math
use subsitution system to solve 4x+5y=21 Y=3x-11
CHEMISTRY: URGENT DRBob222
I thought it was similar so I wrote... x + y = 30cm^3 x + 2y = 61.5cm^3 i.e 2x + 2y =60cm^3 x + 2y = 61.5cm^3 therefore x= -1.5cm^3(volume of methane) and y= {61.5-(-1.5)}/2= 31.5cm^3(volume of ethane) However my teacher said the volume i got for ethane is wrong, because my se...
CHEMISTRY: URGENT
Ok I understand...:-)
CHEMISTRY: URGENT
Ok I understand...:-)
CHEMISTRY: URGENT
****There's something you should know though...I wrote the reaction like how you did. (CH4+ C2H6) + 2O2 ==> CO2 + H2O and my teacher said H2O is not part of the residual gases. She said H2O should be replaced with O2. (CH4+ C2H6) + 2O2 ==> CO2 + O2 ****
CHEMISTRY: URGENT
Lol when you explain it. Not when my teacher teaches me, I never understand a word she says. Anyways thanks alot for staying up to help me. There's something yo should know though...I wrote the reaction like how you did. CH4 + 2O2 ==> CO2 + H2O and my teacher said H2O i...
CHEMISTRY: URGENT
Yes the answer to the first question was correct, that's what my teacher got too... but she did it like this. Either way its correct. x + y = 24cm^3 x + 2y = 32cm^3 then 32 - 2y + y = 24cm^3 32-y = 24cm^3 y= 8cm^3(volume of ethene) x + 8 = 24cm^3 x= 16cm^3(volume of methane)
CHEMISTRY: URGENT
If yes...Here it is... 24cm^3 of a mixture of methane and ethane were exploded with 90cm^3 of oxygen. After cooling to RTP the volume of gases was noted and it decreased by 32cm^3 when treated with KOH. Calculate the composition of the mixture.
CHEMISTRY: URGENT
The one from last week?
CHEMISTRY: URGENT
ok thanks
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