Sunday
May 19, 2013

# Posts by scott

Total # Posts: 495

Math
yes

science
y / x = tan(-47.5º) y = x * tan(-47.5º)

math
(0 * 2^0) + (1 * 2^1) + (0 * 2^2) + (1 * 2^3) + (0 * 2^4) + (1 * 2^5) 0 + 2 + 0 + 8 + 0 + 32 = 42 (2 * 12^0) + (1 * 12^1) + (9 * 12^2) 2 + 12 + 1296 = 1310

5 * x^3 * 4 * x * y^2 20 x^4 y^2

physics
stone time (T) plus splash time (t) equals watch time minus reaction time T + t = 3.65 - .25 __ t = 3.4 - T d = .5 * g * T^2 __ g = 9.8 m/s^2 also, d = 340 * t __ d = 340(3.4 - T) 4.9 T^2 = 1156 - 340 T 4.9 T^2 + 340 T - 1156 = 0 use quadratic formula to find T, then plug in t...

Physics
average velocity is __ 40.0 m / 9.40 s average equals initial plus final, divided by two 40.0 / 9.40 = (i + 2.35) / 2 __ i = 6.16 acceleration equals final minus initial, divided by time a = (2.35 - 6.160 / 9.40

Physics
average velocity is __ 40.0 m / 9.40 s or __ 4.26

Physics
the height of a freely falling object is: H = .5g*t^2 + Vo*t + Ho Vo is the initial vertical velocity Ho is the initial height (height of building) the height is 0 when the brick hits the ground in 3.3 sec g is -9.8 m/s^2 H = .5gt^2 + [17 * sin(25º)]t + Ho 0 = -4.9(3.3^2)...

College Physics
the potential energy at the top of the leap is equal to the (vertical) kinetic energy at the start m * g * h = .5 * m * [v * sin(45º)]^2 the m's cancel (2 * g * h) / [sin(45º)]^2 = v^2 g = 9.8 m/s^2 145 = v^2

physics
H = .5 g t^2 1.7x10^4 = .5 * 3.3 * t^2 1.03x10^4 = t^2 2) multiply the fall time (t) by the acceleration (3.3 m/s^2) to find the final velocity

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