Wednesday

August 27, 2014

August 27, 2014

Total # Posts: 39

**math.**

Distance covered in 4 hrs=4y Return distance=2x4y=8y and speed=5y Hence time of return trip=8y/5y=1.6hr Halt=1hr Total time=4+1+1.6=6.6hrs
*July 17, 2013*

**math**

Relative velocity=45+55=100mph Time taken to cover the total distance=150/100=1.5 hr i.e. 1hr 30min Meeting time is 2:15+1:30=3:45pm
*July 17, 2013*

**math**

1hr10min=1+10/60=1+1/6=7/6hr Distance=48x7/6=56miles
*July 17, 2013*

**math**

Total money=x. Spent in I store=(x/2)+20 Remaining amt=x-[(x/2)+20]=(x/2)-20 Spent in II store=1/2[(x/2)-20]+20 =(x/4)+10 Total expenditure is x x=(x/2)+20+(x/4)+10 Or x=(3x/4)+30 Or x-3x/4=30 x/4=30 or x=120. Check: Spent in I store =60+20=80. Remaining=40. Spent in II store=...
*July 17, 2013*

**algebra**

Please read second expression as 3(8x^2+14x+5)
*July 17, 2013*

**algebra**

24x^2+42x+15=3(8x^2+14+5) =3(8x^2+10x+4x+5) 3[2x(4x+5)+1(4x+5)] =3(4x+5)(2x+1)
*July 17, 2013*

**algebra**

Sorry. I wanted it to be (1-6x)^3-3x6x(1-6x)
*July 17, 2013*

**algebra**

-216x^3+1=1^3-(6x)^3 =(1-x)^3-3x(1-x)
*July 17, 2013*

**math**

Time for going upwqards=7/2=3.5 hrs Time for coming back=7/3.5=2 hrs Total 3.5+2=5.5 i.e. 5 1/2 hrs
*July 16, 2013*

**math**

In 1.75 hrs it fills 100% In 1 hr it will fill 100/1.75=57.14%
*July 16, 2013*

**math**

(-16)^-2/3=- 1/(16)^2/3=-1/(16^2)^1/3 =-1/256^1/3=-1/6.35=-0.157
*July 16, 2013*

**algebra**

(300)^1/2 /6^1/2=(300/6)^1/2 =50^1/2=7.07
*July 16, 2013*

**Math Ratios**

Force is inversely proportional to square of distance between bodies, hence F/3.75x10^-5=18^2/52^2 F=(18^2x3.75x10^-5)/52^2 =0.46x10^-5 dynes
*July 16, 2013*

**math**

PS: There is slight typo. Please readt first line as 'Kath is' and third line as 2x+10.
*July 15, 2013*

**math**

If the number is x, then 3x-8 is=or greater than 2x. Agnus has x bones and Ignatz has x+5. Then x+x+5=27 or 2x=27-5=22 Or x=11. Ignatz has 11+5=16. Kathy mis x and John is x+10 Then x+x+10 is greater than 60 Or 2x+10is greater than 60 Or 2x 10 is greater than 50 Or x is ...
*July 15, 2013*

**MATH**

If cos^-1x=A then cosA=x and if (cosx)^-1=A then A=1/cosx
*July 15, 2013*

**math**

If house costs x and lot costs y then x+y=86000, and x=6y+2000 or x-6y=2000. Subtracting second eq. from first we get 6y+y=86000-2000 or 7y=84000 or y=12000. Thus lot costs $12000 House costs 86000-12000=$74000.
*July 15, 2013*

**algebra**

No. of $5=bills a, $10 bill=b and $20 bill=c Then a+b+c=35 5a+10b+20c=370, and b+c=a+7. Substituting value of b+c in first eq., a+(a+7)=35 or 2a=28 or a=14 and b+c=35-14=21. Substituting value of a in second eq., 14x5+10b+20c=370 or 10b+20c=370-70 Or 10b+20c=300 or b+2c=30 ...
*July 15, 2013*

**Math**

PS: s=11.47 which has appeared as 121.47 at one place in 4th line.
*July 15, 2013*

**Math**

v=u-gt or 0=15-9.81t since final velocity is 0 and ball is going against gravity. Thus t=1.53 sec. s=ut-.5gt^2=15-.5x9.81x(1.53)^2 s=22.95-11.48=121.47 which is the height the ball will go. From there it falls freely for a height of 11.47+1=12.47 ft. s=0xt+.5x9.81xt^2 or t=(12...
*July 15, 2013*

**algebra**

9.95x+11.5y=305.05 x+y=29 9.95x+9.95y=29*9.95 Or (11.50-9.95)y=305.05-288.55 1.55y=16.5 y=16.5/1.55=10.6, say 11 yellow shirts 29-11=18 white shirts 11*11.5+18*9.95=305.6 OK.
*July 15, 2013*

