Thursday

October 30, 2014

October 30, 2014

Total # Posts: 9,391

**science**

1. V = Vo + g*t = 30 - 10*2 = 10 m/s. 2. hmax = (V^2-Vo^2)/2g hmax = (0-(30)^2)/-20 = 3. V = Vo + g*Tr = 0 @ hmax. Tr = -Vo/g = -30/-10 = 3 s. = Rise time.
*June 3, 2014*

**math**

I=2.37*10^-5 watts/cm^2=Sound Intensity level. Io =10^-16 W/cm^2 = Reference sound Intensity level. db = 10*Log(I/Io) db = 10*Log(2.37*10^-5/10^-16) = 114
*June 3, 2014*

**physics**

Fx = 100*Cos37 = 79.86 N. Wb = m*g = 10kg * 9.8N/kg = 98 N. = Weight of buggy. a=(Fx-Fk)/m = (79.86-60)/10=1.99 m/s^2
*June 3, 2014*

**physics**

d1 = d2 25t = 0.5a*t^2 25 = 0.5a*t 0.002t = 25 t = 12,500 s. = 3.5 h.
*June 3, 2014*

**physics**

d = 300km[135o] V1 = 300km[135o]/0.75h = 400 km/h[135o] without wind. Vp + Vw = 400o[135] Vp + 80[-90o] = 400[135] Vp = 400[135] - 80[-90] Vp=400*cos135+i400*sin135 - (80*Cos(-90)+i80*sin(-90)) Vp = -282.84+i282.84 - (0-i80) Vp = -282.84 + i362.84 = 460km[128o] = Velocity and ...
*June 3, 2014*

**Algebra 1 (Reiny)**

1. T = T1*T2/(T1+T2) = 2*3/(2+3)=1.2 h. 2. H = 0.4 * 300 = 120 mL in current solution. W = 0.6 * 300 = 180 mL of water in current solution. W/(W+H) = 0.7 W/(W+120) = 0.7 W = 0.7W + 84 0.3W = 84 W = 280 mL of water in new solution. 280-180 = 100 mL of water added to new solution.
*June 3, 2014*

**geometry**

A1 = 150o = Minor Arc. A2 = 360-150 = 210o = Major Arc. X = (A2-A1)/2 = (210-150)/2 = 30o=Angle formed by 2 tangents. a
*June 3, 2014*

**College Algebra**

Length = L units. Width = (2L-2) units. A = L(2L-2) = 82cm^2 2L^2 - 2L - 82 = 0 L^2 - L - 41 = 0 Use Quadratic formula: L = 6.92 cm. Width = 2L - 2 = 2*6.92 - 2 = 11.84 cm. The diagonal divides the rectangle into 2 congruent rt. triangles. D^2 = L^2 + W^2 = 6.92^2 + 11.84^2=...
*June 2, 2014*

**College Algebra ..Please help**

1. Width = W ft. Length = (W+20) ft. A = W*(W+20) = 8,000 Ft^2 W^2 + 20W - 8000 = 0 C=-8,000 = -80*100. Sum = -80+100=20=B. (w+100)(w-80) = 0 w+100 = 0, W = -100 w-80 = 0, W = 80 Ft = Width. w+20 = 80+20 = 100 Ft = Length. 2. A = L*W = 16, L = 16/W. Eq2: L^2 + W^2 = 68 In Eq2...
*June 2, 2014*

**LOOK AT THE GIVEN TRIANGLES??**

a. P1 = (4x+2) + (7x+7) + (5x-4)=16x + 5 P2 = (x+3) + (x+7) + (2x-5) = 4x+5 b. P1-P2 = (16x+5) - (4x+5) = 16x+5 - 4x-5 = 12x.
*June 2, 2014*

**physics**

d = 3.6 + 0.5 = 4.1 miles. T1 = 3.6/9 + 12/60 = 0.6 hr. To travel 4.1 miles from starting point. V1 = d/T1 = 4.1/0.6 = 6.83 mi/h. V2=9.0 mi/h. when returning to starting point. V = (V1+V2)/2 = (6.83+9.0)/2 = 7.92 mi/h = Average velocity for entire trip.
*June 2, 2014*

**physics**

T^2 = 4pi^2(L/g) = 3.4^2 39.48(2.87/g) = 11.56 113.3/g = 11.56 11.56g = 113.3 g = 9.80 m/s^2
*June 2, 2014*

