Thursday
October 30, 2014

Posts by henry


Total # Posts: 9,391

science
1. V = Vo + g*t = 30 - 10*2 = 10 m/s. 2. hmax = (V^2-Vo^2)/2g hmax = (0-(30)^2)/-20 = 3. V = Vo + g*Tr = 0 @ hmax. Tr = -Vo/g = -30/-10 = 3 s. = Rise time.
June 3, 2014

math
I=2.37*10^-5 watts/cm^2=Sound Intensity level. Io =10^-16 W/cm^2 = Reference sound Intensity level. db = 10*Log(I/Io) db = 10*Log(2.37*10^-5/10^-16) = 114
June 3, 2014

physics
Fx = 100*Cos37 = 79.86 N. Wb = m*g = 10kg * 9.8N/kg = 98 N. = Weight of buggy. a=(Fx-Fk)/m = (79.86-60)/10=1.99 m/s^2
June 3, 2014

physics
d1 = d2 25t = 0.5a*t^2 25 = 0.5a*t 0.002t = 25 t = 12,500 s. = 3.5 h.
June 3, 2014

physics
d = 300km[135o] V1 = 300km[135o]/0.75h = 400 km/h[135o] without wind. Vp + Vw = 400o[135] Vp + 80[-90o] = 400[135] Vp = 400[135] - 80[-90] Vp=400*cos135+i400*sin135 - (80*Cos(-90)+i80*sin(-90)) Vp = -282.84+i282.84 - (0-i80) Vp = -282.84 + i362.84 = 460km[128o] = Velocity and ...
June 3, 2014

Algebra 1 (Reiny)
1. T = T1*T2/(T1+T2) = 2*3/(2+3)=1.2 h. 2. H = 0.4 * 300 = 120 mL in current solution. W = 0.6 * 300 = 180 mL of water in current solution. W/(W+H) = 0.7 W/(W+120) = 0.7 W = 0.7W + 84 0.3W = 84 W = 280 mL of water in new solution. 280-180 = 100 mL of water added to new solution.
June 3, 2014

geometry
A1 = 150o = Minor Arc. A2 = 360-150 = 210o = Major Arc. X = (A2-A1)/2 = (210-150)/2 = 30o=Angle formed by 2 tangents. a
June 3, 2014

College Algebra
Length = L units. Width = (2L-2) units. A = L(2L-2) = 82cm^2 2L^2 - 2L - 82 = 0 L^2 - L - 41 = 0 Use Quadratic formula: L = 6.92 cm. Width = 2L - 2 = 2*6.92 - 2 = 11.84 cm. The diagonal divides the rectangle into 2 congruent rt. triangles. D^2 = L^2 + W^2 = 6.92^2 + 11.84^2=...
June 2, 2014

College Algebra ..Please help
1. Width = W ft. Length = (W+20) ft. A = W*(W+20) = 8,000 Ft^2 W^2 + 20W - 8000 = 0 C=-8,000 = -80*100. Sum = -80+100=20=B. (w+100)(w-80) = 0 w+100 = 0, W = -100 w-80 = 0, W = 80 Ft = Width. w+20 = 80+20 = 100 Ft = Length. 2. A = L*W = 16, L = 16/W. Eq2: L^2 + W^2 = 68 In Eq2...
June 2, 2014

LOOK AT THE GIVEN TRIANGLES??
a. P1 = (4x+2) + (7x+7) + (5x-4)=16x + 5 P2 = (x+3) + (x+7) + (2x-5) = 4x+5 b. P1-P2 = (16x+5) - (4x+5) = 16x+5 - 4x-5 = 12x.
June 2, 2014

physics
d = 3.6 + 0.5 = 4.1 miles. T1 = 3.6/9 + 12/60 = 0.6 hr. To travel 4.1 miles from starting point. V1 = d/T1 = 4.1/0.6 = 6.83 mi/h. V2=9.0 mi/h. when returning to starting point. V = (V1+V2)/2 = (6.83+9.0)/2 = 7.92 mi/h = Average velocity for entire trip.
June 2, 2014

physics
T^2 = 4pi^2(L/g) = 3.4^2 39.48(2.87/g) = 11.56 113.3/g = 11.56 11.56g = 113.3 g = 9.80 m/s^2
June 2, 2014

