algebra
4y^2*4x^2=14xy^4
Pre-Algebra
to solve for y in terms of y just set the equation equal to y. Then divide everything by the coefficiant of y. #1) 2x+7=y (already correct) #2) x-(2/3)y=3 x-3=(2/3)y (move y by itself) (x-3)/(2/3)=y (divide by 2/3) -->(3x-9)/2=y (simplify)
calculus
Thanks I get it now. I just couldn't figure out why they got 1000/3 and I got 8/0.024. I don't know why I didn't see that, just simple algebra.
calculus
I am reposting this because I still don't understand it. I need help with this problem. this is what I got so far: P(x)=12x-(x^2/500)-680-4x-0.01x^2 P'(x)=12-0.004x-4-0.02x P'(x)= -0.024x-8 x=8/0.024 My book says x=8/0.024 which somehow become 1000/3. They are the ...
calculus
I need help with this problem. this is what I got so far: P(x)=12x-(x^2/500)-680-4x-0.01x^2 P'(x)=12-0.004x-4-0.02x P'(x)= -0.024x-8 x=8/0.024 My book says x=8/0.024 which somehow become 1000/3. They are the same when solved but how did they come up with 1000/3?
9th grade Math
-8= (y/4) so multiply both sides by 4. On the right side the 4's will cancel and on the left it will be -32. -8 = (y/4) -8*4 = (y/4)*4 -32 = y Hint: Substitue your answer back into the original equation to check your work. So in this case check, does (-32/4) equal -8? Yes!
Calculus
how did you get the slope of the two lines? I get everything else though.
Calculus
Find an equation of the line through the point (3,5) that cuts off the least area from the first quadrant. How do I solve? I am stuck. The only thing I can come with is this: y-5=m(x-3) How to use this I don't know.
calculus
thanks!
calculus
V(h) = pie/3(R^2h-h^3) take the derivative with respect to h. using the chain rule I got: V'(h) = pie/3(2Rh+R^2-3h^2) but this is not the correct answer. what did I do wrong?
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