**Kirr**

P = Po(1+r)^n = $25,000 r = (1.825%/365)/100% = 5*10^-5 = Daily % rate expressed as a decimal. n = 365Comp./yr. * 4yrs. = 1460 Compounding periods. Po(1.00005)^1460 = 25000 Po = 25,000/1.00005^1460 = $23,240.
*June 2, 2014*

**algebra math!**

9pts/6wks = 1.5 Points/week.
*June 1, 2014*

**physics**

Wb = m*g = 40kg * 9.8N/kg = 392 N. = Weight of box. Fk=u*(Wb-F*sin31)=0.45(392-173*sin31) = 136.3 N.= Force of kinetic friction. Fn=F*CosA-Fk = 173*cos31 - 136.3 = 12 N. = Net force. a = Fn/m = 12/40 = 0.30 m/s^2.
*June 1, 2014*

**Physics**

hmax = L*sin A = 5*sin40 = 3.21 m. At top of incline: KE + PE = mg*hmax-Fk*L 0 + PE = mg*3.21-10*5 PE = mg*3.21-50. At bottom of incline: KE + PE = mg*3.21-50 KE + 0 = mg*3.21-50 KE = mg*3.21-50 = 35 J. m*9.8*3.21-50 = 35 31.5m-50 = 35 31.5m = 85 m = 2.7 kg. = Mass of box.
*May 30, 2014*

**physics**

V = Vo + g*Tr = 0 at max. ht. Tr = -Vo/g = -40/-9.8 = 4.08 s. = Rise time. T = 4.08-1 = 3.08 s. h1 = Vo*t + 0.5g*t^2 h1 = 40*3.08 - 4.9*3.08^2 = 76.7 m. h2 = 40*4.08 - 4.9*4.08^2 = 81.6 m. h2-h1 = 81.6-76.7 = 4.93 m. = Distance traveled in the last second.
*May 30, 2014*

**physics**

h = Vo*t + 0.5g*t^2 h = 0 + 5*3^2 = 45 m. = Height of object above gnd. (45-1)/4m = 11th floor.
*May 30, 2014*

**physics**

V^2 = Vo^2 + 2a*d V^2 = 0 + 10*10 = 100 V = 10 m/s.
*May 30, 2014*

**algebra**

I = 2.42*10^-5 Watts/cm^2. = Sound intensity. Io = 10^-16 Watts/cm^2 = Reference sound intensity. dB = 10^Log(2.42*10^-5/10^-16) = 114.
*May 29, 2014*

**physics**

h = L*sin A = 5.5*sin30 = 2.75 m. Fn = mg*Cos A = 66*Cos 30 = 57.16 N. = Normal force = Force perpendicular to the ramp. Fk = u*Fn = 0.22 * 57.16 = 12.57 N. = Force of kinetic friction. KE + PE = mg*hmax-Fk*L KE + PE = 66*2.75-12.57*5.5 = 112.4 J. 0 + PE = 112.4 PE = 112.4 J. ...
*May 29, 2014*

**physics**

1. W = Fk*d 25 * 12 Joules. 2. W = 175 * 12 Joules. 3. Wn = (175*12)-(25*12)
*May 29, 2014*

**Physics**

a. X = 45 N. Y = -22 N. F^2 = 45^2 + (-22)^2 = 2,509 F = 50.09 N. b. d = 22m/s * 3s = 66 m. Work = F*d = 50.09 * 66 = 3306 Joules.
*May 29, 2014*

**Physics! Help**

F1 + F2 = 96.2N.[55.4o] + 11.6N.[41.2o] X = 96.2*cos55.4 + 11.6*cos41.2=63.35 N
*May 29, 2014*

**ALGERBRA**

What are the "2 ways?" Perhaps some punctuation would help.
*May 29, 2014*

**Physics**

F = m*a = 1350 N. Impulse=m*V = m*(a*T) = 1350*6.2*10^-3= 8.37 kg-m/s.
*May 29, 2014*

**Physics**

D=2m[270o] + 16m[180o] + 24m[90o]+36m[180o]. Add the two 180o vectors directly: D = 2[270o] + 52[180o] + 24[90o] X = 2*cos270+52*cos180+24*cos90 = -52 m. Y = 2*sin270+52*sin180+24*sin90 = 22 m. D^2 = (-52)^2 + 22^2 = 3188 D = 56.5 m.
*May 29, 2014*

