Saturday

February 6, 2016
Total # Posts: 11,480

**Physics**

F = -40 + 50[23o] X = -40 + 50*Cos23 = 6.02 N. Y = 50*sin23 = 19.5 N.
*May 18, 2015*

**physics**

M*g = 8 * 9.8 = 78.4 N. = Wt. of block. Fp = 78.4*sin40 = 50.4 N. = Force parallel to the incline. Fn = 78.4*cos40 = 60.1 N. = Normal force Fk = u*Fn = 0.35 * 60.1 = 21 N. = Force of friction. a = (Fp-Fk)/M = (50.4-21)/8 = 3.68 m/s^2 d = 0.5a*t^2 = 0.5*3.68*3^2 = 16.54 m.
*May 18, 2015*

**PHYSICS**

Vbw = 1km/15Min = 1km/0.25h = 4km/h = Velocity of boat with respect to the water. Vbw = Vb + Vw = 4i 5i + Vw = 4i Vw = -1i = 1km/h[-90o] = 1km/h Due South
*May 18, 2015*

**PHYSICS**

Vsw = Vs + Vw = 10 + 5i, Q1. Tan A = Vw/Vs = 5/10 = 0.500 A = 26.6o E. of N. Direction = 26.6o W. of N.
*May 18, 2015*

**math**

P = Po + Po*r*t P = 10000 + 10000*(0.1219/360)*60 P = 10000 + 203.17 = $10,203.17 On 60th day. I = (10,203.17-5000)*(0.1219/360)*60 = $105.71 For last 60 days. It = 203.17 + 105.71 = $308.88 = Total int. paid. I = 10000*(0.1219/360)*120 = $406.33 For 120 days. 406.33 - 308.88...
*May 16, 2015*

**algebra**

12x + 16y = 150
*May 14, 2015*

**math**

See Related Questions: Fri, 8-31-12, 1:49 AM.
*May 14, 2015*

**math**

See previous post: Thu, 5-14-15, 1:23 PM
*May 14, 2015*

**math**

1. 16t^3 - 50t^2 + 36t = 2t(8t^2 - 25t + 18) A*C = 8*18 = 144 = -9*(-16). Sum = -25 = B. 2t((8t^2-16t) - (9t-18)) 2t(8t(t-2) - 9(t-2)) = 2t(8t-9)(t-2) 4. y^2 + 12y + 35 35 = 7*5, Sum = 7 + 5 = 12 = B. (y+7)(y+5)
*May 14, 2015*

**math**

12N * 20N = 360 240N^2 - 360 = 0 2N^2 - 3 = 0 2N^2 = 3 N^2 = 1.5 N = 1.225 = 122.5% %Increase = 122.5% - 100% = 22.5% = The amount each dimension is increased. Length = 20 * 1.225 = 24.5 Ft. Width = 12 * 1.225 = 14.7 Ft. Area = 24.5 * 14.7 = 360.15 Ft^2.
*May 13, 2015*

**Math**

d = 15*cos58 = 7.95 m. = Distance from base of the wall. Cos A = d/L = 7.95/12.6 = 0.63086 A = 50.9o
*May 13, 2015*

**geometry**

a. (h,k) = (2,-3) b. r = sqrt 9 = 3 D = 2*r = 2 * 3 = 6
*May 13, 2015*

**Math**

P = Po + Po*r*t P = 2500 + 2500*(0.11/12)*6 = Note: (0.11/12) = Monthly % rate.
*May 13, 2015*

**Physics**

2Hz = 2 cycles/s(c/s). Circumference = pi*2r = 3.14 * 10 = 31.4 m. V = 2c/s * 6.28rad/c = 12.56 rad/s
*May 13, 2015*

**Math**

Score = 4 * 14 = 56 Points
*May 13, 2015*

**Math**

P = Po + Po*r*t = $1312.50 1200 + 1200*(r/12)*9 = 1312.50 900r = 1312.50 - 1200 = 112.50 r = 0.125 = 12.5% APR.
*May 13, 2015*

**Math**

Cost = 100% - 3% = 97% of original price 0.97Po = 4195.25 Po = $4,325
*May 13, 2015*

**Electronics, Physics, Math**

E = 30 Vdc R1 = 80 Ohms R2 = 1,000 Ohms R3 = 4,200 Ohms V2 = ? I = E/(R1+R2+R3) = 30/5,280 = 0.00568A V2 = I * R2 =
*May 12, 2015*

