebra 1**

Simplify mn^-4/p^0 q^-2 My answer is mq^2/n^4
*January 16, 2015*

**Geometry**

Take a look here: http://www.algebra.com/algebra/homework/Geometry-proofs/Geometry_proofs.faq.question.392003.html
*January 16, 2015*

**Algebra 1**

correct
*January 16, 2015*

**Algebra 1**

Simplify 5^-1(3^-2) My answer is 1/45
*January 16, 2015*

**meeting and chasing problem**

it takes Amy 1/3 hr to get to the store. Another hour passes. During that time, Beth has walked 1+3 = 4 miles. So, the two must cover 26 miles at a combined rate of 30+3=33 mi/hr. That takes 26/33 hours. During that time, Beth has walked another 26/33*3 = 26/11 miles. So, they...
*January 16, 2015*

**Math**

it took Sally 2 hours to go 180 km. That's 90 km/hr. If Kelley traveled at 80 km/hr, it would take her 2.25 hr. So, she would arrive at 10:45 am
*January 16, 2015*

**Math**

No. The temperature really makes no difference. What you want is 1088 = 0.2204 x where x is the speed of sound in cold water.
*January 16, 2015*

**math**

1-digit: none 2-digit: 1 (21) 3-digit: 10 (201 ,,, 291) 4-digit: 1 (2001) So, 12 in all.
*January 16, 2015*

**Math**

cylinder: πr^2h = 1200 cone: 1/3 πr^2h = 1/3 (1200) = 400
*January 16, 2015*

**math - I'm outta here.**

Ignore that post. It added the window and door, rather than subtracting them. Also, you started out by saying the walls were 8' high. What's the 5x7 foot stuff? And we STILL don't know how wide the walls are!!!!
*January 16, 2015*

**math**

Boy, you're not willing to put anything into this, are you? so, the painted area is (converting the door and window to feet, rather than inches): 4(5*7) + 7*3 + 2*3 = 167 ft^2 So, how many cans will it take, at 100 ft^2 per can?
*January 16, 2015*

**math - still incomplete**

so, the walls are 8' high. How wide are they? Are they all 4 the same width? If not, can we assume the room is rectangular? At any rate, you surely know that for a rectangle, the area is height x width. So, add up the areas for all the walls, then subtract the areas of the...
*January 16, 2015*

**Math**

each large tile covers 3x3 = 9 small tiles. So, what do you think?
*January 16, 2015*

**algebra2**

any value of y which makes the denominator zero is excluded. So, what is y when y+4 = 0?
*January 16, 2015*

**algebra**

since you cannot divide by zero, any value of b which makes b-2 = 0 is excluded.
*January 16, 2015*

**calculus**

s = 4π r^2 ds/dr = 4π(2r) = 8πr
*January 16, 2015*

**trigonometry**

review your basic trig function definitions. Draw a diagram, and you will see that the line-of-sight distance x is given by 800/x = sin 12° The distance along the ground is given by 800/x = tan 12° Pick your case, and just solve for x.
*January 16, 2015*

**trigo**

If the angle is x, then tan x = 50/60
*January 16, 2015*

**Coeakwanga**

well, just plug in the numbers in your formula: An = 2+2n
*January 16, 2015*

**Math, Quadratic Functions**

2(x+y)=80, so y = 40-x area = xy = x(40-x) = 40x-x^2 That's just a parabola. Find the vertex and you will have the maximum area. A little investigation that the rectangular shape of maximum area for a given perimeter is always a square.
*January 16, 2015*

**calculus**

y = 8/x y' = -8/x^2 now plug in x = -3 the avg rate of change is change in y ------------------ change in x So, that would be (y(4)-y(-3))/(4-(-3)) Now just plug in the numbers
*January 16, 2015*

**calculus**

study any proof of the MVT or Rolle's Theorem for the first one. For the 2nd one, since f satisfies the conditions of the MVT, and is concave down over the whole interval, there is but one number c in the interval.
*January 16, 2015*

**MATH**

h(t) = 149 - 59cos(2pi t) all your answers are correct
*January 16, 2015*

**Pre-Calc**

s = rθ, so 1*θ = 10 θ = 10 radians
*January 16, 2015*

**science**

work = force * distance no distance, no work.
*January 16, 2015*

**Circles**

w00t!
*January 15, 2015*

**Math**

F=ma So, since a on earth is 9.8, on earth he weighs 60*9.8 N on the moon, he weighs 60*1.6 N
*January 15, 2015*

**Math**

A to B: Since the scale does not change, 60/(3/4) = x/(4 5/8) 60*4/3 = x * 37/8 x = 60 * 4/3 * 8/37 Do the other parts the same way. Remember that the scale does not change! If a distance is twice a big on the map, it is twice as big in the world.
*January 15, 2015*

**math**

$7 is 1/6 of 3/7 of Bella's money, so she had $98 to start with. 4/7 of 98 is $56, as you figured. The dictionary and the books cost 56 d+3b = 56 3/8 d = 1/2 * 3b so, 3d = 12b 4b + 3b = 56 b = 8 check: 3 books cost 24 dictionary cost 32 3/8(32) = 1/2(24) 12=12
*January 15, 2015*

**Math**

have you no calculator? If not, just type 1221/3 into google's entry box, and it will do the calculation for you. The answer is 407. If you go to http://www.webmath.com/divide.html and enter you numbers, it will show how the division is done.
*January 15, 2015*