**Physics**

a. d = V*T = 420 m. (12.5-2.70) * T1 = 420 T1 = 420/(12.5-2.70) = 42.9 s. b. T2 = 420/(12.5+2.7) = 27.6 s. T = T1+T2 = 42.9 + 27.6 = 70.5 s. c. T1 = 420/12.5 = 33.6 s. T2 = T1 = 33.6 s. T = 33.6 + 33.6 = 67.2 s.
*May 29, 2014*

**physics**

V=100mi/h * 1600m/mi * 1h/3600s = 44.44m/s V = Vo + a*t = 0 a = -Vo/t = -44.444/10^-3=-44,444 m/s^2 F = m*a = 0.145 * (-44,444) = - 6444 N.
*May 28, 2014*

**physics**

Da = 69.5*T Db = 84.3*T B will have to travel 394 m(0.394km) farther than A to catch up: Db = Da + 0.394km 84.3 * T = 69.5 * T + 0.394 84.3T-69.5T = 0.394 14.8T = 0.394 T = 0.02662 h. = 1.60 Min. to catch up.
*May 28, 2014*

**math**

Slope = Tan A = Y/X = 1/6 A = 9.46o
*May 27, 2014*

**math**

Slope = Y/x = 16 Y/3 = 16 Y = 48 m.
*May 27, 2014*

**physics**

W = F*d*cos A = 457 * 6.2 * Cos 8 = 2806 J.
*May 26, 2014*

**college physics**

mgh2 - mgh1 = mg(h2-h1) = mg(3.1) = 64.7*9.8(3.1) = 1966 Joules.
*May 26, 2014*

**college physics**

a. Always negative.
*May 26, 2014*

**Physics**

The force of the golf club acts in parallel with the motion of the ball which is 28o. So my answer is 1650 N. @ 28o. Since they did not ask for the direction of the force, I did not include the angle. Your answer is not the full force acting on the ball; it is the hor. ...
*May 26, 2014*

**Physics**

a=(V-Vo)/t a = (55-0)/1.5*10^-3=36670 m/s^2 F = m*a = 0.045 * 36,670 = 1650 N.
*May 26, 2014*

**Business mat**

7x + 3 = 7x + b b = 7x-7x+3 = 3
*May 24, 2014*

**Math**

Eq1: Y = x^2+3x-4 Eq2: Y = 2x+2 In Eq1, replace Y with 2x+2 and solve for X: 2x+2 = x^2+3x-4 x^2+3x-2x = 2+4 x^2+x = 6 x^2+x-6 = 0 C = -6 = -2*3. (x-2)(x+3) = 0 x-2 = 0, X = 2. x+3 = 0, X = -3. Solution: X = -3, and 2.
*May 23, 2014*

**math**

1. Y = 4x + 12 = $44. 4x = 44-12 = 32 X = 8 Months = Oct. of same yr. 2.C 3. 8 < x + 3 X > 8-3 X > 5. 7 > 5 Answer = b = 7.
*May 23, 2014*

**Math**

Bought X boxes. Sold (x-5) boxes. Cost = $Y per box Selling price = $(y+0.1) per box. P = $6 * 1.25 = 7.50 = Sale price. (x-5)(y+0.1) = 7.50 xy + 0.1x - 5y - 0.5 = 7.5 Eq1: xy + 0.1x - 5y = 8 Eq2: xy = $6.00 Y = 6/x In Eq1, replace Y with 6/x: 6 + 0.1x - 30/x = 8 0.1x - 30/x...
*May 23, 2014*

**math**

Martin is X yrs. old. Joan is (x-3) yrs. old. 4x/5 = x-3 Multiply both sides by 5: 4x = 5x-15 X = 15 (4/5) * 15 = 12 yrs. = Joan's age.
*May 23, 2014*

**math**

Answer = b.
*May 23, 2014*

**math**

I = 2.42*10^-5 watts/cm^2 = Intensity. Io = 1*10^-16 watts/cm2 = Reference. db = 10*Log(I/Io) db = 10*Log(2.42*10^-5/1*10^-16) db = 10*Log(2.42*10^11) = 114.
*May 23, 2014*

**math**

Thu sales = $X Sat sales = $2X Other 4 days = $X/2 X/(x+2X+X/2) = X/(3 1/2)x = X/(7x/2) = x * 2/7x = 2/7.
*May 23, 2014*

**physics**

KE = 0.5m*V^2 = 900,000 J. 0.5*2000*V^2 = 900,000. Solve for V in m/s.
*May 21, 2014*

