Monday

May 30, 2016
Total # Posts: 1,611

**Math**

Already answered below by bobpursley for "Lila"
*November 1, 2009*

**Math**

Already answered below by bobpursley for "Lila"
*November 1, 2009*

**bobpursley - Oops**

I just overtyped your name into the from rather than the subject.
*November 1, 2009*

**English**

Well, you started out with a perfectly good What. When have people been starving since? Where are people starving? (or where used they starve, or will they starve?) Why do people starve today? (And while lack of food is the simple proximate answer, you can go back a step and ...
*November 1, 2009*

**English**

It may be simplistic, but I've always found the W (and one H!) questions useful for separating out issues: What? When? Where? Why? Who? Whether? Which? How?
*November 1, 2009*

**math- Algebra 2**

You're welcome!
*November 1, 2009*

**math- Algebra 2**

It just means, add: the value of (10k-8)(6k+7) when k=1 plus the value of (10k-8)(6k+7) when k=2 plus the value of (10k-8)(6k+7) when k=3 plus ... (and so on, 4, 5, to 9, 10)... the value of (10k-8)(6k+7) when k=11 plus the value of (10k-8)(6k+7) when k=12 So you could just do...
*November 1, 2009*

**books**

It's a bit unfair asking for help with the NPR puzzle of the week, isn't it? :-)
*November 1, 2009*

**Science**

There are some ideas at Biographies for Kids. You can get there by typing "garden of praise" "Biographies for Kids" leaders scientists (with the quotes) into Google and then going quite a way down the page until you come to the scientists - though I think a...
*November 1, 2009*

**Math**

OK. That's the first sentence covered in x+2y=56 . In 8 years time, the son's age will be half of john's age. If x is John's age now, then his age in 8 years is (x+8), and his son's will be (y+8). So the next thing is to make a second equation from that ...
*October 31, 2009*

**math 10**

Answered below.
*October 31, 2009*

**Calculus**

(x+5)/(x - 3) is just (x+5) ----- (x-3)
*October 31, 2009*

**Calculus**

What is 8 divided by zero?
*October 31, 2009*

**Calculus**

No, it's not wrong. When x=3, we have: (x + 5) / ( x - 3) = (3 + 5) / ( 3 - 3) = 8 / 0 which is undefined, because of division by zero.
*October 31, 2009*

**Sameul**

It can be factored, but not into integers like (x-1); more like sqrt(2)+-1, and it's definitely not a perfect square. I suspect you've got one of the signs backwards in your head, and you'll probably recognise that as we work through it. Anyway, direct ...
*October 31, 2009*

**alegebra 1**

Given two points, the slope is easy: it's the difference in the ys divided by the differences in the xs. Just be careful to get the numbers in the right order and careful of the signs. For example, (3,5) and(2,-2) x1=3 x2=2 y1=5 y2=-2 So the slope is (y1 - y2)/(x1 - x2...
*October 31, 2009*

**C programming**

Ok, so you need to test all a, b, c from 1 through 100 for a*a + b*b = c*c. What point would you like help with?
*October 31, 2009*

**Physics!**

30.6 cm seems to have become 30.6 m instead of .306 m. Does this solve your problem?
*October 31, 2009*

**Language Arts**

I can't post a link but dictionary reference com gives strat-uh-fahy and also the IPA which I will try to post here /ˈstrætəˌfaɪ/
*October 31, 2009*

**PreCalc**

"two sides that are equal and two other sides that are equal" is a good start. Call the length of one type of side x, and the other y. Then the area is x * y And the perimeter is 2x + 2y Check this on a small 5 * 3 rectangle, to be sure you understand it. We are told...
*October 31, 2009*

** SQL for Business**

OK. Do you have a table to test on? Here's a statement that might get you going: SELECT Supplierid, SUM(Count) FROM Part WHERE Count > PARAMETER GROUP BY Supplierid If you just run this against your table, substituting some number in for PARAMETER for now, you should ...
*October 31, 2009*

