Pre-Cal.
The question is how you go from x^2+4, to -2i.
Pre-Cal.
use the complex zeros to give fully factored form, the first factor needs a x in it : (-3) (-2i)(x+2i)
Pre-Cal.
How does this go from x^2+ to 2i, explain.
Pre-Cal.
where is the typo in which opening line? And I believe I used the wrong symbol for the factored function it's suppose to be a plus sign over a __ but I can't figure how to type this. and maybe that's what is giving us the answer you have given me. Could that be it?...
Pre-Cal.
f(x)=x^3-3x^2+x-12 =x^2(x-3)+4(x-3) =x^2+4) (x-3) so if f(x) = 0 at x = 3,+/- 2i. what is the f(x) factored form
Pre-Cal.
find the domain, range and the asymptote(s), of each function on the same coordinates plane for this equation... f(x)= 3+ lnx and graph them.
Pre-Cal.
find all the zeros of f(x)=x3-3x2+4x-12
Pre-Cal.
write f(x) in factored form.
Pre-Cal
Solve the following logarithmic equation. Exact words only: log 3(x+4) = 2+log3(x-20) the 3 in the part of log (3)should be lower just didn't know how to type it in here
Pre-Cal.
find the inverse of the following function. Find the domain, range,and asymptotes of each function. Graph both functions on the same coordinate plane. f(x)=3+lnx
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