Monday
December 9, 2013

# Posts by sophie

Total # Posts: 365

Math
tan^-1(1/2)=x=.463648 tan^-1(2/3)=y.588003 x+y+pi/2 = -z=2.62245 z=-2.62245 cos (z) = -.868243 and tan a= -1/2 tan b= -2/3 tan (a+b)=(tan a +tan b)/(1-tan a.tan b) so tan (a+b)= -7/4 sec^2 x-tan^2 x=1 so sec (a+b)=√(1+49/16) =√(65/16) (a+b)=1/sec (a+b) so cos(a+b) ...

Math
ohh okay thanks!

Math
If α and β are two angles in Quadrant II such that tan α= -1/2 and tan β = -2/3, find cos(α+β) Work: cos(α+β) = [ 1 - (tan α)(tan β) ] / [ 1 + (tan α)(tan β)] cos(α+β) = [ 1 - (-1/2)(-2/3) ] / [ 1 + (-1/2)(-...

Math
thanks for checking (;

Math
Find the measure of the reference angle for 400 degrees. I did the work and got 40 degrees, is this right?

Math
Thanks for checking!

Math
Find sin(sin^-1 1/4) is the answer 1/4?

Math
never mind, i was right

Math
Write an equation in slope-intercept form of the line whose parametric equations are: x = (1/2)t +2/3 and y = t - 3/4. a) y = 2x - 7/12 b) y = 2x + 7/12 c) y = -2x - 7/12 d) y = -2x - 25/12 I think it is D.....?

Math
thanks for checking!!

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