Tuesday
December 10, 2013

# Posts by physics

Total # Posts: 358

physics (geometry bit)
not for me =[ look... h t t p : / /i m g1 3 2 . i ma g e s h a c k. u s / i m g1 3 2 / 9 1 3 7 /c a p tu r e t q i. j p g could you try image shack upload (link below) I don't know why it wouldn't let me see it i captured the screen when i clicked on the link it's ...

physics (geometry bit)

physics (geometry bit)

physics
i have a question in my book centripetal acceleration = r^-1 v^2 ok I agree but in my book acceelration is labeled as a vector but yet the velocity is not... Why?

physics
thanks for the help earlier just got a question I'm taking AP Physics B this year does that mean next year I would Take AP Physics C??? I don't know if the material in C convers the same material plus the additional calculus material or what??? Could I take AP Calculus...

physics
I just would like to make sure of something an object experiances a drag force when it travels through a medium like air or water... so dosen't every thing experience a drag force that is in motion because its moving through air?? So like if a person was walking do they ex...

physics
also I was always told to use this equation when the velocity is small through the medium Fd = -bv were this is just a proportion also that other formula that is suppose to be used when there is a high velocity Fd = 2^-1 p v^2 A Cd v Ok what is exactly meant by high and low ve...

physics
so I got a question about projectile motion take the example of shooting of a plastic air rocket into the air and asked to predict its landing point and how high it goes... ok I know how to do this... the thing is now were not neglecting air resistence and I don't know wha...

physics
I don't see how this relationship works Fn sin theta = r^-1 m v^2 or more like why it works??? my text goes on to prove tan theta = (rg)^-1 v^2 which I understand how to rearange I just don't get where the first relationship comes from Fn sin theta = r^-1 m v^2 i get i...

physics
ok if a car is going around a bank curve my book is telling me there is an ideal spead were no friction is required at all for it to complete the banked turn it says that this occurs when the horizontal component of the normal force is equal to the radial acceleration why?

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