Friday

November 27, 2015
Total # Posts: 1,545

**english**

I can think of a four letter word that begins with f. It would work even better if the first sentence were "The weather will be _____ today"
*October 15, 2009*

**math**

Given what?
*October 14, 2009*

**pre-calculus**

That's solvable easily with calculus, not sure whether you're supposed to be using it given your heading: C'(x) = 4.9(2)x - 617 = 9.8x -617.4 at its minimum, 9.8x = 617.4
*October 14, 2009*

**geometry**

Both have four sides. Both have pairs of adjacent sides equal. A kite's opposite sides don't have to be equal, but a rhombus must have all sides equal.
*October 14, 2009*

**geometry**

a) So you're looking at a Right Angled Triangle (RAT) with the two short sides being 4 and 25. What does Pythagoras say about the other side, which must be the hypotenuse? b) This is the same question, except with 6 on the shortest side instead of 4.
*October 14, 2009*

**Programming**

Glad I could help, especially in a case like yours where you clearly could do the job yourself, but just hit a snag. Good luck with it!
*October 14, 2009*

**Programming**

Given the short deadline, and that I'll be away for a while, I hacked nastily into your code, to produce something that runs all the way through, I think. I want to emphasise just how ugly this is, and that it needs a lot of work to be a worthy project! But it runs, and if...
*October 14, 2009*

**Programming**

I'll be away until tonight. How long do you have for this project?
*October 14, 2009*

**Programming**

OK, doing what I said last is really easy. Just move the two displays abve the loop, and actually draw the board instead of just returning it, like: myGame.getPrompt(); myGame.getRules(); while(myGame.winner() == 0 && !myGame.placeMarker()) { System.out.println(myGame....
*October 14, 2009*

**Programming**

I think you want a String rather than a char. Here's what I did: 1. I made a little batch file to recompile and rerun, containing javac TicTacToe.java jar cvf TicTacToe.jar TicTacToe.class javac -cp .\TicTacToe.jar Lab2.java java -classpath . Lab2 I don't know whether ...
*October 14, 2009*

**Programming**

Just home and had a quick look. My two immediate thoughts: 1. You need to write getCurrentPlayer() in TicTacToe so that you can get the whole thing to start running, from where you can get a handle on what it is doing. 2. I still don't think the instructions I/O should be ...
*October 14, 2009*

**Programming**

Nice to see you back, Tim. I'll be away from the forum until tonight, but somebody else may help in the meantime. To help them help you, you could post your thinking, given your current code. Where are you stuck? What doesn't seem to be working that you think should be...
*October 14, 2009*

**Chemistry**

After 0.6523 g of is heated, the residue has a mass of 0.3423 g. Calculate the % H2O in the hydrate.
*October 13, 2009*

**math**

two equations : n+d=42 .05n+.10d=3.85 or 5n+10d=385
*October 13, 2009*

**3rd grade**

if you round the number to the tens place, it is 460 if you round the number to the hundreds, it is 500 could the number be 468 and why
*October 13, 2009*

**Math**

a. (13-2)/32 = b. @1000 it had 11/32. @20000 it had 5/32. So after 19,000 it lost 6/32. It needs to lose another 3/32 to be "worn out". You should be able to see the number of miles from that.
*October 13, 2009*

**math**

Oh. If it's any comfort, I have no idea how writing sentences embodying equations could be proven, either.
*October 13, 2009*

**math**

The question wants you to figure out what number replaces X. 7 = x + 5 7 = ? + 5. What number replaces x, or the question-mark? You're going to write: x = (some digit, which is your answer) Proving is easy. Just write 7 = x + 5 down again, but this time replacing x with ...
*October 13, 2009*

**math**

"maximum: 8, range: 6" gives you your minimum number, so pencil that in, and 8 at the other end of course to make your maximum. Now, if you know what mode and median mean, you should be ready to write in some 6s, and spread about the same number of lower digits.
*October 13, 2009*

**math**

Well, we're going to need three lots of some unknown number plus 4. Let the three be bags. Since we're near Halloween, let's say some unknown number of pieces of candy get divided equally into 3 bags. Then let's say somebody adds 4 pieces to each bag. Can you ...
*October 13, 2009*