**Algerbra 2**

V = Vo - Vo*r*T V = 16,400 - 16,400*0.24*2 = $8528
*May 21, 2014*

**Math**

Do you mean: A(7,3.-4), B(-3,1,0). If so, X = (7+(-3))/2 = 2. Y = (3+1)/2 = 2. Z = (-4+0)/2 = -2. (x,y,z) = (2,2,-2).
*May 21, 2014*

**Math**

See previous post.
*May 21, 2014*

**Math**

C(h,k), P(x,y). x - h = x+5 x-x-h = 5 -h = 5 h = -5 y-k = y-2 y-y-k = -2 -k = -2 k = 2 C(-5,2). r = sqrt(9) = 3 Units.
*May 21, 2014*

**math**

-15-(-4) + (-12) + -8 -9 = -15 + 4 -12 -17 = -44 + 4 = -40.
*May 21, 2014*

**Science**

B. 1.
*May 21, 2014*

**Science**

1d. 2a.
*May 20, 2014*

**Math**

Incomplete.
*May 20, 2014*

**Science**

W = F*d = 200 * 45.5
*May 19, 2014*

**physics**

T^2 = 4pi^2(L/g) = (2.45)^2 39.48(1.25/g) = 6.00 6g = 49.35 g = 8.23 m/s^2
*May 19, 2014*

**Math**

csc R = 13/12 = 1/sin R 1/Sin R = 13/12 sin R = 12/13 = Y/r. X^2 + Y^2 = r^2 X^2 + 12^2 = 13^2 X^2 = 13^2 - 12^2 = 25 X = 5. Tan T = Y/X = 12/5
*May 19, 2014*

**Algebra**

Tan A = 5.67 A = 80 Degrees.
*May 19, 2014*

**Geometry**

A(0,0), B(a,0). AB is a hor. line, because Y is constant. AB = a - 0 = a. D(0,b), C(a,b). DC is a hor. line. DC = a - 0 = a. AB = DC, Because quantities that are = to the same or = quantities are = to each other. A(0,0), D(0,b). AD is a Vertical line, because X is constant. AD...
*May 19, 2014*

**algebra**

h max = ho + (V^2-Vo^2)/2g h max = 80 + (0-(64^2))/-64 = 144 Ft above gnd.
*May 19, 2014*

**maths**

Multiply numerator and denominator by 2^-(1-n): 1/2^(1-n) = 2^-(1-n)/1 = 2^(-1+n) = 2^(n-1)
*May 19, 2014*

**maths**

a. 16 = 2^4 b. 2^m/8 = 2^m/2^3 = 2^(m-3)
*May 19, 2014*

**Algebra**

P = Po(1+r)^n P = $25,000 Po = ? = Initial principal. r = (8%/2)/100% = 0.04 = Semi-annual % rate expressed as a decimal. n = 2Comp./yr. * 3.5yrs. = 7 Compounding periods. P = Po(1.04)^7 = 25,000 Po = 25,000/1.04^7 = $18,997.95 Down.
*May 19, 2014*

**Physics**

a = (V-Vo)/t = (-46-30)/5*10^-3 = -15.2*10^3 m/s^2. F = m*a = 0.15 * (-15,200) = -2280 N.
*May 18, 2014*

**Math**

a. Bal = 739.65 - 0.05*739.65 + 179.39 = $882.06 b. P min = 0.05 * 882.06
*May 18, 2014*

**math**

Ab = Ab = (W*L)/2 = (6*9)/2 = 27 in^2 = Area of the base. V = (Ab*h)/3 = (27*4)/3 = 36 in^3.
*May 18, 2014*

**math**

As = 2(L*h) + 2(W*h) + 2(L*W) As = 2(2*12) + 2(9*12) + 2(2*9) =
*May 18, 2014*

**math**

I don't know how they came up with $5100; perhaps you should double check that number. In a discounted loan, the discounted amount(Int.) is paid up-front by deducting it from the amount borrowed: Ab = $2,000 = Amount borrowed = Face value. Ar = Amount received by borrower...
*May 18, 2014*

**physics**

Vo = 12m/s[50o] Xo = 12*Cos50 = 7.71 m/s. Yo = 12*sin50 = 9.19 m/s. Tr = -Yo/g = -9.19/-9.8 = 0.938 s. Tf = Tr = 0.938 s. = Fall time. Tr+Tf = 0.938 + 0.938 = 1.876 s. = Time to return to launching height. Range=Xo * (Tr+Tf) = 7.71 * 1.876=14.46m D max = 14.46 + 8m/s * 1.876s ...
*May 17, 2014*