**Physics**

Impulse = F*t = 25 * 0.16 = 4
*May 12, 2015*

**algebra 2**

Y = x^2 - 5x + 4 h = Xv = -B/2A = 5/2 = 2.50 = Value of X at the vertex. k = 2.5^2 - 5*2.5 + 4 = -2.25 = Value of Y at the vertex. D(2.5,Y1), V(2.5,-2.25), F(2.5,Y2) In a y-parabola, the y-coordinates vary while the x-coordinates remain constant and is equal to h(2.50). The ...
*May 12, 2015*

**physics**

M1*V1 + M2*V2 = M1*V + M2*V 1030*3.4 + 1140*0 = 1030V + 1140V V = ?
*May 12, 2015*

**physics**

Select: R1 = 33k R2 = 120k R3 = 120k 1/Req = 1/33k + 1/120k + 1/120k = 0.0469697k Req = 21.3k
*May 12, 2015*

**Electronics, Physics**

Correction: Rt = 10 + (60*5)/(60+5) = 10 + 4.62 = 14.62 Ohms.
*May 12, 2015*

**Electronics, Physics**

Rt = 10 * (60*5)/(60+5) = 10 + 4.62 = 14.62 Ohms = Total resistance. Note: Based on the values given, the total resistance will be less than 15 ohms.
*May 12, 2015*

**Electronics, Physics**

Another Method R1 = 10 Ohms R2 = 60 Ohms R3 = 5 Ohms Rt = R1 + (R2*R3)/(R2+R3)
*May 12, 2015*

**math**

r = 4 in. h = 12 in. V = pi*r^2 * h = 3.14*4^2 * 12 = 602.88 m^3. r = 4.2 in. h = 12.2 in. V = 3.14*4.2^2 * 12.2 = 675.75 in^3 Error = 675.75 - 602.88 = 72.87 in^3
*May 11, 2015*

**math**

The degree is the largest exponent(3).
*May 11, 2015*

**Calc 2**

∞ Σ n/(√n^7+5n+1) n=1 I just tried using a sub n and b sub n and got the limit = 1, therefore it diverges right? but I'm not sure
*May 11, 2015*

**ALGEBRA help ASAP**

At 0o: Tan A = Y/X X = r Tan A = Y/r = Sin A.
*May 11, 2015*

**pre calculus**

sin A = 3/5 = y/r, Q2. x^2 + y^2 = r^2 x^2 = r^2 - y^2 = 5^2 - 3^2=25 - 9 = 16 X = -4, Q2. Cos A = X/r = -4/5 Tan A = Y/X = 3/-4 = -3/4
*May 11, 2015*

**Physics**

Eq1: R1+R2 = E/I = 12.4/2.13 = 5.82 Ohms (R1*R2)/(R1+R2) = 12.4/9.01 = 1.38 Ohms Replace R1+R2 with 5.82 Ohms: R1*R2/5.82 = 1.38 R1*R2 = 5.82*1.38 = 8.0 R1 = 8/R2 In Eq1, replace R1 with 8/R2: 8/R2 + R2 = 5.82 8 + R2^2 = 5.82R2 R2^2 - 5.82R2 + 8 = 0 Use Quadratic Formula. R2...
*May 11, 2015*

**Math 12A Plain Trigonometry**

sin70.5 = 13/d d = 13/sin70.5 = 13.8 Miles.
*May 11, 2015*

**Analytic Geometry**

h = 0.5g*t^2 = 3 m. 4.9t^2 = 3 t^2 = 0.612 Tf = 0.782 s. = Fall time. Dx = Xo*Tf = 5 m. Xo * 0.782 = 5 Xo = 6.39 m/s = Hor. component of initial velocity. h = 0.5g*t^2 = 12 m. 4.9t^2 = 12 t^2 = 2.45 Tf = 1.56 s. Dx = Xo*Tf = 6.39m/s * 1.56s. = 10 m. From water outlet.
*May 11, 2015*

**Geometry**

C(x,y) B(8,2) x-8 = (8-0)/2 = 4 X = 12 y-2 = (2-0)/2 = 1 Y = 3 C(12,3) D(x,y) 12-x = 8-0 = 8 X = 4 3-y = 2-0 = 2 Y = 1 D(4,1)
*May 10, 2015*