**SQL for Business**

Which part or concept or keyword are you having problems with?
*October 31, 2009*

**algebra 2**

Count from -9, -8, -7... to 2, 3 Where is halfway?
*October 31, 2009*

**high school math**

I presume you want to multiply it out? (1+2y)(3+5y) = 1 * (3+5y) + 2y * (3+5y) = 3 + 5y + 6y * 10y^2 and you can finish
*October 31, 2009*

**gr 9 math**

I got my PC to run up a hundred of each type. If you want something else, let us know. -10x^2 -27x -18y^2 6x^2 + 30x -36y^2 32x^2 -16x -30y^2 -28x^2 -85x -22y^2 -40x^2 + 21x + 49y^2 27x^2 -33x -4y^2 -36x^2 -6x + 90y^2 15x^2 -13x -20y^2 -24x^2 -95x -50y^2 -25x^2 + 60x -35y^2 ...
*October 31, 2009*

**gr 9 math**

What kinds of polynomials? Can you give an example, please? Something like 7x^2 + 46x + 24 y^2 that factors into (ax+by)(cx*dy), or something like 6x^5 + 21x^4 + 13x^3 - 10x^2 -78x -36, that factors into (3x^3+2x-12)(2x^2+7x+3) Or something else?
*October 31, 2009*

**math**

Bring everything to feet as a unit, so the cartons are .5 * .5 * 1 cu. ft. = 0.25 cu.ft. For the tank, it's pi r^2 h again: pi * 16 * 8 = 128 pi cu. ft. So how many containers will that fill?
*October 31, 2009*

**Literature**

I'm inclined to think that that last sentence implies omniscient; a third-person limited narrator could not say what the protagonist knew. IMHO, of course :-)
*October 31, 2009*

**math**

volume of cyl: pi r^2 h but if h = d then h = 2r, so pi * r^2 * 2r = 2pi * r^3 Vol of hemisphere = (1/2) volume of sphere: = 2/3 pi r^3 So the ratio is obvious from those results.
*October 31, 2009*

**Math**

volume cylinder = pi r^2 h = pi * 5^2 * 29 = pi * 725 volume sphere - (4/3) pi r^3 = pi * 4/3 * 5^3 = pi * 500/3 and you can finish
*October 31, 2009*

**Grammar and Composition**

Wow. You only know 21 words you don't know? :-) I've always liked aglet and dottle, myself. Anyway, there's quite a fun site called freerice - I can't post a link here but if you Google that word or add the most common dot after it, that is com, you'll get ...
*October 30, 2009*

**Algebra**

I think maybe you're getting two concepts mixed up, but I'm not quite sure. The _domain_ is the set of values x can take. That is every real number_except_11, since it's undefined at x=11. The _solution_ to (8x+3)/(11-x) = 0 (aka the y-intercept of the graph) is x...
*October 30, 2009*

**math**

Your answer is not wrong, but it isn't "a fraction in simplest terms", because you've brought in a decimal approximation. Go back a step, to -87 / (-6/7) which is where you were before you detoured into decimal-land. Dividing by 6/7 is the same as multiplying...
*October 30, 2009*

**Algebra 1A**

7 x + 2 <30 Subtract 2 from both sides: 7 x < 28 Now divide across by 7, and finish,
*October 30, 2009*

**math 5th**

Between 2 and 4 yards, and A multiple of 0.5. No integer can be the answer, because it wouldn't divide evenly into 24.5. The only two possibilities are then 2.5 and 3.5. Which is it?
*October 30, 2009*

**Pre-Calculus**

I think you mean 9 cos (pi * x /6) where x is the month number 0 through 11. And very neat that snswer is. It provides a low of 2 and a high of 20. Mind you, you might want to mention that your actual answer is: 1,000,000(9cos(pi/6) + 11) or 10^6(9cos(pi * x/6) + 11) to make ...
*October 29, 2009*