**physics**

Incomplete.
*May 17, 2014*

**Physics**

P = (0.45m/3.6m) * 1s. = 0.125 s. = The period of the wave. Freq. = 1/P = 1/0.125 = 8 Cycles/s = 8 Hz.
*May 17, 2014*

**Physics**

d=V*T = 3*10^8 * (1.9*10^-3/2) = 2.85*10^5 m.
*May 17, 2014*

**Geometry**

As = 2*(W*h)) + 2*(L*h) + 2(L*W) a. As = Al + 2*(L*W) = 992 Ft^2 Al + 2*(20*12) = 992 Al = 992 - 480 = 512 Ft^2.=Lateral area. b. Al = 2(W*h) + 2(L*h) = 512 Ft^2 2(12*h) + 2(20*h) = 512 Solve for h.
*May 17, 2014*

**physics**

Circumference = pi*2r = 3.14 * 80 = 251.3 cm. = 2.513 m. V=300rev/min * 2.513m/rev * 1min/60s = 12.57 m/s. = Linear speed. Va = 12.57m/s * 6.28rad/2.513m=31.4rad/s = Angular speed.
*May 17, 2014*

**physics**

X = 100N Y = 100N Tan A = Y/X = 100p/100 = 1.0 A = 45o = Direction. Fr = X/Cos A = = 100/Cos45=141.4N[45o]= Resultant force. a=Fr/m=141.4[45o]/100kg=1.414m/s^2[45o].
*May 16, 2014*

**math**

Ans: D
*May 15, 2014*

**Pre cal**

1. AB+BC = 200km[110o] + 100km[37o] X = 200*cos110 + 100*cos37 = 11.46 km. Y = 200*sin110 + 100*sin37 = 248.1 km. D^2 = X^2 + Y^2 = (11.46)^2+(248.1)^2 = 61,685 D = 248.4 km 2. V = 530mph[N25oW] = 530mph[115o] CCW.
*May 15, 2014*

**Pre cal**

1. An airplane flies 200 km on course 110 degrees from point A to point B. At point B the pilot changes course to 37 degrees. The plane then flies 100 km to point C. Find the magnitude of the net displacement from A to C. 2. A plane is flying on a bearing of 25 degrees west of...
*May 15, 2014*

**Physic**

k = 50N/(25-20)cm = 10N/cm. L = 20cm + (100N/10N) * 1cm = 30 cm.
*May 15, 2014*

**algebra**

Po = $32,500 @ 69%? for 3 years. P1 = Po(1+r)^n. Compounded annually. P1 = 32,500(1+0.69)^3 = $156,871.29 P2 = 32,500(1+0.69/2)^6 = 192,405.32 P3 = 32,500(1+0.69/4)^12 = 219,400.48 P4 = 32,500(1+0.69/12)^36 = 243,207.46 P5 = 32,500(1+0.69/365)^1095=257,053.95 P6 = 32,500(1+0....
*May 14, 2014*

**math**

Assuming simple interest: A. Po = 2055.99-400 = 1655.99 P = Po + Po*r*t P = 1655.99 + 1655.99*0.0725*2 P = 1655.99 + 240.12 = $1896.11 1896.11/24mo = $79.00/Mo. B. P = 180/mo * 12mo = $2160. r = (p-Po)/Po = (2160-2055.99)/2055.99 = 0.0506 = 5.06% Per annum C. Option 1: $1896....
*May 14, 2014*

**Math**

(4/3)*Log(z+2) = Log 4 Log(z+2) = Log 4/(4/3) Log(z+2) = (3/4)*Log 4 = 0.4515 10^(0.4515) = z+2 z+2 = 2.828 Z = 0.828
*May 14, 2014*

**Math**

V(1,2), W(-2,-3) X = 1 + (-2) = -1. Y = 2 + (-3) = -1. (x,y) = (-1,-1).
*May 13, 2014*

**math**

A(-2,3),--B(4,3) C(-2,-2), D(4,y) AC = -2-3 = -5 BD = AC = -5 = y-3 y-3 = -5 Y = -2.
*May 13, 2014*

**Algebra 1**

post it.
*May 13, 2014*

**Algebra 1**

See previous post: Tue,5-13-14, 1:15 PM.
*May 13, 2014*

**Algebra 1**

2x^2 + 7x + 8 = 0 B^2 = 7^2 = 49 4AC = 4*2*8 = 64. Since B^2 is less than 4AC, there are no real solution. But there are 2 imaginary solutions: X = (-B +-sqrt(B^2-4AC))/2A X =(-7 +-sqrt(49-64))/4 X = (-7+-sqrt(-15))/4 X = (-7+-sqrt(15*-1))/4 X = (-7+-(3.87i))/4 X = -1.75 + 0....
*May 13, 2014*

