well, since the only infinitive is "to ride" I guess it'd be (D), eh? Extra credit: what is "to work"?
80000 * .020 = 1600
pick a point in plane #1, say (2,3,1) Now just use the distance formula to get the distance to 6x-6y+6z=3 or, equivalently, 2x-2y+2z-1 = 0 d = |2*2-2*3+2*1-1|/√(2^2+2^2+1^2) = 1/√5
You do the hokey pokey and you turn yourself about. That's what it's all about!
If 1 side of a triangle is 10 inches and the same side in a 2nd triangle is 20 inches. A 2nd side is 4 inches in the 1st triangle what is the same side in the 2nd triangle? My answer is 8 inches
and you are correct
well, let's see 120 = 10*12
since 77 = 7*11, I think the answer is clear.
I think that if someone had a method of predicting winning numbers, they'd probably be sunning on the French riviera on their winnings, rather than handing out their secret.
1st fall: 2m nth bounce: 2*(3/4)^n So, you have to decide what "at rest" means. At some point the friction will overcome the tendency to bounce, and the bounces will stop. In theory, the ball bounces forever, each time achieving less height. So, once you decide how h...
Thx to Reiny
Sorry to be obscure, Joy. It was sort an informal shortcut, so I could present the subtraction of x- and y-values both at once. If you look carefully at Reiny's calculations, you will see that the same subtractions show up in my pairs of numbers. The logic was: figure the ...
y = 4-(5x-4) = 8-5x
Assuming you meant "A" instead of "H", note that if A is at (0,0), then A to B = (300,0) B to C = (167,-109) So, adding them up, C is at (467,-109) and is 480 km from A
cost is the same when 100.00 + .50x = 90.00 + .60x now just solve for x then, unless there's a typo, convert km to miles!
Algebra II - oops
Zowie! Did I say that? x^2 - 4 is the graph of x^2 shifted down 4 units.
excellent graphing help can be found at http://rechneronline.de/function-graphs/ where you can plot up to three functions on the same axes. Note that x^2-4 = (x-2)^2, so it is the graph of x^2, shifted 2 units to the right.
you can also make use of the fact that the vertex is midway between the roots. Recall that the roots are at x = -b/2a ±(some junk) That means that the vertex is at x = -b/2a. Plug that in to get the y-value: y = 2x^2-12x-6 the vertex is at x = 12/4 = 3 y(3) = 2*9-12*3-6...
LCM(4,7,5) = 140 1/4 = 35/140 6/7 = 120/140 3/5 = 84/140 that should help
((10-25) m/s)/240s = -1/16 m/s^2
32-(-8) = 40 = 8d, so d = 5 -8+3*5 = 7 or, T4 = T1 + 3*(T9-T1)/8
Hm. I get 3 _ _, _ 7 _ . 4 _ 1
wikipedia has a nice article, with examples in the natural sciences.
basically correct Though that may not guarantee that the curve is exponential. Given that assumption, your reasoning is correct.
Did we forget 2,6 and -2,-6?
math - other possibilities
Damon's answer does indicate how many do not buy their lunch in the cafeteria. Your series of questions indicates there may be students who bring their lunch who do not bring it from home. Maybe they ripped off a convenience store on the way to school. Maybe they stole som...
(a) using (i) and (ii) 2gg' + 2hh' = 0 2gh^2 + 2hh' = 0 gh + h' = 0 h' = -gh (b) from (a) and (iv), h'(0) = -g(0)*h(0) = 0 h" = -g'h-gh' so, h"(0) = -g'(0)h(0) Since h(0)>0, g'(0)>0, so h"(0) < 0 (c) from (ii) and...
c+t = 4 2c+2p = 9 p+2t = 2 c = 3.5 t = 0.5 p = 1 c+t+p = 5
15 ft * 20 ft = 300 ft^3 Usually, carpet is measured in square yards, though, so that would be 15/3 yd * 20/3 yd = 100/3 yd^2
1.5/2 * 2 = 1.5 in assuming that hem size is proportional to dress size. Somehow I doubt that. I'd imagine the hem is a constant width. But, for the topic at hand, I guess we need the proportion.
science --- check my answers!
all looks good. Maybe #10 could also check (B), since boiling would drive off the water even faster than just evaporation.
