oin AC and DE. Triangles AFE and DFC are similar. so AF/FC = AE/CD = AE/EB also AE + EB = AB ie AE +234AE =AB so AE/AB =1/235 so AF/FC = 1/235 FC = 235 AF now, AC = AF +FC = 236AF ie AC/AF = 236/1 ie AC : AF = 236 : 1
February 28, 2013
There exists only one solution and the whole challenge is in proving the fact that there does not exist any other solution. So here we go... Let's add both these expressions. Then as per the problem, 7(a^2+b^2)=c^2+d^2 Clearly LHS is a multiple of 7 and so RHS must be a ...
February 26, 2013