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September 21, 2014

Posts by hurrdurrbeedooda


Total # Posts: 19

Physics
Find the net force of the two concurrent forces, and then reverse the direction of the net force. There's your equilibriant. SIMPLE ex: 2N east Equilibriant: 2N west
October 2, 2011

college Algebra
Umm, just add them together and divide by 2... 17.5 + 35 = 52.5... Divided by 2...26.25..
October 2, 2011

Science
79N
October 2, 2011

science
d = m/v d = 5g / 10cm3 d = 0.5 g/cm3
October 2, 2011

calculus
Whats the equation? If point is just 1, then there is an undefined tangent. Since the tangent will be vertical.
October 2, 2011

Physics
Kinematic equation: d = vi*t + (1/2)a*t^2 Since its moving at 3.6m/s in the horizontal direction, disregard it. Hence initial velocity is 0 1.2m = 0 + (1/2)9.81m/s^2 * t^2 (1.2m / (1/2)9.81 m/s^2) = t^2 (1.2m / (1/2)9.81 m/s^2)^1/2 = t t = 0.49 s
October 2, 2011

physics
Assuming acceleration is the force of gravity. Vf = Vi + a*t Vf = 18m/s + 9.81ms^-2 * 15s Vf = 165.15 m/s d = Vi*t + 1/2a*t^2 358 = 18m's*t + (1/2)9.81ms^-2 * t^2 Set it to zero: 0 = 4.91ms^-2 * t^2 + 18m/s * t - 358. Use quadratic formula t = 6.9s or t = -10.5s Can't ...
October 2, 2011

physics 180A
F = kx ma = kx 480kg * (4*9.81) = k * 11.8m k = 1596.20339
October 2, 2011

Math
EDIT: Change 250x = 5000 - 2500 to: 250x = 5000 - 2800
October 2, 2011

Math
Let x = part - time staff Total cost for full-time workers = 350 * 8 = 2800 2800 + 250x = 5000 250x = 5000 - 2500 x = 8.8 Since I have not met 4/5'ths of a person we would have to either round up or down. Since the daily wage cannot exceed $5000 we will round down to 8. ...
October 2, 2011

Math
Let x = 2$ coins Let y = 5$ coins First equation is for the total amount of coins: x + y = 18 Second Equation is for total amount in dollars in total from the coins: 2x + 5y = $75 Lets isolate for y x = 18 - y Sub into second equation 2(18 - y) + 5y = 75 36 - 2y + 5y = 75 3y...
October 2, 2011

physics
Lets get acceleration. Vf^2 = Vi^2 + 2a*d Vf = Final velocity Vi = Initial veloctiy a = acceleration d = distance traveled 0 = (120)^2 + 2a(0.90) a = -8000 Ava = (Vf - Vi/(Tf - Ti) First must find time. Ava = average acceleration Vf = Vi + a*T Tf = final time, Ti = initial ...
October 1, 2011

physics
Kinematic Equation d = Vi*t + 1/2a*t^2 Vi = Initial Velocity d = distance traveled a = acceleration t = time Since Vi is 0(he drops it). -Also converted 18 km to 18000m 18000 = 0 + 1/2(4.4)*t^2 18000 = 2.2*t^2 (18000/2.2) = t*2 (18000/2.2)^1/2 = t t = 90s
October 1, 2011

science
Ke (Kinetic Energy) = (1/2)m*v^2 m = mass v = speed u = 1.66 x 10^-27 kg 12u = 1.99 x 10^-26 kg Ke = (1/2)(1.99 x 10^-26 kg)*(2 x 10^6m/s)^2 Ke = 3.98 x 10^-12. Convert this to KeV or w/e.
October 1, 2011

Physics 1
Hmm, based off of what I think. The rope will be holding the mass at an angle of 76 degrees with respect to a horizontal x- axis. Fg = 9.81 * 17 = 167N 167N sin 76 <--- thinking about the gravity force being weaker since its at an angle. =162N Now calculate the FN 162N cos ...
September 30, 2011

science
yes
September 30, 2011

math
Inverse sin (8/150) will get you the angle. Ramp is the hypotenuse, entrance height is the opposite side of the triangle.
September 30, 2011

physics
Since the object is at the top of its trajectory its change in altitude (sin velocity) should be 0. Then you just need to calculate for the speed in the horizontal axis(which never changes in simple projectile motion). It becomes 141 cos(pi/4) or 141 cos (45) if you prefer ...
September 30, 2011

physics
Be more specific with the chart
September 30, 2011

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