**Algebra 1 Answer Evaluation**

V = Vo + g*Tr = 0 Tr = (V-Vo)/g = (0-64)/-32 = 2 s. = Rise time. Tf = Tr = 2 s. = Fall time. Tr+Tf = 2 + 2 = 4 s. = Time it takes to return to gnd.
*May 13, 2014*

**Math - Proportion**

a. I = P^2/V b. I = (2P)^2/2V = 4P^2/2V = 2P^2/V. Therefore, I is doubled.
*May 13, 2014*

**Algebra 1**

(x+2)(x-5) = 60 x^2-5x +2x - 10 = 60 x^2 - 3x - 70 = 0 C = -70 = 7*(-10). B = 7 + (-10) = -3. (x+7)(x-10) = 0 x+7 = 0, X = -7. x-10 = 0, X = 10.
*May 13, 2014*

**Physical World Concepts**

Fn = 250 - 120 = 130 N.
*May 13, 2014*

**math**

Compounded Daily? Monthly? Annually?
*May 12, 2014*

**Algebra**

Width = W Ft. Length = (W+2) Ft. Area = (W+2)*W = 15Ft^2 W^2 + 2W - 15 = 0 C = -15 = -3*5 (W-3)(W+5) = 0 W-3 = 0 W = 3 W+5 = 0 W = -5. The width can't be negative. Therefore, W = 3 Ft. Length = W+2 = 3 + 2 = 5 Ft.
*May 12, 2014*

**Finance**

P = Po(1+r)^n P = $3,800 r = (8.9%/12)/100% = 0.00742 = Monthly % rate expressed as a decimal. n = 12comp./yr. * 5yrs.=60 Compounding periods. P = Po(1+0.00742)^60 = 3800 Po*(1.00742)^60 = 3800 Po = 3800/(1.00742)^60 = $2438.65 = Present value.
*May 12, 2014*

**Algebra 1 (Step-by-Step)**

1. -7 = X^2 x^2 + 7 = 0 X =( -B +- sqrt(B^2-4AC))/2A X = (0 +- sqrt(0-28))/2 = sqrt(28*(-1))/2 = 5.29i/2 = +-2.65i
*May 12, 2014*

**math**

10. P1 = Po(1+r)^n Po1 = $5,000 r = (6%/2)/100% = 0.03 n = 2comp/yr. * 2yrs. = 4 Compounding periods. P1 = 5000(1.03)^4 = $5627.54 in 2 yrs. P2 = P1(1+r)^n r = (8%/4)/100% = = 0.02 n = 4comp/yr. * 1.5yrs. = 6 Compounding periods. P2 = 5627.54(1.02)^=$6337.53 in 3.5 yrs.
*May 12, 2014*

**math**

a. Ar = Ab - Ab*r*t Ar = Ab - Ab*(0.055/360)*(60-15)=997.77 Ab - Ab*0.006875 = 997.77 0.993125Ab = 997.77 Ab = $1004.68 = Amt. borrowed. Ac = Ab-Ar = 1004.68 - 997.77 = $6.91 = Amt. charged. b. Face Value = Ab = $1004.68
*May 12, 2014*

**math**

5. Ar = Ab - Ab*r*t = 2,000 Ab - Ab*(0.08/360)*120 = 2,000 Ab - 0.02667Ab = 2000 0.97333Ab = 2000 Ab = $2,054.79 = Amount borrowed.
*May 12, 2014*

**math**

Correction: My calculations was based on a 4-day loan; it should be for 4 months: 2. Pr = Po - Po*r*t = 12,000 Po - Po*(0.095/12)*4 = 12,000 Po - Po*0.03167 = 12000 0.96833Po = 12,000 Po = $12,392.46
*May 12, 2014*

**math**

1. P = Po - Po*r*t P = 5000 - 5000*(0.085/360)*180 P = 5000 - 212.50 = $4787.50 = Amt. received by Joanne(Proceeds). 2. P = Po - Po*r*t = 12,000 Po - Po*(0.095/360)*4 = 12,000 Po - Po*0.00106 = 12000 0.99894Po = 12,000 Po = $12,012.68
*May 12, 2014*

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