Sunday

August 28, 2016
Total # Posts: 13

**math**

If 2100 square centimeters of material is available to make a box with a square base and an open top, find the largest possible volume of the box. Volume = cubic centimeters.
*September 7, 2010*

**math**

i need to find when the function increases or decreases, this is the derivative of the function (10 − 3x)/(2 ¡î5 − x) but how do you solve the function when x is zero?
*September 7, 2010*

**calculus**

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=2–x2. What are the dimensions of such a rectangle with the greatest possible area? I got Width = 4/1.732 but i don't know why its wrong I got Height = 4/3 which is right
*September 7, 2010*

**calculus**

I put -1.454 for x2 but when I put -2.299 for x3 I got it wrong
*September 7, 2010*

**calculus**

Use Newton's method to approximate a root of the equation 3sin(x)=x as follows. Let x1=1 be the initial approximation. The second approximation x2 is and the third approximation x3 is
*September 7, 2010*

**calculus**

i got it wrong
*September 7, 2010*

**calculus**

If 2100 square centimeters of material is available to make a box with a square base and an open top, find the largest possible volume of the box. Volume = cubic centimeters.
*September 7, 2010*

**math**

The altitude of a triangle is increasing at a rate of 1500 centimeters/minute while the area of the triangle is increasing at a rate of 1000 square centimeters/minute. At what rate is the base of the triangle changing when the altitude is 10000 centimeters and the area is ...
*August 27, 2010*

**math**

show that the equation 2x-1-sinx=0 has exactly one real root. sin x = 2x-1 2x = sin x - 1 range of sin x is -1 to + 1 but how do you know that 2x is between -2 and 0 and so x is between -1 and 0
*August 25, 2010*

**math**

4.2 18. show that the equation 2x-1-sinx=0 has exactly one real root.
*August 24, 2010*

**math**

nvm i got the answer
*August 21, 2010*

**math**

Find the equation of the tangent line to the curve y=6tanx at the point (pi/4,6). The equation of this tangent line can be written in the form y=mx+b where m is: and where b is:
*August 21, 2010*

**math**

Find the equation of the tangent line to the curve y=5xcosx at the point (pi,–5pi). The equation of this tangent line can be written in the form y=mx+b where m= and b=
*August 20, 2010*

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