# Posts by scott

Total # Posts: 2,425

**Algebra**

s + L = 40 s + 6 = L subtracting the equations ... eliminating s L - 6 = 40 - L

**Physics**

the supports each exert 98 N to support the plank one support exerts [490 N * m / 3] to support the person the other support exerts ... 490 N - [490 N * m / 3]

**Physics , static fluids**

the buoyancy force is the difference in the air weight and immersed weight

**Physics , static fluids**

hello (again) 8.6 meters is 860 cm if you picture a stack of 860 cm cubes of water, what is the force at the bottom? ... 860 gm * g ... this is the force on one cm^2 .86 kg * 9.8 m/s^2 = f a Pascal is one Newton per m^2 ... a kPa is .001 N per cm^2

**Physics**

you can use the density of water and the depth to find the pressure the "rule of thumb" for diving is one atmosphere for every ten meters of depth

**Physics**

e = 1/2 k x^2 ... (kind of like KE) 2.0 = 1/2 * 100 * x^2

**Physics**

look up Doppler shift formula

**Maths**

2 = (1 + .06)^t log(2) = t log(1.06) t = [log(2)] / [log(1.06)]

**Algebra 2 (Please help Ms. Sue!)**

use synthetic division

**Algebra**

(d / 55) + (d / 35) = 50 - 10

**Physics**

momentum is conserved find the momenta in x and y for the two decay products the two y momenta add to zero, and the two x momenta equal the original add the vectors to find the 234Th velocity

**pre calc**

100% - 30% = (1/2)^(2 / h) log(.7) = (2 / h) log(1/2) h = 2 log(1/2) / log(.7) (after a week) = (1/2)^(7 / h)

**Algebra**

it stops at the top, so the average velocity is ... (103 + 0) / 2 gravitational acceleration is 32 ft/s^2 , downward so the time to reach the peak is ... 103 ft/s / 32 ft/s^2 r * t = d

**Physics**

momentum is conserved, so the truck's loss is the car's gain 7500 kg-m/s / 750 kg = ?

**physics**

radio waves travel at the speed of light (c) ... 3E8 m/s the distance from Venus to Earth depends on where each planet is in its orbit around the Sun

**technical drawing**

85 m is 85000 mm 85000 mm / 10000 = ?

**science**

x + y = 10 3.1 x + 2.5 y = 25 solves easily by inspection (observation)

**physics**

6000 Nm/s = 6 kw

**Physics**

the object displaces 1/5 of its weight in water, so it is 5 times the density of water the weight change in the other liquid is 2/3 of the change in water, so the other liquid is 2/3 the density of water

**Chemistry**

the Ar will effectively be "squeezed" into 80% of its previous volume this will increase the tank pressure to 125% of the original the pp of Ar is 80% of the total the pp of nitrogen is 20%

**Physics**

F accelerates the three boxes equally since C is half of the total system mass, F equals twice the force on C

**physics**

the initial vertical velocity is ... 50 m/s * sin(37º) the (vertical) freefall equation is . h = 1/2 g t^2 + [50 sin(37º)] t + 55 plug in zero for h (ball on ground) and solve for t (use quadratic formula) the horizontal velocity is ... 50 m/s * cos(37º) ... ...

**math**

the intercepts are points with x and y coordinates for x-intercepts, the y coordinates are zero...but they still exist

**Physics**

avg vel = (14 + 0) / 2 = 7 rev/s stop time = 1/7 s distance = 1/2 a t^2 ... 1 = 1/2 * a * (1/7)^2

**Maths**

6 pts total per event 24 pts total awarded...so 4 events Betty has three 1st's and a 2nd Cathy has a 2nd and three 3rd's

**physics**

momentum (as usual) is conserved .05 * v = (5 + .05) * 10

**applied physics**

g = -980 cm/s^2 the object reaches its peak at 2 s average velocity is 980 cm/s ... so peak height is 1960 cm time up equals time down

**Physics**

KE = 1/2 m vB^2 6 KE = 1/2 * m/2 * vA^2 12 = (vA / vB)^2

**Physics**

twice the force, twice the stretch

**Math**

what design?