Maybe you can't. The SAT assesses scholastic aptitude for attending an American university. If your English skills are poor, you probably will not do well there. So, I'd suggest getting help with English. Lots of reading can do wonders, as you will learn vocabulary and...
2(w + 2w-1) = 40 2(3w-1) = 40 3w-1 = 20 3w = 21 w = 7 so, the garden is 7 x 13 meters
w + w+163 = 2713 2w = 2550 w = 1275 . . .
Exponential Growth and Decay
That was a typo. She meant 16/8 since that is how many half-lives there were.
set into standard format 5x+3y = -9 2x-5y = -16 Now multiply by proper ratios to eliminate y: 25x+15y = -45 6x-15y = -48 now add to eliminate y: 31x = -93 x = -3 now substitute that value for x into either of the original equations to get y.
you know it will be a plane normal to the vector <7,-3,-6> passing through (3/2,9/2,0). I'm sure you've covered that.
If the pole's shadow is 14 times as long as her shadow, then the pole is 14 times as tall as she is. 14(5.5) = 77 feet
GEOMETRY MIDPOINT FORMULA
B-A = (-4,-3) C-A = 4(B-A) = (-16,-12) C = A+(C-A) = (-14,-9)
fenced area is 30*35 = 1050 inner area is (30-8)(35-8) = 594 walk area is the difference: 456
2nd Order linear ODEs
Hmmm. I'd let v = y' Then we have x^2 v' = xv v' = v/x dv/v = dx/x log v = log x + c v = e^c x or, v = c1 * x That means y' = c1 * x y = c1 x^2 + c2 check: y' = 2c1 x y" = 2c1 x^2 y" - xy' = x^2(2c1) - x(2c1 x) = 0
d*5^2 + d*5 + 4 = 124 25d+5d+4 = 124 d = 4
There are 8 ways to choose the first role, leaving 7 ways to choose the 2nd role, 6 ways for the 3rd, etc. 8*7 = 56, so we must have just two roles.
.70 p = 2.53 p = 3.61
7/(4+7+8) = 7/19
factor out 2x^5(x^2-9)^7 and you have 2x^5(x^2-9)^7 * (8x^2 + 3(x^2-9)) = 2x^5(x^2-9)^7 (8x^2+3x^2-27) and voila...
(1000*0.70)(1+r) = 1000 1+r = 1.428 r = .428 = 42.8%
7.50 <= x <= 8.49
.60 h = 27
m/sf = 4/3 sf/b = 4/5 sf = 48, so m/48 = 4/3 m = 64 48/b = 4/5 b = 60 sf+m+b = 48+64+60 = 172 maybe you can fit that into your bar model.
assuming it was circular, d = 7.9/pi = 2.5 inches
sin < 0 in QIII,QIV sec < 0 in QII,QIII so, what do you think?
If those are the (length,width) of your plots, then the area would be 3*2 + 8*6 = 6+48 = 54 unit^2
22 looks good to me
If you are going to integrate over y, the solid has two parts: a plain old cylinder of height 4 and thickness 2, and a variable-thickness shape of height 2. So, v = π(5^2-3^2)(4) + ∫[4,6] π(R^2-r^2) dy where R=5 and r=x-1=y-1 v = 64π + π∫[4,6] 2...
If $x is invested at 12%, then .12x - .05(18000-x) = 620
If you have x gallons of 15% juice, then .15x + 1.00(27-x) = .21(27)
correct on all counts
Actually, those are the roots of your equation, but they have nothing to do with the problem. Since f(-4) = f(3) = 0, the slope of the line segment joining (-4,0) and (3,0) is zero. the MVT says there is at least one value c between -4 and 3 where f'(c) = 0. So, since f...
Eric rounded up to the nearest inch. Or, the card is 2 3/4 x 3 inches, and they are calling different sides the length.
2*3^5-1 2*243-1 486-1 485
I assumed you wanted the roots of your equation 3x^2+10x-8=7
yes. the mean value theorem lets you pick any interval, but Rolle's theorem says f(a) = f(b). It's just a special case of the MVT where f'(c) = 0. Your interval here meets that condition. As for your exact value, forget about decimal approximations. (-5±W...