**Math- fractions and decimals**

"62 and a half" is 62.5, or 62 1/2, or 125/2. That's all fine. But you talked about a hundred chart. I wonder whether you mean what 62.5 is as a fraction of a hundred, which is the same as asking what 62.5% is as a fraction. Does your 100 chat show 50 as being 1/...
*October 13, 2009*

**Algebra**

I'm totally with you on y=8, but the best way to check your answer is to substitute the value back in. Now try y=2/3: Is |2/3+3| + 5 = 2(2/3) ? Is 11/3 + 15/3 = 4/3 ? I think you took a wrong turn at: "Now, the two equations are 3=y-5 and 3y+3=5." You can't ...
*October 13, 2009*

**Algebra**

The perimeter is two lengths + two widths, and that has to be more than 70. 2L + 2W > 70 We know that the length is 19, so 2L = 38. 2W + 38 > 70 2W > 70 - 38 Now pick a width that makes that true. There are lots of them to choose from: a million will do. :-)
*October 13, 2009*

**Programming**

OK! I suggest when you get your client ready you start a new question to keep it on the front page, since I don't think anybody looks beyond the front page much. I didn't really expect to see a response down here, but I was curious so I checked.
*October 13, 2009*

**Programming**

Tim, this forum doesn't seem to allow indenting; that's why your code didn't show. You can paste your code if you remove the leading spaces. I did get your code. But, given that, I'm not quite clear what you want to know. By "fill in the blank", do ...
*October 13, 2009*

**Computer Science Java**

A Boolean variable is a variable, like an int or a string, but whose value is either "true" or "false". Try this little lump of code, and vary d1 and d2 values, to see the effect: int d1 = 1 int d2 = 1 boolean snakeeyes; boolean doubles; boolean boxcars; ...
*October 13, 2009*

**Math Analysis**

4. "I got the square root of 7x. Is this right?" Nearly, but not quite. Careful with your sqrt signs. f(x)=sqrt(x) g(x)=6sqrt(x) f(x)+g(x) = sqrt(x) + 6 sqrt(x) = 7 sqrt(x), not sqrt(7x) 16. This is much easier on paper! Consider your constants. You have sqrt(2) on ...
*October 12, 2009*

**math anaylsis**

g takes x to x-3. That is, start with x, then g(x) will be three less. 5 -> 2, 11-> 8, 1 -> -2. Right? f squares x, so f(5)=25. Similarly, 3-> 9, 8 -> 64, and so on. f(g(x)) just means "do g on x, then do f on the result". If you start with x=5, then g...
*October 12, 2009*

**programming**

I'm also not clear what is being asked, exactly, but at least it's not just a cut-and-paste question. Steve, what exactly do you need to do, and within what terms? Do you need to create a flowchart modelling currency conversion logic using some specific software, or ...
*October 11, 2009*

**Physics**

A passenger on a bus moving with uniform velocity lurches forward when the bus stops suddenly. Explain? I do not understand this
*October 11, 2009*

**Algebra**

If it depends on something else, it's dependent. If it doesn't depend on something else, it's independent. Does the time of day depend on the air temperature? Does the air temperature depend on the time of day?
*October 10, 2009*

**math**

Do read the earlier two first. At the end of hour five, which we'll call t5, speed @t5 = 100 km/h It's been accelerating at 3km/h, so at 4 hours speed @t4 = 100 - 3 = 97 km/s and at 3 hours speed @t3 = 97 - 3 = 94 km/s You can work it back from there.
*October 10, 2009*

**math**

This is like the car problem. At the start, t0, the stone has a speed of zero. t0 = 0 m/s The acceleration is (10 meters per second) per second, so after one second the speed is 10 m/s. t1 = 10m/s After another second, we add on another 10m/s to the speed t2 = 20 m/s At the ...
*October 10, 2009*

**math - corr**

I used a shorthand that was wrong in this question, and it might confuse you. When I say t0 = 103 m/s what I should have said, to be clear, was speed at t0 = 103 m/s and so on.
*October 10, 2009*