**math**

180 = 5/8 x
*January 15, 2015*

**math**

could be any of those. What haven't you told us?
*January 15, 2015*

**Math**

.70 * 185 = ?
*January 15, 2015*

**Math**

right. x+y=7 that counts the coins. Now you have to count the value. If you have x nickels and y quarters, then 5x+25y = 95 Now, you can insert your first equation into this one as follows: 5x+5y+20y = 95 5(x+y)+20y = 95 5(7)+20y = 95 35+20y = 95 20y = 60 y=3 so, x=4 That is ...
*January 15, 2015*

**geometry - bogus?**

I don't see how you can say that LM ≅ TU, and then say that LM=15 and TU=10. Also, when you say LMN ~ TUV that implies that the vertices are listed in the same respective order. That is, LM ~ TU MN ~ UV NL ~ VT But that's not the case here.
*January 15, 2015*

**Math**

32+56 = 8(4+7)
*January 15, 2015*

**math**

what you really need is to think about the problem. By 12:30, car A had been traveling 1/2 hr at 50 mph. SO, it had gone 25 miles. At 3:PM, both cars had been traveling an additional 2.5 hours, so Carter had gone another 2.5*50 = 125 miles. Carter's total distance is thus ...
*January 15, 2015*

**Math**

7*9+7 = 63+7 = 70
*January 15, 2015*

**Math**

that is correct, but to follow the advice given, you should have taken the following step: 43+9 = j-9+9 That gets rid of the 9 from one side and leaves j all alone: 52 = j That is the result you wanted, not just rewriting it with the solution inserted. When it says to solve ...
*January 15, 2015*

**Math**

8000(1+0.11/2)^(2*8) = ?
*January 15, 2015*

**math**

a = (5-2x)(3-2x) a = 12
*January 15, 2015*

**Math**

just set 4x = 2x^2 4 = 2x x = 2
*January 15, 2015*

**Math - oops**

y(-1) = -2
*January 15, 2015*

**Math**

you ever gonna show any of your work? you want the slope of the line (-2) to be the same as the slope of the parabola. The slope of the parabola at any point (x,y) is 6x+4 So, if 6x+4 = -2, x = -1 y(-1) = 6, so the line y = -2x+b must pass through (-1,-2) I think now you can ...
*January 15, 2015*

**Math**

downstream speed: 10/(1/2) = 20 mi/hr upstream speed : 10/(5/6) = 12 mi/hr So, if te boat's speed is b and the current's speed is c, b+c=20 b-c=12 now go figure c
*January 15, 2015*

**Position vs. Time graph clarification**

it is a parabola, just like the trajectory of a falling body under constant gravitational acceleration.
*January 15, 2015*

**algebra**

0.80c + 50 = 1.05c c = 200
*January 15, 2015*

**Math**

Divide the octagon into 8 congruent isosceles triangles, each with base 15. Since the vertex angle is 360/8 = 45°, each of the slant sides has length 7.5/sin22.5° = 19.6 The desired distance is twice the length of one of these sides, or 39.2
*January 15, 2015*

**algebra**

no access to those files. Better just give some coordinates. Then use the 2-point form of a line to get the equation.
*January 15, 2015*

**MAT222**

since 27 = 3^3, 27^(1/3) = 3 27^(2/3) = 3^2 = 9 So, you have 27^-(2/3) = 1/27^(2/3) = 1/9 the other is correct
*January 15, 2015*

**alegbra 1**

a little less work would be to note that if you subtract one equation from the other, the x's disappear: x+y=5 x-3y=3 4y = 2 y = 1/2 Then use that value of y in either equation to get x.
*January 15, 2015*

**chemistry**

2H2 + O2 = 2H2O 10g of H2 is 5 moles. Each mole of H2 produces a mole of H2O, so, you will get 5 moles of water. Just convert that to grams for the mass.
*January 15, 2015*

**math**

2500/25 = 100 m^2 since a = pi r^2, pi r^2 = 100 So now you can easily find r.
*January 15, 2015*

**math**

a+b = 8 10a+b + 18 = 10b+a Now just solve for a and b, the two digits.
*January 15, 2015*

**solid mensuration**

since s = rθ, r = s/θ = 112/(28 * π/180) = 229m
*January 15, 2015*

**MAth Igcse**

If we label the top of the tower T and the bottom Q, then we have tan 27° = PQ/QA tan 11° = PQ/QB QA^2 + QB^2 = 40 (PQ/tan27°)^2 + (PQ/tan11°)^2 = 40^2 Now just solve for PQ, the height of the tower.
*January 15, 2015*

**solid mensuration**

the area, of course, is base * height = 225*80 = 18000m^2 Use the law of cosines for the diagonals. The angles between the sides are θ and π-θ, where sinθ = 80/145
*January 15, 2015*

**precalculus**

so, use the product-to-sum property: sina cosb = 1/2 (sin(a+b)+sin(a-b)) with a=x+y and b=x-y, that gives 1/2 (sin(2x)+sin(2y)) Not sure why you would have used up so much paper, given that they told you what formula to use...
*January 15, 2015*

**calculus**

I always hate to see homework dumps. I'll do a couple, but till I see some work on your part, I feel no obligation to do all your work. #1 f(x) = cos(x) f'(x) = -sin(x) at the given point, f'(2) = -sin(2) #2 Recall that |x| = x if x >= 0 |x| = -x if x < 0 At ...
*January 15, 2015*

**algebra**

Hmm. It occurs that you might have meant that 4b = b+12 so, b = 4 baby is 4, sitter is 16
*January 15, 2015*

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