**calc**

It all looks OK to me, except from 1 to e^4 you should have your signs the other way around: ln(1+ln(e^4)) - ln(1+In(1)) ... =~ +1.60944
*October 29, 2009*

**trig**

Ask yourself this: 1. If x>0, is |x - 2| - |x + 2| positive or negative or zero? (or think of it as "is |x - 2| > |x + 2| ?" 2. If x==0, then clearly |x - 2| - |x + 2| is zero. 3. Now, the interesting one: what if x is negative? Then is |x - 2| > |x + 2| ?
*October 28, 2009*

**physics 8th grade**

If a woman hasa mass of 50 kg calculate her weight in neutons
*October 28, 2009*

**math**

Your first answer, y = x + (1/x), is absolutely right. I don't understand why you would think that a square would be involved. Bringing in the square makes it a completely different thing, and that's why you're getting different results on your graphing calculator...
*October 28, 2009*

**Algebra**

You can't separate the added parts and take the square root of each. (You could if they were multiplied, but not if added.) I will show a counterexample. You were looking at sqrt(x^2+1). Consider this example - let x=3, then we have : sqrt(3^2+1) = sqrt(9+1) = sqrt(10) Now...
*October 28, 2009*

**Algebra I**

You've got the 2w bit right, but you haven't followed through on your original equation. Divide 2w^3 by 2w Divide 6w^2 by 2w Divide 4w by 2w Put 'em all back together. What have you got now?
*October 28, 2009*

**Math**

To graphing a straight line: 1. Draw your axes. 2. Set x=0 in your equation to get the y-intercept: x + y = 1 0 + y = 1 y = 1 so we have one point: (0,1) 3. Set y=0 in your equation to get the x-intercept: x + y = 1 x + 0 = 1 x = 1 so we have a second point: (1.0) 4. Mark the ...
*October 28, 2009*

**college**

Assume you are performing the calibration step of Experiment 8 and you begin with 80 g of water at 20 oC and 80 g of water at 80 oC. After adding the two portions of water into your calorimeter setup and following the procedure outlined in the experiment, you determine the ...
*October 28, 2009*

**chemistry**

Assume you are performing the calibration step of Experiment 8 and you begin with 80 g of water at 20 oC and 80 g of water at 80 oC. After adding the two portions of water into your calorimeter setup and following the procedure outlined in the experiment, you determine the ...
*October 28, 2009*

**math**

You're welcome!
*October 28, 2009*

**math**

2y^2-y(3-2(y-4)-y) Get rid of the inner brackets: 2y^2 - y(3 - 2y + 8 -y) Multiply the y into the brackets: 2y^2 - (3y - 2y^2 + 8y - y^2) 2y^2 - 3y + 2y^2 - 8y + y^2 Now collect the terms together.
*October 28, 2009*

**MATH/SCIENCE**

Easha has the right idea. You need to get all the inputs and outputs into the same units. There's water entering the lake, and there's water leaving the lake. The numbers are just given in different units, which is common in the real world! There's nothing ...
*October 28, 2009*

**MATH**

In each of them, find some factor all the terms have in common. Take #2 for example: 5a^2 - 25a^3 Well, both divide by 5, so we have: 5(a^2 - 5a^3) but we can also take a^2 out of the expression inside the brackets: (a^2 - 5a^3) = a^2*1 - a^2 * 5a = a^2(1 - 5a) So the whole ...
*October 27, 2009*

**math**

I don't think those equations came out right.
*October 27, 2009*

**Calculus**

Just from looking at 2x^2+10x and that has to be zero - I'd try -5
*October 27, 2009*

**math**

1 inch =25.4mm. That is right. But when squaring, you have to square both the units _and_ the numbers, so 1 inch = 25.4 mm (1 inch)^ = (25.4mm)^2 (1^2) inch^2 = (25.4^2) mm^2 1 in^2 = 645.16 mm^2 Or think of it this way: Draw a 3-inch line. That's 3 inches. Now make a ...
*October 27, 2009*

