Wednesday
May 22, 2013

Posts by janet


Total # Posts: 308

calculus
Evaluate the limits without using a calculator. Justify all steps in the solutions. lim x-->0 x^7cos(3/x)

Calculus
I figured this out this way but am not sure it's right. f(2) + 4(2) = f(2) + 8. From this we can tell that it exists, but I'm not sure why.

Calculus
If a function f(x) is continuous, then what can be said about the value of the following limit lim-->2 [f(x) +4x]

calculus
Evaluate the limits without using a calculator. Justify all steps in the solutions. lim x-->0 x^7cos(3/x)

calculus
This is what I tried. g(x) = 2((x-2/(squareroot x)-2)) lim --> 2 I just substituted 2 in for x and 2((2-2)/(squareroot 2)-2) = 0 This doesn't look right. It seems like I'd need to try something different.

calculus
Use the function given to answer the following questions. g(x)= 2 x-2/(squareroot x)-2 The first 2 is set in the middle of the division line. I think signifying that you solve the x-2/(squareroot x)-2 first then multiple everything by 2. problem to solve is lim-->2 g(x)

calculus
Thank you so much for your help!!

calculus
Sorry MathMate, The anonymous answer above was mine. Just on a different computer.

calculus
I'm really unsure of how to treat the cos(x/3). YOu stated about that the domain for sin, cos is all real numbers. Would it be (-infinity, infinity) for both domain and range?

calculus
Find the domain and range of the given functions. 1. h(x)= (squareroot4x+1)+3x-5 2. f(x)=3cos(x/3)-1 3. g(x)= log (x+2) Can someone show me the steps to figure the above problems?

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