**Algebra**

the general equation is ... x = a(y - k)^2 + h the vertex is at the origin, so h and k are both zero a = 1 / 4p ... where p is the distance from the vertex to the focus b) the center depth is the value of x at the edges of the dish (where y equals ±7)

**Physics**

the acceleration (j) of the jet and gravitational acceleration (g) are two sides of the triangle j / g = tan(25º) ... j = 9.8 m/s^2 * tan(25º) multiplying j by 11 s will give the takeoff speed

**Psychics**

d = 1/2 a t^2 88.3 = 1/2 * 23.6 * t^2

**Math**

your "weird" answer is correct

**Math**

An = [10 * 3^(n-1)] + 1

**Technology**

the moments about the fulcrum must be equal for balance moment = mass * distance from fulcrum

**university physics**

momentum is conserved with the pellet/block find the velocity of the pellet/block the KE of the p/b is the work that compresses the spring 1/2 m v^2 = 1/2 k x^2

**Differential calculus**

the general vertex form is ... y = a(x - h)^2 + k ... (h,k) is the vertex a = 1 / 4p ... p is the distance from the directrix to the vertex

**Trig**

use Pythagoras (a^2 + b^2 = c^2) to find the angle functions then use the trig identity to find the tangent

**Advanced physics**

the period of the swing (pendulum) is related to its length the speed is not a factor

**Algebra**

a = 2 b 3(a + b) = 90

**Chemistry**

an interesting question will probably make for a lively class discussion a couple of pertinent facts ... normal exhaled air is about 15% O2 ... humans can "survive" in air down to about 6% O2

**Physics**

the work (energy) is equal to the KE of the object f d = 1/2 m v^2 123 * 45.6 = 1/2 * 10.0 * v^2

**Maths**

12 ... 4/10

**Math (Derivative)**

a) y = 6 x^-1 ... dy/dt = -6 x^-2 dx/dt ... dy/dt = (-6 / 64) * 12 b) missing y a typo?

**Math**

p(p + 1) = 3192 p^2 + p - 3192 = 0

**Science**

yes certainly if 180º apart

**Physics**

work (energy) to stop the wagon ... w = 42 * g * .18 * 16 w equals the initial KE of the wagon ... 1/2 * 42 * v^2 = w the speed of the boy is the same as the initial speed of the wagon

**Chemistry**

you are correct

**Maths**

eight "3" cards gives 24 ... 7 shy of 31 replace four "3" cards with three "5" cards and a "4" card

**Physics**

d = 1/2 a t^2 t = ?(2 * d * a)

**Physics**

the period (of the pendulum) is dependent on the length the speed of the "bob" is not a factor

**math- Trigonometry**

looks good...TALL lighthouse

**Chemistry**

.325 L * .05 M/L * 55.8 g/M

**Math**

time is inversely proportional to the number of machines and directly proportional to the number of raviolis t = 15 min * 15/75 * 6000/500

**science**

would call this a "trick" question circular path means radial (centripetal) acceleration there is no tangential component

**Math**

d = 6 233 - 53 = 180 ... so, 31 terms s = (233 + 53) * 31 / 2

**Physics**

1 kcal = 4184 joules m g h = 300 * 4184 h = (300 * 4184) / (1000 * g)

**Physics**

the gravitational potential energy becomes kinetic energy m g h = 1/2 m v^2 v = ?(2 g h)

**Physics**

20º is 1/18 of a circle (20/360) the length of the arc is ... 1/18 * 2 * ? * 1 m

**Physics**

momentum is conserved the smaller mass is 1/3 of the larger ... so it must have 3 times the speed

**Math**

check the related questions

**Physics**

f = m a ... a = f / m a = (33 - 12) / (6 + 15)

**physics**

time up equals time down h = 1/2 g t^2 = 1/2 * 32 ft/s^2v * (2 s)^2

**math**

the x-coordinate doesn't change the sign of the y-coordinate is reversed drawing a picture can help

**Math**

complex roots (zeros with i) occur in conjugate pairs f(x) = (x-6+3i)(x-6-3i)(x^5)