**programming language**

OK, my conscience nags me about that double. To do it right, then instead of taking the lazy way of converting to doubles, and comparing, then: if your current smallest is, say, 13/6 and your new line is, say, 27/13 you should do the comparison by finding a common denominator...
*October 27, 2009*

**programming language**

One approach, simple but with a caveat or two: You need a double for "smallest absoulte ratio so far". Initialise it to something very big. As you take in each line, a) calculate the surface and the volume as two integers b) calculate the absolute ratio as a double c...
*October 27, 2009*

**pre calculus**

Think of it as two curves to draw. One starts at x just greater than 0, somewhere in negative y, passes through (1,0) and (2,3) and off to infinity at x=3. The other comes down from infinity at x=3, passing through (4,3), and just touches the x-axis at a turning point (5,0) ...
*October 26, 2009*

**geometry**

We can't answer without knowing more, like what s is, and whether s is a unit of length or of area.
*October 26, 2009*

**Math**

"maximum: 8, range: 6" gives you your minimum number, so pencil that in, and 8 at the other end of course to make your maximum. Now, if you know what mode and median mean, you should be ready to write in some 6s, and spread about the same number of lower digits.
*October 26, 2009*

**Math**

More like substitution. You already worked out the hard bit: 1.25x + 0.75y = 129.75 and Reiny pointed out that y = 117-x So you can replace (substitute) y in your equation: 1.25x + 0.75(117-x) = 129.75 and I'm sure you can see your way home from there.
*October 26, 2009*

**math**

You can do this with an equation. Let one of the numbers be x. Then the other is (70-x). And we know that x(70-x) = 1224 So -x^2 + 70x = 1224 and solve the quadratic from there. Another way is to list the prime factors of 1224, and guess your way through. Hint: 17 is a prime ...
*October 26, 2009*

**math**

I'm with Zava on the idea, but I think one of us dropped a sign along the way. And I'm not at all sure it wasn't me, so I'll check at the end. Dropped signs happen all the time. We have: x + y = 5 but we're also given what y is: y = x - 3 So we can just ...
*October 26, 2009*

**math**

please help, I have a test tomorrow and i don't get this. solve by substitution 1. y = x - 3 x + y = 5 2. 5x + 2y = 0 x - 3y =0
*October 26, 2009*

**Math**

Oops: that last line should have been = 6.3 * 10^9 of course!
*October 26, 2009*

**Math**

Yes, but "scientific notation" is often used when talking about powers of 10, like: 20000 = 2 * 10^4 This makes arithmetic with large numbers easy, since, following the rule above, all you have to do is add powers to multiply the factors of 10, like: (2.1 * 10^5) * (...
*October 26, 2009*

**Math**

I'll try to answer the case I think you're asking about. If I'm guessing wrong, do ask again. If you have something like x^2 * x^3 (x-squared times x-cubed) then you add the exponents: x^2 * x^3 = x^5 Similarly, in general, x^a * x^b = x^(a+b) With negative ...
*October 26, 2009*

**Algebra 1**

We know that y = mx + c where m is the slope, so the equation we're looking for has to be y = (1/5)x + c (or y = x/5 + c, which is easier to write n this board!) Now all we have to do is find c. We know that (5, -1) must satisfy the equation, do to find c: y = x/5 + c -1...
*October 26, 2009*

**math**

There are two things here. I think you dropped a sign along the way. You have y2 - y1 = 5-1 whereas I think you meant y2 - y1 = -5-1 When you fix that, you still need to find the y-intercept c to finish the whole equation.
*October 26, 2009*

**maths**

I answered this below, rather wordily. If there's something else I can explain, do ask.
*October 26, 2009*

