# Posts by steff

Total # Posts: 37

**math**

I love my mom

**find the derivative**

and help with this one... f(t)= e^7t * In (t+4)

**find the derivative**

3 In (√x + 7)

**Integration by parts**

integrate (e^x-x)^2 dx

**Calculus**

Thank you!

**Calculus**

help! ∫((ln x^2)/x)) dx u= ln x^2 du= 2 ln x dx (?) Not sure how to set this one up?

**integration (calculus)**

got it figured out.

**integration (calculus)**

Find the indefinite integral. ∫((e^-x-1)/(e^-x + x)^2) dx I am trying to use the substitution method. u=e^-x + x du= -e^-x+1 dx Right so far?

**U-substitution (calculus)**

this is an example from the book. I do not understand where the 1/2 comes from in (1/2u)du. Find indefinite integral. ((.3x-.2)/(.3x^2-.4x+2))dx u=.3x^2-.4x+1 du= 2(.3x+.2)dx 1/2u(du)= 1/2 In u + c 1/2 In(.3x^2-.4x+2) + c

**Calculus**

Am I right so far? G(x)=e^x sqrt(1+x^2) =e^x(1+x^2)^1/2 =e^x(1/2)(1+x^2)^-1/2(2x) + e^x(1+x^2)^1/2 So I used product rule, chain rule, and exponential function with base e

**Implicit (calculus)**

Can someone explain implicit differentiation to me like I am a kindergarten? I am not getting it. Any hints to help me understand better?

**Calculus (demand)**

18) The demand equation is x + 1/6p - 10+0. Compute the elasticity of demand and determine whether the demand is elastic, unitary, or inelastic at p=50. a) 5; elastic b) 1/9; inelastic c) 7/6; elastic d) 6; elastic I choose answer A. Is that correct?

**Derivative**

25) Suppose F(x) = g(2x^2 + 2). Find F(1) if g'(4) = -3. This is the question on my take home test. Seems to me that the question is wrong. Should it be f'(1) if g'(4) = -3? Your thoughts?

**calculus**

Thanks. I am on my ipad and it is such a pain to type this stuff out. I get a little lazy.

**calculus**

Just want to check and see if I am setting this up right. Let y=f(x)=x^2-6x Find the average rate of change of y with respect to x in the interval from x=4 to x=5 (5^2-6*5)- (4^2-6*4)/ 5-4

**derivative calculus**

Thanks. I see my mistake now.

**Multiple choice options**

added

**derivative calculus**

Here are my options a) 10t^2+32t√t - 5 / √t b) 20t^2-64t√t - 5 / 2√t c) 20t^2+ 32t√t - 5 / 2√t d) 20t^2+64t√t - 5 / 2√t e) 10t^2-32t√t - 5 / √t

**derivative calculus**

Please help. f(t)=(4+√t)(4t^2-5) This is what I have so far... (4+√t)(8t)+(4t^2-5) (1/2t^-1/2) Am struggling to get this in factored form. Am working on a multiple choice take home test and nothing I am getting matches.

**Calculus derivative**

Thanks. I was missing the step where you plug in the -1 to get slope.

**Calculus derivative**

Find the slope and an equation of the tangent line to the graph of the function f at the specified point. f(x)=-1/3x^2+5x+5: (-1, -1/3) Answer: f’(x)=-2/3x + 5 y=-2/3x -1 I re-worked the problem and got f'(x)=5, y=5x+ 14/3 This is from a multiple choice test and this ...

**Derivative Calculus**

Thanks. I will check my answer.

**Derivative Calculus**

I just need my answers checked. 1) Find the derivative. f(x)=3x^5/4 - 8/9x^9/8 + x^2 - 9x + 1 Answer: f’(x)= 15/4x^1/4 - x ^1/8 + 2x -9 2) Let f(x)= 7x^3 - 9x. Find f’(5) Answer: f’(x)=21x^2-9 f’(5)=516 3) Find the given limit by evaluating the derivative. ...

**derivative**

41) Find the derivative. h(x)= (3x^2 + 1)^3 / (x^2 - 1)^4 This is where I am at the moment.... h'(x)= (x^2-1)^4 (3)(3x^2+1)^2(6x) - (3x^2+1)^3(4)(x^2-1)^3(2x) This is what I am trying to get....(not final answer) =2x(x^2-1)^3(3x^2+1)^2[(9)(x^2-1) - (4)(3x^2+1)} Am really ...

**derivative**

Should be =4x(3-4x)^3(-12x+3)

**derivative**

29) Find the derivative of the function. F(X)=2x^2(3-4x)^2 This is what I have so far. I am usually pretty good at simplifying but I am missing something here. f'(x)=2x^2(4)(3-4x)^3(-4) + (3-4x)^4(4x) Here is where I go wrong. (Answer from book) =4x(3-4x)^3(-12+3) Thanks ...

**Supply and Demand**

50) the monthly demand and supply functions for the Luminar desk lamp are given by p=d(x)= -1.1x^2 + 1.5x + 40 p= s(x)= 0.1x^2 + 0.5x + 15 respectively, where p is measured in dollars and x in units of a thousand. Find the equilibrium quantity and price.

**Supply & Demand**

42) Given the demand equation 3 + p -40=0 and the supply equation 2x - p + 10=0, where p is the unit price in dollars and x represents the quantity in units of a thousand, determine the equilibrium quantity and the equilibrium price.

**french**

just missing some accents!

**reading**

But i don't have the book with me.

**reading**

where can i find the answers to a book i read ? The book is shark girl.

**Chemistry**

I found this but wasn't sure how accurate is was: 4.) There is a major effect of the nitrate ion in solution on the color emission because the nitrate ion is the oxidizing agent in the compound without it you could not produce a spectrum so there would not be an emission ...

**chem**

what kind of intermol forces can be seen in this molecule CH3COOCH2C6H5 is it only dispersion? If you mean BETWEEN molecules, then the O of the carbonyl will be slightly negative and some hydrogen bonding could occur with another molecule. Remember a few nights ago you asked ...

**Chemistry**

can anybody think of a reaction that involves benzyl acetate? formula is CH3COOCH2C6H5 i already have most of the synthesis's but i really need a reaction that involves this ester as a reactant NOT a product. thanks :) Why don't you just cleave the ester and make the ...

**science**

how do you figure out intermolecular forces in a molecule? 1. You learn (memorize) the types of forces and what causes them. 2. You go through example molecules with those forces. 3. You learn to recognize types of molecules (fats, covalent long chain, dipoles, etc).

**chem**

I have a really urgent question. I am wondering wheter or not esters are polar and what types of intermolular forces they have. can anybody answer this question nvm

**chemistry**

hi, I am wondering if benzyl acetate is polar or nonpolar? because it has a non polar benzene ring but also it has the ester bit attached so i am confused. Also i cant seem to understand the vander waal forces that are in it. if anybody could help that would be super A little ...

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