**math**

P = Po + Po*r*t P = 7,000,000 + 7,000,000*0.05*12 = 11,200,000
*May 10, 2015*

**Math**

x-3y+9 = 0 -3y = -x - 9 Y = (1/3)x + 3 m = 1/3 b = 3
*May 10, 2015*

**Physics**

Out of phase.
*May 10, 2015*

**algebra**

N + .22N = 3,200,000 1.22N = 3,200,000 N = 2,622,951 or 2,623,000
*May 9, 2015*

**math**

Tan60 = 15/x X = 15/Tan60 = 8.66 Side = 2x = 2 * 8.66 = 17.32
*May 9, 2015*

**Physics**

Distance Traveled = 300 + 400 = 700 mi. Displacement = sqrt(300^2+400^2) = 500 m
*May 9, 2015*

**Math**

Tan26 = h/50 h = 50*Tan26 = 24.4 m.
*May 9, 2015*

**Simmons**

M*g = 2kg * 9.8N./kg = 19.6 N. = Wt. of box. Fp = 19.6*sin65 = 17.76 N. = Force parallel to the incline. Fn = 19.6*Cos65 = 8.28 N.=Perpendicular to the incline = Normal. Fs = u*Fn = 0.3 * 8.28 = 2.48 N. = Force of static friction. Fap-Fp-Fs = M*a Fap-17.76-2.48 = M*0 = 0 Fap...
*May 8, 2015*

**Physics**

Work = Energy output(Eo). Eff. = Eo/(Eo+800) = 0.20 Eo = 0.2(Eo+800) Eo = 0.2Eo + 160 0.8Eo = 160 Eo = = 200 J.
*May 8, 2015*

**Physics**

1609m/5280Ft * 100cm/m * 1Ft/12in = 2.54 cm/in.
*May 8, 2015*

**Physics**

Correct.
*May 8, 2015*

**Math**

850x > 300x + 7500 850x - 300x > 7500 550x > 7500 X > 13.6 Weeks.
*May 7, 2015*

**PreCal**

2|5x-5| + 4 = 20 2|5x-5| = 20-4 = 16 |5x-5| = 8 5x-5 = 8 5x = 13 X = 13/5 -(5x-5) = 8 -5x + 5 = 8 -5x = 3 X = -3/5
*May 7, 2015*

**math**

William: $X Jan: $2X Greg: $11. x + 2x + 11 = 26 x = ?.
*May 7, 2015*

**math**

PART A: Mr. Parker: $100/(5.4*3) = $6.17/m^2 Mr. Lewis: $115/(5.7*3.2) = $6.30/m^2 PART B: Mr. Parker: 49 Min./(5.4*3) = 3 Min/m^2 PART C: Mr. Lewis: (5.7*3.2)m^2 * 3Min/m^2=55min
*May 7, 2015*

**Algebra Readiness**

Slope = Y/X = 6/10 = 0.6 Note: 6/10 = 3/5(D).
*May 6, 2015*

**Physics**

Xc = 1/2pi*F*C = 79.62 Ohms. I = V/Xc = 30/79.62 = 0.377A = 37.7 mA.
*May 6, 2015*

**Physics**

Xl = 2pi*F*L = 6.28*25*30 = 4710 Ohms. I = V/Xl = 30/4710 = 0.0064 A = 6.4 mA
*May 6, 2015*

**physics**

4.5kW = 4500 W. = 4500 J./s Work = F*d = Mg * d = 3.56*10^7 * 1741.4 = 6199.4*10^7 = 6.199*10^10 J. T = 6.2*10^10J. * 1s/4500J = 1.38*10^7 s = 833.3 Hours.
*May 6, 2015*

**Physics**

See previous post: Wed, 55-6-15, 1:26 PM.
*May 6, 2015*

**Physics**

M*g = 40*9.8 = 392 N. = Wt. of sled. Fp = 392*sin 0 = 0 = Force parallel to the surface. Fn = 392*Cos 0 = 392 N. = Force perpendicular to the surface. Fs = u*Fn = 0.4 * 392 = 156.8 N. = Force of static friction. Fk = 0.25 * 392 N. = 98 N. = Force of kinetic friction. a. Fap-Fs...
*May 6, 2015*

**Trig**

sec A * sin A = 1/Cos A * sin A = Sin A/Cos A = Tan A.
*May 6, 2015*

**Physics**

X = 4 km/h Y = 3 km/h V = sqrt(X^2+Y^2)
*May 5, 2015*

**IDOC**

1/b(2b-10) = 17 Multiply both sides by b: 2b-10 = 17b 15b = -10 b = -2/3
*May 5, 2015*