**scatter plots**

OK, so you've plotted your points. The linear model assumption is that a straight line will go through them. It won't, of course, because they're not perfectly in a line, but the idea is to create a line that comes as close as possible to them, usually with the ...
*October 26, 2009*

**algebra (check plz)**

d) is not wrong, but it's not in its final form; you have a constant on each side. Subtract one from each side to get rid of the 1 on the LHS and you'll be finished.
*October 26, 2009*

**math**

You'd recognise it. :-) xy < 0 means xy is negative. When x is 1, what values can y have? When x is 5? pi? 1,000,000,000? When x is -1, what values can y have? If the product of two numbers, say x * y, is negative, what do you know about those numbers? One is p------- ...
*October 24, 2009*

**math finals**

15. and 16 are the answers I got for these questions for margie_o a few days ago, but I see I didn't agree with 18.8% then either.
*October 24, 2009*

**Math Analysis**

You probably took a wrong turn in what was included inside the fourth root. Easy turn to miss. :-) f(x)=(3/4)x^4 g(x)= ((108((3/4)x^4 + 2)-216)^(1/4))/3 = ((81x^4 + 216 -216)^1/4) /3 = ((81x^4)^1/4) /3 = 81^(1/4)x^(1/4) /3 = 3 x / 3 = x
*October 24, 2009*

**math115**

Yes!
*October 24, 2009*

**math115**

You can also do it by getting the prime factors of each: 15 -> 3, 5 24 -> 2, 2, 2, 3 44 -> 2, 2, 11 Now, your LCM must contain all the numbers from any one of those lines. Start by selecting any line, say 15: 3, 5 Now add anything else yu need from 24: 2, 2, 2, 3, but...
*October 24, 2009*

**math115**

15 ad 24 go into 360 evenly. Does 44?
*October 24, 2009*

**equations**

If they're sratring at x = 1 -> Y1 = 1997 , then x = 2 -> Y2 = 1998 then you can just count for a) and b) In the formula y = mx + c, m is the slope and c is the y-intercept, which should answer a couple of them. f) Once you've counted to 2018, just let x equal ...
*October 24, 2009*

**College Algebra**

You're right so far, which was the hard bit. Me, I'd just pull out the calculator at this point. I did, and got 67.2972 = 67.30 to 2 d.p. You can do it by = 29 * sqrt(sqrt(29)) or by log tables. I can't think of an especially clever way.
*October 24, 2009*

**math**

I get 1/(x-3)(x+3) = A/(x-3) + B/(x+3) 1 = (x+3)A + (x-3)B 1 = x(A+B) + 3A -3B -> A + B = 0 -> A = -B -> 3A - 3B = 1 -> A = 1/6; B = -1/6 = (1/6)(x-3) - (1/6)/(x+3)
*October 24, 2009*

**Math **

On what grounds do you choose d?
*October 24, 2009*

**Math **

No, c is not correct. In each of the other cases, what happens when x is the number given: a) 8/(10-90/9) b) x < 10/9, say 1/9 -> 8/(10-9/9) d) 8/(10-72) One of these three is undefined. Which?
*October 24, 2009*

**Pre Calc still confused**

Oops. Left off the last equals: 6.5/1.5 + 6/(1.5-4)+7/(1.5^2-4*1.5) = 0.066666...
*October 24, 2009*

**Pre Calc still confused**

OK. If it's (x+5)/x + 6/(x-4)=-7/(x^2-4x) then I agree with bobpursley's answer but the numerical answers aren't exactly -17/2 and 3/2; they're (-7+-sqrt(101))/2. If you plug 3/2 in, it'll be close but not zero. 6.5/1.5 + 6/(1.5-4)+7/(1.5^2-4*1.5)
*October 24, 2009*

**Pre Calc still confused**

Are the brackets right? I've tried (x+5/x)+(6/x-4)=(-7/x^2-4x), and (x+5)/x + 6/(x-4)=-7/(x^2-4x) and a couple of other permutations without achieving enlightenment.
*October 24, 2009*

