Friday

May 22, 2015

May 22, 2015

Total # Posts: 16

**physics**

the force is pulling both boxes to the right
*September 16, 2011*

**physics**

There are Two boxes on top of each other. The top has a mass of 2.99kg the bottom one has a mass of 7.89 kg. A horizontal force of 39.97 newtons is applied to the left to move them both at an acceleration of 1.42m's^2 Find the minimum coefficient of static friction μt...
*September 16, 2011*

**physics**

The speed of a point on a rotating turntable, which is 0.264 m from the center, changes at a constant rate from rest to 0.902 m/s in 1.94 s. At t1 = 0.64 s, find the magnitude of the tangential acceleration. Answer in units of m/s2 I assumed the velocity was constant so i ...
*September 12, 2011*

**physics**

The speed of a point on a rotating turntable, which is 0.264 m from the center, changes at a constant rate from rest to 0.902 m/s in 1.94 s. At t1 = 0.64 s, find the magnitude of the tangential acceleration. Answer in units of m/s2 I assumed the velocity was constant so i ...
*September 12, 2011*

**physics**

The speed of a point on a rotating turntable, which is 0.264 m from the center, changes at a constant rate from rest to 0.902 m/s in 1.94 s. At t1 = 0.64 s, find the magnitude of the tangential acceleration. Answer in units of m/s2 I assumed the velocity was constant so i ...
*September 10, 2011*

**physics**

The speed of a point on a rotating turntable, which is 0.264 m from the center, changes at a constant rate from rest to 0.902 m/s in 1.94 s. At t1 = 0.64 s, find the magnitude of the tangential acceleration. Answer in units of m/s2 I assumed the velocity was constant so i ...
*September 9, 2011*

**physics**

i figured it out if anyone would like me to work out the process let me know =]
*September 9, 2011*

**physics**

A ball on the end of a string is whirled around in a horizontal circle of radius 0.22 m. The plane of the circle is 1.69 m above the ground. The string breaks and the ball lands 2.68 m away from the point on the ground directly beneath the ball’s location when the string ...
*September 9, 2011*

**physics**

If the rotation of a planet of radius 3.41 × 106 m and free-fall acceleration 8.71 m/s2 increased to the point that the cen- tripetal acceleration was equal to the gravita- tional acceleration at the equator, what would be the tangential speed of a person standing at the...
*September 8, 2011*

**physics**

A plane is flying horizontally with speed 244 m/s at a height 5670 m above the ground, when a package is thrown downward from the plane with a vertical speed v(initial) = 73 m/s. What horizontal distance is traveled by this package? The acceleration of gravity is 9.8 m/s2 . ...
*September 3, 2011*

**physics**

Wiley Coyote (Carnivouous hungribilous) is chasing the roadrunner (Speediburd cant- catchmi) yet again. While running down the road, they come to a deep gorge, 22 m straight across and 101 m deep. The roadrun- ner launches itself across the gorge at a launch angle of 20◦...
*September 2, 2011*

**physics**

A plane is flying horizontally with speed 244 m/s at a height 5670 m above the ground, when a package is thrown downward from the plane with a vertical speed v(initial) = 73 m/s. What horizontal distance is traveled by this package? The acceleration of gravity is 9.8 m/s2 . ...
*September 2, 2011*

**physics**

Thank you very much.. i understand it...it crosses the x-axis when the y point is =o, and is parallel to the y- axis when the vector in the x direction aka the slope is = to 0 =]
*September 2, 2011*

**physics**

A particle has ⃗r(0) = (4 m)j and ⃗v(0) = (2 m/s)i. If its acceleration is constant and given by ⃗a = −(2 m/s2) (i +j), at what time t does the particle first cross the x axis? Answer in units of s. part 2. At what time t is the particle moving parallel...
*September 2, 2011*

**physics**

after calculating all that i came to a max height of 206.59m but supposedly that is not the correct answer ? did i make an error- because i worked out the problem numerous times.
*August 30, 2011*

**physics**

A model rocket is launched straight upward with an initial speed of 52 m/s. It acceler- ates with a constant upward acceleration of 2.6 m/s2 until its engines stop at an altitude of 202.2 m. What is the maximum height reached by the rocket? Answer in units of m How long after ...
*August 30, 2011*

- Pages:
**1**