Wednesday

August 24, 2016
Total # Posts: 13

**Ms. Sue can you answer this please**

just plug it in. 6t^2+110t+3000=6000, thus 6t^2+110t-3000=0 and we factor but first we divide by 2. Thus we get the equation 2(3t+100)(t-15)=0. FYI if you did not learn what just happened please study your algebra book. Anyway, x= -100/3 or 15, but it cannot be negative so t=...
*November 17, 2012*

**Please Help! Quadratic Eqautions**

just plug it in. 6t^2+110t+3000=6000, thus 6t^2+110t-3000=0 and we factor but first we divide by 2. Thus we get the equation 2(3t+100)(t-15)=0. FYI if you did not learn what just happened please study your algebra book. Anyway, x= -100/3 or 15, but it cannot be negative so t=...
*November 17, 2012*

**Please Help! Quadratic Eqautions**

You can go Damon's way, or the graphing way/ comnpleting the square binomial way or you can go quadratic
*November 17, 2012*

**Math**

use area of circle formula. a=pi r^2 c=pi d Thus, we need to plug in numbers. 1385/pi = r^2. We take the square root of that to get the radius.Then, we can double that radius and multiply by pi to get the circumference. the formula would be 2pi sqrt1385/sqrt pi
*November 16, 2012*

**math**

its about 2.7 or so.... its the sum of the infinite series 1+ 1/1 +1/1*2 + 1/1*2*3 + 1/1*2*3*4....
*November 16, 2012*

**English - Ms. Sue**

D yes. remember its not present, nor past, nor future, but continual. (whatever, its D)
*November 16, 2012*

**Math**

try guessing. 28*2 =56. 56 is between 50 and 60. so its 56.
*November 16, 2012*

**English - Ms. Sue**

it probably would be B.."in 1960, american scientists raiseda serious concern" vs "in 1960, american scientists have raised a serious concern"
*November 16, 2012*

**English - Ms. Sue**

raised...past tense remember
*November 16, 2012*

**does anyone know probability????**

=6, and arrange the rest of the digits appropriately...i think...
*November 16, 2012*

**does anyone know probability????**

use prob, last digit has to be either 2,4, or 8 to be divisible by 4, and the tens digit for 2 will be either 3 or 7. for 4, it has to be either 2 or 8, and for 8, it will be either 2 or 4. 3*2
*November 16, 2012*

**Calculus II**

Use L'Hospital's rule (twice)
*November 16, 2012*

**HELP !!! Algebra 2**

first things first...calm down. yes, its extremely hard. but we go simple approach. y-x=2 implies y=x+2.we substitute that in the first equation to get x+2 = x^2+5x-3 =x^2+4x-5=0. We factor to get (x-1)(x+5)=0. Thus, x=1, or -5. PLugging in, we get y=-3,3. Thus, (1,3)(-5,-3) ...
*November 16, 2012*

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