√3/2 ka man
h = t^(3/4) - 5t^(1/4) h' = 3/4 t^(-1/4) - 5/4 t^(-3/4) = (3√t-5) / 4t^(3/4) h' is undefined at t=0 h' = 0 at t = 25/9
If the dimensions are x wide and y high, then y = 160/x The printed area is a = (x-2)(y-1-7) = (x-2)(160/x - 8) = 176-8x-320/x da/dx = -8+320/x^2 da/dx=0 when x=2√10 Now figure y and you're done.
f = x^4 - 8x^2 + 6 f' = 4x^3 - 16x f" = 12x^2 - 16 f'=0 at x = 0,±2 at x = -2, f" > 0 so f has a local min at x = 0, f" = < 0 so f has a local max at x = 2, f" > 0 so f has a local min So, now just evaluate f(x) at 0,±2 and th...
substitute the value of a variable from one equation into the other equation. For #1, we are told y = x-11 So, substitute that into the other equation, and we have 3x + 10(x-11) = -6 3x + 10x - 110 = -6 13x = 104 x = 8 So, y = x-11 = 3 Be sure to check the solution to make sur...
S = 0.9p - 1500
well, plug it in... g(-4n) = (-4n)^3 - 5(-4n)^2 = (-4)^3 n^3 - 5(-4)^2 n^2 = -64n^3 - 80n^2
frosting on the top and the curved sides, so π(9/2)^2 + π(9)(4) = ?
.086 * 3000000 = ?
equal shares are 5/6 pizza each. 5/6 - 1/2 = 1/3
m = (4600-136)/36
A(n) = 2*3^(n-1) one less than n just means n-1
Math; Check my answers please
both are correct, but I think the answer to #2 does not relate well to the question. I'd have said tan^-1(0) = 0 since tan(0) = 0
A D A
correct but, (x-3)(x-1)=-2x-3 is not the same equation.
wherever there's a y, just plug in 3: 5(3^2)+2(3)+7 5(9)+2(3)+7 45+6+7 58
5/31 * 23/15 = (5*23)/(5*3*31) = 23/93 Looks like (B) to me
h = 3.0 + 2.58t - 4.9t^2 h=0 when t=1.08883 v = 2.58 - 9.8*1.08883 = -8.09 max h(0.263) = 3.34 Hmm. the max height seems kinda low, given that he started at 3.0 m up. Better double-check my math.
Sorry, Writeacher. Got carried away for a minute.
32 yd/min * 36in/yd * 1 min/60s = 96/5 in/s
I assume that Sn = sum(1..n) An, so Sn -> 3 Dunno where the x comes from, but if you mean when n > 1, An = Sn - s(n-1) = (3n-2)/(n+1) - (3(n-1)-2)/(n-1+1) = 5 / n(n+1)
no table, so no help on #1 t+h = 117 10t + 100h = 6390 so, 10(117-h) + 100h = 6390 h=58 so, t=59
Physics Help - Use Damon's Answer
Go with Damon - I switched the a and the t.
39 km/hr = 10.83 m/s s = Vi*t + 1/2 at^2 25 = 10.83t + .5 at^2 v = Vi + at 10.83 + at = 0 so, t = 2.35s a = -4.46 m/s^2
80 <= (78+92+x)/3 <= 85 240 <= 170+x <= 255 70 <= x <= 85
luckily, f' = f
well, what is the area of a parallelogram of base b and height h?
5/10 = 1/2 subtract exponents when dividing s^-7 / s^-9 = s^-7 * s^9 = s^2 Looks like you need to review dividing powers. Also constructing fractions.
(5/10)s^(-7+9) = s^2/2
you can cage a swallow can't you?
Sorry - I meant 18-6 confusing the answer with the problem. (C) is the answer
the bucket holds 3 cans, or 18L. SO, what's 18-12?
Correct (-2)^-1 = -1/2 (-2)^-2 = 1/4
just add them up: 2u-3v-w = 12-6-6 8-6-2 10-9-1 = 0 0 0
2.5 @ W45N = -1.77i + 1.77j 4.7 @ E60S = 2.35i - 4.07j do the others likewise. Then add them all up and convert back to a distance and bearing
what is your problem? Quid causæ habes? qual é o seu problema? was ist Ihr Problem? vad är ditt problem? таны асуудал юу вэ? 你有什麼問&...