P(x) = R(x)-C(x) = -2x^2+360x-100 P'(x) = -4x+360 P'=0 at x=90 P(90)=16100 good work AvgCost A(x) = C(x)/x = x+40+100/x A'(x) = 1-100/x^2 A'=0 at x=10 A(10) = 60
if you can find the critical numbers, that is where the derivative is zero. That is the point of min/max of the function. Check some of the related links below; you will find such problems worked out. Also, a net search for minimum revenue and such will produce many examples s...
revenue is price * quantity profit is revenue - cost avg cost is totalcost/quantity as usual, max/min is found via the derivative
it's the number of permutations of 3 distinct items: 3! = 6
if Ricardo's age is x, then x+(x+4)=14 2x+4=14 x=5
since the rates per period are the same, simple interest is less than compound interest.
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you'll never get a job if you cant communicate in clear English. If that's the best you can do, your time in school has been wasted. Figure out what you like, find people who are good at it, and talk to them about what it takes to succeed in that field. One of the best...
by dividing each term by -8 and by x^2: -5x^3+7x^2-3x
f undefined for x=0 f' = 2-6/x^2 f'=0 when x=±√3 I'll let you sort them out.
find the prime factors of each number. The GCF is the highest power of each prime that they have in common 80=2^4*5 60=2^2*3*5 GCF(60,80) = 2^2*5 = 20 3 is not common to both numbers, so it is not a factor of the GCF.