Parabola
How do I put this parabola in standard form? Could someone show how they would put it in this form: (x - h)2 = 4p(y - k) 1. 4x^2+24x+128y-988=0 Please help! I'm lost.
Parabola
3y^2+24y+72x-96=0 Can anyone put this in standard form: (y - k)2 = 4p(x - h) All help is greatly appreciated! :)
Pecalculs
Thank you again! ^o^
Pecalculs
Sorry: Precalculus! :P
Pecalculs
Can anyone put this parabola into this standard form: x-h = a(y-k)^2 x^2-12x-48y-372=0 ? Please help!
Parabolas in standard form!
WOW! Thank you so much! you made more sense than my teacher! :D
Parabolas in standard form!
Can you solve this one?: x^2-12x-48y-372=0 & I made a mistake one the second one!! Its actually: x^2+14x+44y+313=0 !!
Parabolas in standard form!
Hello, I am having the worst time trying to solve these parabolas and putting them into x-h = a(y-k)^2 form. :( There are two problems that i keep doing something wrong. could someone solve them so I can have a set up for the rest of my problems? :) 3y^2+6y+108x-969=0 and x^2+...
Ellipse equation?
Thank you, @Steve ! Would you happen to know how to find the Foci for this equation?!?! :)
Ellipse equation?
(x-2)^2 / 49 + (y+1)^2 / 25 = 1 a.) what are the vertices? b.) What are the major and minor axises? I always have troubling understanding how to find these. :( Any help is greatly appreciated!
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