**algebra**

Lemon juice=x Oil=2x x+2x=3x=36
*July 15, 2013*

**maths**

If one train has a velocity of V km/h, the other one will have velocity V+5 km/h approaching the first train. Therefore Relative velocity will be V+V+5=2V+5 km/h. Distance travelled by them in 2 hrs is 340-30=310km which is =2(2V+5) Thus 4V+10=310 or 4V=300 hence V=75km/h and ...
*July 15, 2013*

**physics**

v=u+ft or 30=10+2t t=(30-20)/2=10 secs.
*July 15, 2013*

**Algebra**

Yes please. 10 cubed is 1000 and cuberoot of q^36=q^(36/3)=q^12
*July 15, 2013*

**algebra**

Please see your third line: It should be 4y-3y=20-5 or y=15, by subtracting first equation from second. Now x+3*15=5 Or x=5-45=-40. Check:-40+4*15=20 by putting values in second equation. This -40=15-60=-40 OK.
*July 15, 2013*

**math**

Let present age of Kristen be x and of Daniel be y.Then after 1 year, x+1=4(y+1)or x-4y=3.....Eq.1 After 10 yrs from then, ages will be (x+1)+10=2[(y+1)+10] Or x+11=2y+22 Or x-2y=11 .....Eq.2. Subtract eq. 1 from eq.2 and solve. We get y=4 and x=19. Check: After 1 year Kristen...
*July 14, 2013*

**physics**

v=u+at or 220/4=200/2+a*1 55=50+a or a=5m/s^2 Again, v=55+5*1=60m/sec at the start of 7th second.
*July 14, 2013*

**math**

Let the integers be x and x/4.Then x/4+12=x-3 or x+48=4x-12 by multiplying both sides by 4. Or -3x=-20-48 or x=20 which is the larger integer. Smaller one is then 20/4=5. Check:5+12=17=20-3 OK.
*July 14, 2013*

**math**

Let it be x yrs ago, when Lisa was 15-x and her father was 40-x. Then- 40-x=6(15-x) or 40-x=90-6x Or 6x-x=90-40 or 5x=50 thus x=5. Let Bob be x yrs and Joel be 3x. Then (x+7)+(3x+7)=58 or 4x+14=85 Or 4x=44 hence x=11. Thus Bob is 11 and Joel is 33. After 7 yrs Bob willbe 18 ...
*July 14, 2013*

**maths**

Prove that max & min values of asinx+bcosx are = +/- (a^2+b^2)^1/2
*July 12, 2013*

**Geometry**

Square has all sides equal hence 2x-5=x+8 or 2x-x=8+5 (by subtracting x and adding 5 on both sides) Thus x=13 inches. Check: 2x13-5=8+13 or 26-5=21.
*July 12, 2013*

**physics**

Weight is mass m times acceleration due to gravity g, which is given by g=GMm/R^2 where M and R are mass & radius of Earth and G is Universal Gravitational Constant. For new planet, g`=G(0.1Mm/(R/2)^2 =0.1GMm/R^2/4 =GMm(0.1x4)/R^2=0.4GMm/R^2 Hence g/g`=0.4, which means the ...
*July 12, 2013*

**maths**

Find max and min values of y=sinx sin2x
*July 11, 2013*

**physics**

Components of a force P due North-West acting at an angle A from North will be PcosA and PsinA in North and West directions respectively and should be equal in magnitude to the force acting on the object. Thus PcosA=83.4 and PsinA=47.2. Therefore tanA=47.2/83.4 =0.566 and A=...
*June 30, 2013*

**physics**

Heat released by 0.5 kg silver=heat gained by 1 kg water upto final temp T. Or 0.5(2.4x100)(150-T)=1(4.18x1000)(T-5) Or 1.2(150-T)=41.8(T-5) Or 180-1.2T=41.8T-209 Or 43T=389 Or T=9.05 deg Celsius
*January 12, 2013*

**Physics**

t^2=2x3.14x0.47/a Or, a=6.28x0.47/1.43^2=0.43 m/sec^2
*November 3, 2012*

**math**

. A boat is travelling on a bearing of 25° east of north at a speed of 5 knots (a knot is 1.852 km/h). After travelling for 3 hours, the boat heading is changed to 180° and it travels for a further 2 hours at 5 knots. What is the boat’s bearing from its original ...
*October 18, 2011*

**physics**

what happend 2 ur mobile? i was trying 2 call u but i got this msg: welcome 2 D jungle network,D monkey u r tring 2 call is on tree plz try later.
*July 17, 2008*

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