**math**

We start counting when it's moving 103m/s. (And incidentally, that's pretty fast for a car. Formula 1, maybe?) Each second after that, it moves 1m/s faster than it was before. So if we call time by seconds, as we often do in these things, we call the start, after zero ...
*October 10, 2009*

**ap calc**

Draw the pool as a rectangle. Now draw a rectangle around that, such that each side is equally distant from the sides of the pool. This represents the sidewalk around the pool. The area of the pool is 12 * 18 = 216 sq.ft. If the sidewalk were 3 feet wide everywhere, the width ...
*October 10, 2009*

**Algebra - oops typo**

b^2 - 4ac 1 - (4)(2)(-1)
*October 10, 2009*

**Algebra**

Doublecheck the expression within the square root, and watch your signs. b^2 - 4ac 1 - (4)(1)(-1)
*October 10, 2009*

**Finance. **

Start with 10, finish with 20 after 1 year you have 10*x after 2 years 10*x*x after 3 years 10*x*x*x 10 x^3 = 20 x^3 = 2
*October 10, 2009*

**Finance. **

I just answered a very similar question from Kim right below. The method to solve this is the same, but you can make up your own numbers: say, 10,000 at the start and 20,000 at the end.
*October 10, 2009*

**finance**

I like this question :-) Let's assume interest is compounded annually. After one year, the value will be 10,477.03 * x, where x is 1 + (interest rate implicitly divided by 100). After two years, it will be 10,477.03 * x * x, because we increase it by the same percent again...
*October 10, 2009*

**Algebra**

Well done! You got it right. But I think you may have missed a turn in the simplification. The simplification is largely a matter of taste, but also laziness - the less you have to write to use your result in the next stage of a problem, the better :-) You started with: (10...
*October 10, 2009*

**Programming & Algorithm**

I'm not exactly sure what (1) is asking. General considerations? An exemplar? Anyway, a stack has only two operations: push something in; pop something out. You will need space in which to store the items on the stack. Start with the items. What data types will you be ...
*October 10, 2009*

**Maths**

Is this using current British coinage, or pre-decimalisation? There is a quite famous problem by Dudeney about this, but it uses old coinage - farthings and suchlike. The book "Amusements in Mathematics by Henry Ernest Dudeney" is available ibn Project Gutenberg, if ...
*October 10, 2009*

**math**

Magic, you need to post a new question, rather than follow on an existing thread. I'm not sure, but I think the question means that the _answer_ after subtracting 1 is 114. If so, then start by asking yourself what number leaves 114 when you subtract 1 from it. Got that? ...
*October 10, 2009*

**marketing**

Thanks for the kind words :-)
*October 10, 2009*

**marketing**

Look up what the 4 Ps are. Got that? OK. Now consider something _you_ bought recently. It's likely that it'll be easier to write about something large and unusual you bought, like a pair of skis, than something small and common, like a fizzy drink, though both will ...
*October 10, 2009*

**visual basic**

I just read your question again, and I now think that, given an input string, you want to find the first non-zero digit in it. Though again, I could be wrong. So if the input is "A046", you want "4", and if it's "0.0029x" you want "2"...
*October 9, 2009*

**visual basic**

Perhaps the most useful tip you can know in learning to program, though you won't find it in a book, is to ask for help, giving _all_ information about the problem, whether you think it's useful of not! :-) You've posted the problem code. This is good. You haven&#...
*October 9, 2009*

**System analysis**

The hardware vendor will say it's a software problem. The software company will call it a hardware problem. The department manager will have somewhere else to be. The sysadmin/BOFH will sigh and mutter "PEBKAC" as he walks past. The experienced project manager ...
*October 9, 2009*

**math**

This one's kind of pretty. I first thought we'd be into sin and trig country, but we don't have to. But you have to see it in a diagram. Draw lines for the lamppost and the woman, and a line from the top of the lamppost just over the woman to the ground. You should...
*October 9, 2009*

**Alg**

I don't think (2z)^(1/2)/4z^4 can be correct, since y has disappeared. Take it in steps, by distributing th power: (y^(1/4)*Z^4)^(-4/5) = (y^(1/4))^(-4/5)(*Z^4)^(-4/5) Now, what's the rule for raising powers? As for (3-2SQRT2)(SQRT6-5) I don't really get it to be ...
*October 9, 2009*