**algebra**

We need a variable for the time. Let's call that t. And we can call the distance d. At t = 0 (1pm) you are 150 miles away, and as t increases, the distance decreases, so we need to subtract some multiple of t from 150 as we go. We need something that starts with d = since ...
*October 24, 2009*

**math**

Correct! Perpendicular lines have slopes that are negative reciprocals of each other. Thus perpendiculars of y = -(1/2)x + anything will have a form like y = 2 + something The two lines you specified are in fact parallel, because they have the same slope : (y = -x/2 + something)
*October 24, 2009*

**math**

It would!
*October 24, 2009*

**Trig**

I suspect you mean tan((m + n)/2) on the RHS
*October 24, 2009*

**pre calc**

Not sure you should go by me, because I took it down wrong the first time, but I got: x + 11/x - 4 + 7/x^2 + 4x = 0 Gathering and multiplying by x^2: 5x^3 - 4x^2 + 11x + 7 = 0 Does this makes sense to you in the context of your course?
*October 24, 2009*

**programming**

The confusion may be coming from trying to take in too many things at once. At root, all this is asking is for you to write a function to find a sequence like {8, 7} in a sequence like (1, 2, 3, 4, 5, 6, 7, 8, 9, 8, 7, 6, 5, 4, 3, 2, 1} - which is essentially the same process ...
*October 24, 2009*

**Math**

Which functions are exponential? A)3x B)3^x C)3x^2 D)2^-x I think that B and C are exponential. Am I correct?
*October 23, 2009*

**Physics**

As the time required to run up the stairs increases, the power developed by that person Increases, decreases, or remains the same. Is the answer decreases?
*October 22, 2009*

**algebra**

y = mx + c, where m is the slope and c is the intercept. You are told m, and you are told c, so all you have to do is plug them in.
*October 22, 2009*

**algebra**

y = mx + c, where m is the slope, and c is the y-intercept. You have y = -9x + (-7) So, thinking of it that way, what is the slope and intercept?
*October 22, 2009*

**algebra**

I didn't get it either, until I erad the question for the equation three times. It seems they're assuming that the life expectancy function plotted agaist the years since 1990 is a straight line, and I'm not at all sure you should assume that. Anyway, if we do ...
*October 22, 2009*

**math 115**

So plot your amount spent along the x-axis and your sales on the y-axis, and extend the line out to $50. Nt much else we can help you with on this one.
*October 22, 2009*

**algebra**

he slope is just the difference in the ys over the differences in the xs. That is, when you move 1 in the x direction, how far do you move in the y direction. -4 isn't very far off, but it's not the exact answer: Your Ys are 13.4 and 2.1 Your Xes are -19.3 and -17.3 (...
*October 22, 2009*

**math(rational functions application)**

Call the speeds j and c. j - c = 100 -> j = 100 + c (100 + c) = 5c / 4 (from the "25% faster") Solve for c.
*October 22, 2009*

**algebra**

If I understand the question, 10, 12, 14 and 16 is not right. Is 2 * 10 + 16 = 96? Call the numbers a, b, c, d. We're really only interested in a and d. How much bigger is d than a? d = a + ? Call the unknown x. d = a + x Now, we know that 2a + d = 96 but we also know that...
*October 22, 2009*

**corp. finance**

It's tedious, but there isn't a useful shortcut. In year one, you add 13% of 5000 to the 5000, making 5650. Then you add 3500, making 9150. Then you add 13% to that, and then add another 3500, and go for another year @ 13%. And so on.
*October 22, 2009*

**math**

Would you fit a billion gallons of gas in your tank? Could you afford to? Would you stop to buy 1 thousandth of a gallon? The appropriate domain will be somewhere inbetween. You figure out what, based on your own good sense. Given your domain, the range easily falls into place.
*October 22, 2009*