Tuesday

December 6, 2016
Total # Posts: 8

**mustapha**

0.0025*10^1/3

*December 27, 2015*

**Physics**

Magnitude = 1580 N from 3rd Law of Motion but F itself = -1580 N (opposite direction)

*July 28, 2012*

**physics**

Draw a block and tackle system of pulleys with a velocity ratio of 5 is used to raise a mass of a 25kg through a vertical distance of 40cm at a steady rate.

*November 20, 2011*

**math**

Thanks. I'm in 5th grade. It was just math question to continue these and other simple pattern: 1; 10; 3; 30 __; __; __; 150; 140; 170; 160; __; __; __; 5; 25; 50; 10; __; __; __; 2; 5; 10; 3; __; __; __; 1; 300; 2; 600; __; __; __; my answers continue a pattern: 1; 10; 3...

*October 21, 2008*

**math**

continue a pattern: 1; 10;3; 30 __; __; __; 150; 140; 170; 160; __; __; __; 5; 25; 50; 10; __; __; __; 2; 5; 10; 3; __; __; __; 1; 300; 2; 600; __; __; __;

*October 21, 2008*

**math**

continue a pattern: 1; 10; __; __; __; 150; 140; 170; 160; __; __; __; 5; 25; 50; 10; __; __; __; 2; 5; 10; 3; __; __; __; 1; 300; 2; 600; __; __; __;

*October 21, 2008*

**algebra**

continue a pattern 1; 10; 3; 30; __; __; __:

*October 21, 2008*

**egypt-german univerty in cairo-sherif.el-sayed@student.guc.edu.eg**

s=integral let i=S(sec^3x)dx i=S(sec^3x)=S(sec^2x.secx).dx =tanxsecx-S(tan^2x.secx)dx= tanxsecx-S(sec^2x-1)secx.dx= tanxsecx-S(sec^3x)dx+S(secx)dx 2i=tanxsecx+ln|secx+tanx|+x i=(tanxsecx+ln|secx+tanx|+c)(0.5)

*October 15, 2006*

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