**Math**

You've done the hard part; you're almost there! You just lost sight of the simple bit. x = 2/(2a+1) we need to find a when x = 10 10 = 2/(2a+1) Now find a
*October 9, 2009*

**algebra**

y=mx+c m= -1/6 y=-(1/6)x+c The point (-6,9/7) must be on that line: use it to find c by plugging in x and y like 9/7=-(1/6)(-6)+c So what's c? So now we have the equation of the line, we need the value of the point on that line where x=12. Plug in 12 instead of x in the ...
*October 8, 2009*

**Physics check **

A person has a reasonable chance of surviving an automobile crash if the deceleration is no more than 30 "g's" (recall that g = 9.8 m/s2). Calculate the force, in N, on a 68 kg person accelerating at this rate. 30"g" x 9.8 294 ms^2 f=ma 294x68 =19,992N
*October 8, 2009*

**visual basic**

I didn't verify your code, but I see the general way to do it. Suppose you have user(1) = "vsu1"; password(1)="123456" user(2) = "jim"; password(2)="abcdef" now, after the swap above, you have user(1) = "jim"; password(1)=&...
*October 8, 2009*

**[math]**

You have the right idea, but watch your sign: 3x-2y=7 Subtract 3x from both sides: -2y = -3x + 7 Divide by -2 y = (3/2)x -7/2
*October 8, 2009*

**equations**

Sign dropped? Doesn't y+x=-5 rewrite as y=-x-5?
*October 8, 2009*

**algebra**

By solving it graphically, I presume the question means draw the graph, and read off the answer from the point where the lines cross. To do that, you need to draw each of the two lines. Start with the first one: y-x+4=0. You need to find two points on that line, then use your ...
*October 8, 2009*

**physics**

Aaach. In (a) I meant "The boat actually ends up at the point (0,-4) after 3 hours. " Sorry for the confusion.
*October 8, 2009*

**physics**

There are a couple of ways to consider this, and I'm probably mixing them, so check my sanity as well as my thinking! I'm not at all sure I've got this right. And draw a small sketch of the points; it makes a whole lot more sense that way. (a) Consider the harbor ...
*October 8, 2009*

**Math**

How do you convert C to F? Multiply by 9, divide by 5, then add 32. Multiply 1.1111111... by 9, you get ---- which is equivalent to (it may look nearly the same as, but it is the same) ---- Divide that by 5, to get ----- Now add 32.
*October 8, 2009*

**Math**

Um, possible typo there? If the cards are drawn _with_ replacement, the first card is back in the deck when the second is drawn, and the probability of the second being a diamond is again 13/52?
*October 7, 2009*

**math**

First, draw your triangle so you can see what you're doing. The short side, 12, will be opposite the small angle, 30. We know that the sin of an angle = opposite over hypotenuse. The angle is 30, and we can look up sin(30)=0.5. So opposite (which we know is 12) over ...
*October 7, 2009*

**math**

Consider the line tangent to y^2=4x. It has m = x^(-1/2). At 1,2, that's m=1, so y=x+1. The circles are tangent to this line, so a perpendicular through (1,2) joins their centres. That'll be y=-x+3. So to get our centres we're looking for two points with a distance...
*October 7, 2009*

**7th grade math**

The counting principle is oddly-named, since it mostly involves multiplying :-) It just means that if you can do the first thing x ways, and then in the next step you can do that y ways, then overall you can do the whole thing in x * y ways. Consider a two-digit PIN. How many ...
*October 7, 2009*

**math**

For a rectangle, you need to have sides A and B wide and long. Then you multiply A and B to get the 50 players. This is the same as asking how can 50 be factored into two factors (which don't have to be prime). Start with the prime factors. 50 = 5 * 10 = 2 * 5 * 5 Um. ...
*October 7, 2009*

**algebra 2**

An inverse just undoes what the original function did, so you can get it by doing the opposite of what the original functtion did, in reverse order. g(x) tells you: multiply by -6, then add 5. Its inverse will tell you: subtract 5, then divide by -6. Example: g(2) = 2*-6 + 5...
*October 7, 2009*