**IDOC**

Multiply both sides by b: 2b-10 = 17b
*May 5, 2015*

**Physics**

V^2 = Vo^2 + 2g*h Vo = 12 m/s. g = -9.8 m/s^2 h = 5 m. V = ?
*May 5, 2015*

**science**

X = 3 km Y = 4 km D = sqrt(X^2+Y^2)
*May 5, 2015*

**chemistry**

what is the volume occupied by 2 moles of ammonia at s.t.p(1mole of gas at s.t.p=22.4)
*May 4, 2015*

**Physics**

I = 24/8 = 3A = Lamp current. Vr = 117-24 = 93 V. = Voltage across the resistor. R = Vr/I = 93/3 = 31 Ohms.
*May 4, 2015*

**math**

V = Vo(1-r)^t = 35,000/2 35,000(1-0.12)^t = 17,500 Divide both sides by 35,000: (0.88)^t = 0.5 Take Log of both sides: t*Log(0.88) = Log 0.5 t = Log 0.5/Log(0.88) = 5.42 Years.
*May 4, 2015*

**science**

Work = F*d = Mg*d = 80*9.8 * 6 = 4704 J
*May 3, 2015*

**math**

a. 19/20 - 5/8 - 7/10 = 38/40 - 25/40 - 28/40 = -15/40 = -3/8. b. (24/40)/(30/14)(25/63) = (3/8)/(15/7)(25/63) = (7/8)/(375/441) = 7/8 * 441/375 = 3087/3000 = 1029/1000 c. (-24/1)(1/1)(-1/1)(1/1)(-1/1)(1/30) = -24/30 = -4/5.
*May 1, 2015*

**Math**

22/7
*May 1, 2015*

**Physics**

1A = 1C/s 1.1*10^-3A = 1.1*10^-3 C/s. T = 3.40C * 1s/1.1*10^-3C = 3090 C.
*April 30, 2015*

**Math**

There appears to be a typo in your problem. So I'm assuming b = h = 14 in. At = bh/2 = 14*14/2 = 98 in^2 = Area of triangle. As = 7^2 = 49 in^2 = Area of the square. Ar = At-As = 98 - 49 = 49 in^2 = Area remaining.
*April 30, 2015*

**Consumer math**

I = Po*r*t = 4000*(0.095/360)*270 = $285
*April 30, 2015*

**Financial math**

Po = 0.80 * 235,000 = $188,000 P = (Po*r*t)/(1-(1+r)^-t) r = (4.5%/12)/100 = 0.00375 = Monthly % rate expressed as a decimal. t = 30yrs. * 12mo/yr. = 360 Months. Monthly Payments = P/t
*April 30, 2015*

**algebra**

(y+4)/3 + 6 = (3y-1)/4 - 2 4(y+4)/12 + 6 = 3(3y-1)/12 - 2 (4y+16)/12 + 6 = (9y-3)/12 - 2 Multiply both sides by 12: 4y + 16 + 72 = 9y - 3 - 24 4y - 9y = -27 -88 -5y = -115 Y = 23
*April 30, 2015*

**Math**

A.12mo/yr. * 10yrs. = 120 months I = Po*r*t = 20,000*(0.04/12)*120 = B. 360days/yr * 5yrs. = 1800 days I = 20,000*(0.08/360)*1800 =
*April 30, 2015*

**Physics**

P = 8.8*10^6 * 19*10^-3 =
*April 30, 2015*

**Physics**

Glad I could help!
*April 30, 2015*

**Physics**

a = F/M = 152/0.07 = 2171 m/s^2 V = Vo + a*t Vo = 0 a = 2171 m/s^2 t = 0.030 s. V = ? KE = o.5*M*V^2
*April 30, 2015*

**physics**

See Related Questions: Thu, 4-21-11, 9:53 AM.
*April 30, 2015*

**physics**

Dx = Xo*Tf = 200 m. 400 * Tf = 200 Tf = 0.5 s. = Fall time. d = 0.5g*Tf^2 = 4.9*0.5^2 = 1.23 m.
*April 29, 2015*

