Wednesday

March 1, 2017
Total # Posts: 19

**Physics**

Find the net force of the two concurrent forces, and then reverse the direction of the net force. There's your equilibriant. SIMPLE ex: 2N east Equilibriant: 2N west

*October 2, 2011*

**college Algebra**

Umm, just add them together and divide by 2... 17.5 + 35 = 52.5... Divided by 2...26.25..

*October 2, 2011*

**science**

d = m/v d = 5g / 10cm3 d = 0.5 g/cm3

*October 2, 2011*

**calculus**

Whats the equation? If point is just 1, then there is an undefined tangent. Since the tangent will be vertical.

*October 2, 2011*

**Physics**

Kinematic equation: d = vi*t + (1/2)a*t^2 Since its moving at 3.6m/s in the horizontal direction, disregard it. Hence initial velocity is 0 1.2m = 0 + (1/2)9.81m/s^2 * t^2 (1.2m / (1/2)9.81 m/s^2) = t^2 (1.2m / (1/2)9.81 m/s^2)^1/2 = t t = 0.49 s

*October 2, 2011*

**physics**

Assuming acceleration is the force of gravity. Vf = Vi + a*t Vf = 18m/s + 9.81ms^-2 * 15s Vf = 165.15 m/s d = Vi*t + 1/2a*t^2 358 = 18m's*t + (1/2)9.81ms^-2 * t^2 Set it to zero: 0 = 4.91ms^-2 * t^2 + 18m/s * t - 358. Use quadratic formula t = 6.9s or t = -10.5s Can't ...

*October 2, 2011*

**physics 180A**

F = kx ma = kx 480kg * (4*9.81) = k * 11.8m k = 1596.20339

*October 2, 2011*

**Math**

EDIT: Change 250x = 5000 - 2500 to: 250x = 5000 - 2800

*October 2, 2011*

**Math**

Let x = part - time staff Total cost for full-time workers = 350 * 8 = 2800 2800 + 250x = 5000 250x = 5000 - 2500 x = 8.8 Since I have not met 4/5'ths of a person we would have to either round up or down. Since the daily wage cannot exceed $5000 we will round down to 8. ...

*October 2, 2011*

**Math**

Let x = 2$ coins Let y = 5$ coins First equation is for the total amount of coins: x + y = 18 Second Equation is for total amount in dollars in total from the coins: 2x + 5y = $75 Lets isolate for y x = 18 - y Sub into second equation 2(18 - y) + 5y = 75 36 - 2y + 5y = 75 3y...

*October 2, 2011*

**physics**

Lets get acceleration. Vf^2 = Vi^2 + 2a*d Vf = Final velocity Vi = Initial veloctiy a = acceleration d = distance traveled 0 = (120)^2 + 2a(0.90) a = -8000 Ava = (Vf - Vi/(Tf - Ti) First must find time. Ava = average acceleration Vf = Vi + a*T Tf = final time, Ti = initial ...

*October 1, 2011*

**physics**

Kinematic Equation d = Vi*t + 1/2a*t^2 Vi = Initial Velocity d = distance traveled a = acceleration t = time Since Vi is 0(he drops it). -Also converted 18 km to 18000m 18000 = 0 + 1/2(4.4)*t^2 18000 = 2.2*t^2 (18000/2.2) = t*2 (18000/2.2)^1/2 = t t = 90s

*October 1, 2011*

**science**

Ke (Kinetic Energy) = (1/2)m*v^2 m = mass v = speed u = 1.66 x 10^-27 kg 12u = 1.99 x 10^-26 kg Ke = (1/2)(1.99 x 10^-26 kg)*(2 x 10^6m/s)^2 Ke = 3.98 x 10^-12. Convert this to KeV or w/e.

*October 1, 2011*

**Physics 1**

Hmm, based off of what I think. The rope will be holding the mass at an angle of 76 degrees with respect to a horizontal x- axis. Fg = 9.81 * 17 = 167N 167N sin 76 <--- thinking about the gravity force being weaker since its at an angle. =162N Now calculate the FN 162N cos ...

*September 30, 2011*

**science**

yes

*September 30, 2011*

**math**

Inverse sin (8/150) will get you the angle. Ramp is the hypotenuse, entrance height is the opposite side of the triangle.

*September 30, 2011*

**physics**

Since the object is at the top of its trajectory its change in altitude (sin velocity) should be 0. Then you just need to calculate for the speed in the horizontal axis(which never changes in simple projectile motion). It becomes 141 cos(pi/4) or 141 cos (45) if you prefer ...

*September 30, 2011*

**physics**

Be more specific with the chart

*September 30, 2011*

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