**maths**

I don't see a short-cut. Could this just be division practice? I make it two such numbers of 24 possibilities, one of which is 4186, and the other is predictable from that because 8 mod 7 = 1, and the equation (1000a + 100b + 10c + d = 0 mod 7) works out to (6a + 2b + 3c...
*October 7, 2009*

**math**

Forget the halfway for a minute. From the point she fell asleep, she slept twice as long as the rest of the flight after waking. Does that smell like 2/3 + 1/3 to you? Back to the halfway bit... She slept 2/3 of the second half of the flight. She slept 2/3 of half of the ...
*October 7, 2009*

**Math**

You're wrong about one thing; you _do_ know how to do it. You just did it :-)
*October 7, 2009*

**math **

You multiplied by -1/4, I presume: -4x>1/11 -4x (- 1/4) > 1/11 (- 1/4) x > -1/44. That's what I get, too!
*October 7, 2009*

**algebra**

Let's take the first one. We know that any line can be expressed as y = mx + c First we plug in the m given: y = (2/3)x + c. Now, we know that the point (3/2, 9/5) is on this line, so we can substitute these values into our equation to find c: 9/5 = (2/3)(3/2) + c 9/5 = 1...
*October 7, 2009*

**Math**

You typed both 81,700,00 and 81,700,000. I will assume you meant the second, because of the placement of the commas. So Standard form 81,700,000 = 81.7 * 10^6 = 8.17 * 10^7 In scientific notation, we put only _one_ digit before the decimal place, so you will never see 81.7 x ...
*October 7, 2009*

**algebra**

Oops, typo. In case you're confused, I meant "One way to approach it is, as you say, to add -5x to both sides..."
*October 7, 2009*

**algebra**

When you have an equation with just x and y terms, you're looking at a straight line. One way to approach is it, as you say, to add -5 to both sides, and then divide across by 2, so that the LHS just contains y on its own. Then you have it in the form y = mx + c, and you ...
*October 7, 2009*

**algebra**

I think you mean (12-8)(7-4)^3 Just checking, because an extra bracket around like ((12-8)(7-4))^3 would give a different answer. Brackets first. Then powers or roots. Then multiply or divide. Then add or subtract. First do the arithmetic inside the brackets: (4)(3)^3 Now ...
*October 7, 2009*

**Algebra**

To find the y-intersect, you can just set x=0, and see what's left: y + x = -10 y + 0 = -10 y = -10 So (0, -10) is your intersect. This is a straight line, so all you have to do is find two points, and use a ruler to draw a line through them. Let's find the x-intercept...
*October 7, 2009*

**Math**

Just start at the beginning and think it through choice by choice. There are 11 to choose from. How many can you choose? 11. Now you've seen one. Choose another. How many do you have to choose from? 10, 'cos you've already seen one. So how many ways can we choose 2...
*October 7, 2009*

**vocab**

On the same assumption, I see that "chosen" works as well.
*October 7, 2009*

**AP Stats**

Well, $115 is exactly one SD below the mean, so that's handy. A useful guideline is that, moving left to right, over 2SD covers the first 2%; 2-to-1 SD is another 14%, bringing you up to 16%, and 1-to-0 SD covers another 33%, bringing you to the mean at 50% (not quite, ...
*October 6, 2009*

**math - equivalent expression**

An example of the distributive property: 3 * (1 + 2) = (3 * 1) + (3 * 2) x * (a + b) = (x * a) + (x * b) or x(a+b) = xa + xb Where the operators are like this, you multiply the figure outside the brackets into each of the symbols intide the brackets separately. You can also ...
*October 6, 2009*

**GEOMETRY **

Each lilt contains at least one distinct pair. There must be exactly one lilt containing each possible pair. Which axiom number is that? We know that L1 contains {A, B}. Write out the pairs you can make from A, B, C.
*October 6, 2009*

**GEOMETRY **

That allcaps is a bit hard on the eyes. If you want people to read your message, do tone it down and type normally, please. From 2) spoof contains at least two purrs. Call the first two A and B. From 4) there exists exactly one lilt containing them, therefore 1. is proved. ...
*October 6, 2009*