**science**

Incomplete.
*April 29, 2015*

**physics**

1. V^2 = Vo^2 + g*h V = 0 Vo = 50 m/s g = -9.8 m/s^2 h = ? 2. V = Vo + g*Tr = 0 Tr = -Vo/g = -50/-9.8 = 5.1 s. = Rise time = Time to reach max ht. 3. Tf = Tr = 5.1 s. = Fall time. Tr + Tf = 5.1 + 5.1 = 10.2 s. = Time in flight.
*April 29, 2015*

**Math**

V = sqrt(90*60*54) = 540 in^3
*April 29, 2015*

**physical science**

D = 90 Ft.
*April 29, 2015*

**math**

V = sqrt(90*54*60) = 540 Cubic units.
*April 29, 2015*

**physics**

V^2 = Vo^2 + 2g*h V = 0 Vo = 1.2 m/s g = -9.8 m/s^2 h = ?
*April 29, 2015*

**physics**

Distance from each end to the center = 5/2 = 2.5 m. 2.5 - 1.5 = 1.0 m from center. 40*1 = 25*d d = 1.6 m from center = 0.9 m from the end.
*April 29, 2015*

**trig**

Vpw = 630mi/3h = 210m1/h, Due North Vpw = Vp + Vw = 210i Vp + 15[318o] = 210i Vp + 15*Cos318+15*sin318 = 210i Vp + 11.15 -10i = 210i Vp = -11.15 + 210i + 10i = -11.15 + 220i ,Q2. Tan A = 220/-11.15 = -19.73094 A = -87.1o = 87.1o N. of W. = 92.9o CCW from + x-axis. = 2.9o W. of...
*April 28, 2015*

**algebra**

T1 = 5 h T2 = 6 h T = T1*T2/(T1+T2) = 30/11 = 2.73 h.
*April 28, 2015*

**geometry**

Area = pi*r^2 When the radius is doubled: Area = pi * (2r)^2 = pi * 4r^2. Therefore, the area is 4 times the original value.
*April 27, 2015*

**geometry**

Circumference = pi*2r = pi*Dia. = 3.14 * 50 = 157.1 Ft. When the radius is doubled, the diameter is also doubled. Therefore, the Circumference is doubled: Circumference = 3.14 * 100 = 314.2 Ft.
*April 27, 2015*

**Math 222**

See your previous post.
*April 27, 2015*

**Math 222**

See your previous post.
*April 27, 2015*

**Physics**

V = a*t = 10 * 3 = 30 m/s KE = 0.5*M*V^2 Solve for KE
*April 27, 2015*

**math- algebra**

5x > 2x + 18 5x-2x > 18 3x > 18 X > 6 Note: Any real value of X greater than 6 will satisfy the inequality.
*April 27, 2015*

**Math**

Correction: If Sin A = -0.204 A = -11.8o = 11.8o N. of W. = 168.2o CCW from + x-axis; Q2. If Sin A = 0.204 A = 11.8o S. of W. = 191.8o CCW from + x-axis.
*April 27, 2015*

**Math**

sin A = -0.204 A = -11.8o = 11.8o W. of S. = 258.2o CCW from + X-axis.
*April 27, 2015*

**Math 222**

x = -1 x+1 = 0 x = -2 x+2 = 0 (x+1)(x+2) = 0 x^2 + 2x + x + 2 = 0 x^2 + 3x + 2 = 0
*April 27, 2015*

**Math 222**

y^2 - 18y + (-18/2)^2 y^2 - 18y + 81
*April 27, 2015*

**physics**

See Related Questions: Mon, 2-11-13, 12:22 PM.
*April 27, 2015*

**physics**

E = 18 V. R1 = 61 Ohms R2 = 34 Ohms R3 = 90 Ohms R4 = 11 Ohms I2 = ? Req. = R4 + (R1+R2)R3/(R1+R2+R3) Req. = 11 + (95)90/185 = 11 + 46.22 = 57.22 Ohms. I4 = E/Req. = 18/57.22 = 0.315A I2 + I3 = 0.315A I3 = 95/90 * I2 = 1.056I2 I2 + 1.056I2 = 0.315 2.056I2 = 0.315 I2 = 0.1532A
*April 26, 2015*

**PHYSICS**

M1*V1 + M2*V2 = M1*V + M2*V 16.6*8.92 + 29.2*4.44i = 16.6V + 29.2V 148.1 + 129.6i = 45.8V 196.8[41.2o] = 45.8V V = 4.3 m/s[41.2o] a. Momentum = 196.8 kg-m/s b. Direction = 41.2o N. of E.
*April 26, 2015*