**math**

i = 7400 * [1 - (1 + .06/4)^(4*4)]

**algebra**

try again on the 1st one the slope formula does work

**physics**

the frictional force is ... 5 * 9.8 * .4

**Physics: Centre of Mass**

(4 * 4) + (8 * 5) > 7 * 5 ... so the CM is > 0 [4*(4-x)]+[5*(8-x)]-[7*(5+x)] = 0

**Math**

Tom has a 40 km head start ... 80 km/h * .5 h Cindy is catching up at 20 km/h ... 100 km/h - 80 km/h

**Physics**

the velocity is the vector sum of the horizontal and vertical components horizontal ... 88 m / 3.8 s vertical ... time up equals time down ... (3.8 s / 2) * 9.8 m/s^2 the max height is half the initial vertical component, multiplied by half the flight time

**Math**

distributing the 10 ... 40x + 30 - 9x

**Math**

undefined slope means the line is vertical the equation is of the form ... x = ?

**Physics**

a = v^2 / r r = v^2 / a = (54 m/s)^2 / 90 m/s^2

**Physics**

the object is moving at 20 m/s when the force is removed, the object will be decelerated to a stop (over some distance) by friction find the frictional force (m * g * .2) find the deceleration ... a = f / m find the stopping time ... t = v / a = 20 / a find the stopping ...

**pre-calc.**

100 = 10^2 10 = 10^1 logarithms are exponents -- powers of some base regardless of the base, the logarithm of 100 will always be twice the logarithm of 10

**Pre-Calc**

the values for sine and cosine are limited to the range ±1

**physics**

h = 1/2 g t^2 40 = 1/2 * 9.8 * t^2

**Physics**

gravity follows an inverse square relation two radii above the surface is three times the distance from the center (of mass) to the surface so the force would be ... g / (3^2)

**physics**

Pi * Vi / Ti = Pf * Vf / Tf the T is absolute (Kelvin) temperature

**physics**

you're adding two vectors 2^2 + 4^2 = s^2

**Physics**

need the drawing for a solution or, at least, more data

**Physics**

(b) f = m a ... a = f / m = 900 / 1800 a = .5 m/s^2 so it takes 40 s to stop ... 20 / .5 ave velocity is ... (20 + 0) / 2 distance = v * t

**Algebra**

.12 x + .10(7500 - x) = 890 .02x + 750 = 890

**Science Psysics**

the gravitational potential energy at the top of the ramp becomes kinetic energy at the bottom of the ramp (minus the work done by friction) m g h - f d = 1/2 m v^2 [6 * 9.8 * 3.5 sin(31º)] - (17 * 35.) = 1/2 * 6 * v^2

**Algebra 2**

x^2 - 8x + 14 = 0 use the quadratic formula to find x x = {8±?[64-(4 * 1 * -14)]} / (2 * 1)

**Algebra 2**

use the quadratic formula to find the value(s) of x

**physics**

momentum is conserved (1200 * 14) + (2000 * 25) = ... (1200 + 2000) * v

**Chemistry**

8 half-lives 625 * (1/2)^8

**Chemistry**

3 half-lives m * (1/2)^3 = 6

**Chemistry**

2 days (48 hr) is 8 half-lives 10.0 * (1/2)^8

**Chemistry**

5 / 20 = 1/4 = (1/2)^2 2 half-lives

**Algebra 2**

3 half-lives 345 * 1/2 * 1/2 * 1/2

**Need help with math**

people who own both (b) will be counted in both groups (laptop owners and desktop owners) when you count all of the households, the "both" group is only counted once 130 + 30 + 50 + b = 250

**Mathematics**

the area is side times altitude 30 * 15 = 25 * x

**Math**

8 oz per cup

**Science**

switching the electrical polarity also switches the magnetic polarity

**Science 7**

switching the wires changes the magnetic polarity of the coil

**algebra 2**

3000 = 2000 [1 + (.038 / 2)]^(2t) ... t is the number of years 1.5 = 1.019^(2t) log(1.5) = 2t * log(1.019)