**math**

My bad, Ellie and Reiny, on the second one. My thinker slipped a cog, and I considered y = 1/|11-9x|-6 rather than 1/|11-9x|-6=0. Reiny is correct, of course!
*October 6, 2009*

**math**

Sorry, Ellie, I'm not quite sure what it is you have to do with them - graph them? specify a range for which they are defined, or true in the first case? make a table of values? Anyway, I'll talk a bit about them. The first one says -2 * x^2 < 30. Now, this one is ...
*October 6, 2009*

**arithmetic**

This sounds awkward, but is actually easy. Consider the number 400P. It must end in zero - actually, it must end in 00, since it has 100 as a factor. Therefore its cube root must end in zero. Check this for yourself: the last digit of a cube can be determined by the last digit...
*October 5, 2009*

**AP Calculus**

You're very welcome, Bri. And do look up _why_ that is true sometime. It's quite neat.
*October 5, 2009*

**AP Calculus**

You don't actually have to know the whole function to get its value at one point, if you have other useful information. You can - and should! - look up the background to "Leibniz's law", but it says that f(x)=g(x)h(x) implies f'(x)=g'(x)h(x) + g(x)h&#...
*October 5, 2009*

**Help with deductive reasoning**

Let's take the first one. You can make a syllogism if you have two statements like: (1) If A, then B _and_ (2) Rover is A (3)_then_ you can say that Rover is B Now: (1) If a dog eats Superdog Dog Food, he will be happy. (2) Rover is happy. What is "A" here? it&#...
*October 5, 2009*

**Prorgramming in Java**

I'm not a teacher in this forum, but that's kind of a big lump of a problem just to throw out there and expect help with. You'll probably get more useful help if you break it down into tasks - starting with the writing of the CatalogItem class, I suspect - and then...
*October 5, 2009*

**maths**

regina, in the second part, you ask about the graph. When I was doing this kind of thing, I always used to calculate the x and y intercepts, and then just draw a straight line between. Nowadays there is "Wolfram Alpha" wolframalpha you-know-what on the net
*October 3, 2009*

**math**

The first one is either a typo or a trick, since no number of cm^2 make a litre. Was ir cm^3? There are 1000 cm^3 in a L. By "simplify", I presume the question means convert to one unit - either pounds or ouncez. There are 16 oz in a lb, so one pssible answer is (10...
*October 3, 2009*

**math**

Assuming the question was "Find the value of the digit 5 in 35,791" you are absolutely right!
*October 3, 2009*

**Statistics**

Since the flight is always fully booked, we can say that the luggage weight's mean is 8000 and the SD is 2000. We're interested in the number of flights that is more than (300 / 2000 =) .15 SD above the mean. Now we go to a z-score table - Google will provide, if you ...
*October 3, 2009*

**maths**

Profit then 30M. Profit later, 210M. Change in profit is obviously 180M, right? OK, so that change is over how many years? 1992 to 1998 - 6 years. Profit changed by 180,000,000 over 6 years, so on average it changed $180,000,000 / 6 per year.
*October 3, 2009*

**algebra**

When you see an inequality, and most other equations, with one variable, your first job is usually to add, subtract, multiply, or divide, to get the variable on its own, isolated from the numbers. Just remember to do the same thing to both sides. This one has three sides, but ...
*October 3, 2009*

**Computers**

Ouch. Typing too fast. Should test in that else that l1 hasn't exceeded 10. But you should get the idea.
*October 1, 2009*

**Computers**

This is one of the classic workhorse situations of programming, a sort-merge, used just about everywhere. You sort two lists, then merge them. The basic idea is this: Establish a pointer to the first (lowest) entry in each list, then Loop while any entries unmerged: 1. Compare...
*October 1, 2009*

**Algebra ll**

Slope-intercept form y=mx +c where m is the slope. You are told that the slope is -4, so the equation muct be like y = -4x + c That rules out one of your choices. Now, of the other two, the equation must be true for the point (1,2). So which of these is true? 2 = -4 * 1 + 6 2...
*September 30, 2009*