Wednesday
December 11, 2013

# Posts by kristin

Total # Posts: 163

thank you

like why would Tacitus put Augustus in a bad line? What changed about Rome because of Augustus?

Explain the Difference during the Roman Empire on what Augustus says about himself and what Tacitus says about Augustus

Chemistry
The standard enthalpies of formation of ions in aqueous solutions are obtained by arbitrarily assigning a value of zero to H ions;that is, delta H(f) [H+(aq)]=0 A.for this reaction: calculate delta H(f) for the Cl- ions. HCl(g) ==H2O==>H+(aq)+Cl-(aq) delta H= -74.9 kJ/mol (...

multimeter
When an AC voltage is being measured across a 15 Ù resistor which is carrying a current of 12 amps, the selector switch should be set to the AC voltage position of

physic
A 0.20 kg ice cube at 0.0° C has sufficient heat added to it to cause total melting, and the resulting water is heated to70deg.Cel. > How much heat is added? (For water Lf=334kj/kg > andLv=2257kj/kg >

grammar
The informant, who will not be named, called in a tip last night informing police officers about an attempted robbery. The cold, dry, and ruthless wind lashed at their bare hands and faces. Are these sentences grammatically correct?

Schindler's List Essay
Directions: We recently watched the movie "Schindler's List," and now we have to write an essay. So I chose to write it based on this question: What are the three most important reasons for Schindler's success in saving 1,100 people? This assignment is suppos...

Chemistry
Ok, so for the first one I got mol of HCl=4.92x10^-4 and so [OH-] is 4.92x10^-4/.020L = .0246 mol/L. Is that correct? And then from there I have the [OH-] in NaOH to be (.0125)(.020L) = 2.5x10^-4 [OH-] in Ca(OH)2 is .0246-2.5x10^-4 = .02435 [Ca2+] then is .012175 Are my calcul...

Chemistry
I'm trying to find the solubility of Ca(OH)2 in .0125 mol/L aqueous NaOH. Here is my data: Vol of solution used per titration: 20mL Conc of HCl: .1201 mol/L Average Titre: 4.71 I need to calculte: 1. the TOTAL [OH-] in the saturated solution of Ca(OH)2 in NaOH 2. the [OH-]...

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