Kirr
P = Po(1+r)^n = $25,000 r = (1.825%/365)/100% = 5*10^-5 = Daily % rate expressed as a decimal. n = 365Comp./yr. * 4yrs. = 1460 Compounding periods. Po(1.00005)^1460 = 25000 Po = 25,000/1.00005^1460 = $23,240.
June 2, 2014

algebra math!
9pts/6wks = 1.5 Points/week.
June 1, 2014

physics
Wb = m*g = 40kg * 9.8N/kg = 392 N. = Weight of box. Fk=u*(Wb-F*sin31)=0.45(392-173*sin31) = 136.3 N.= Force of kinetic friction. Fn=F*CosA-Fk = 173*cos31 - 136.3 = 12 N. = Net force. a = Fn/m = 12/40 = 0.30 m/s^2.
June 1, 2014

Physics
hmax = L*sin A = 5*sin40 = 3.21 m. At top of incline: KE + PE = mg*hmax-Fk*L 0 + PE = mg*3.21-10*5 PE = mg*3.21-50. At bottom of incline: KE + PE = mg*3.21-50 KE + 0 = mg*3.21-50 KE = mg*3.21-50 = 35 J. m*9.8*3.21-50 = 35 31.5m-50 = 35 31.5m = 85 m = 2.7 kg. = Mass of box.
May 30, 2014

physics
V = Vo + g*Tr = 0 at max. ht. Tr = -Vo/g = -40/-9.8 = 4.08 s. = Rise time. T = 4.08-1 = 3.08 s. h1 = Vo*t + 0.5g*t^2 h1 = 40*3.08 - 4.9*3.08^2 = 76.7 m. h2 = 40*4.08 - 4.9*4.08^2 = 81.6 m. h2-h1 = 81.6-76.7 = 4.93 m. = Distance traveled in the last second.
May 30, 2014

physics
h = Vo*t + 0.5g*t^2 h = 0 + 5*3^2 = 45 m. = Height of object above gnd. (45-1)/4m = 11th floor.
May 30, 2014

physics
V^2 = Vo^2 + 2a*d V^2 = 0 + 10*10 = 100 V = 10 m/s.
May 30, 2014

algebra
I = 2.42*10^-5 Watts/cm^2. = Sound intensity. Io = 10^-16 Watts/cm^2 = Reference sound intensity. dB = 10^Log(2.42*10^-5/10^-16) = 114.
May 29, 2014

physics
h = L*sin A = 5.5*sin30 = 2.75 m. Fn = mg*Cos A = 66*Cos 30 = 57.16 N. = Normal force = Force perpendicular to the ramp. Fk = u*Fn = 0.22 * 57.16 = 12.57 N. = Force of kinetic friction. KE + PE = mg*hmax-Fk*L KE + PE = 66*2.75-12.57*5.5 = 112.4 J. 0 + PE = 112.4 PE = 112.4 J. ...
May 29, 2014

physics
1. W = Fk*d 25 * 12 Joules. 2. W = 175 * 12 Joules. 3. Wn = (175*12)-(25*12)
May 29, 2014

Physics
a. X = 45 N. Y = -22 N. F^2 = 45^2 + (-22)^2 = 2,509 F = 50.09 N. b. d = 22m/s * 3s = 66 m. Work = F*d = 50.09 * 66 = 3306 Joules.
May 29, 2014

Physics! Help
F1 + F2 = 96.2N.[55.4o] + 11.6N.[41.2o] X = 96.2*cos55.4 + 11.6*cos41.2=63.35 N
May 29, 2014

ALGERBRA
What are the "2 ways?" Perhaps some punctuation would help.
May 29, 2014

Physics
F = m*a = 1350 N. Impulse=m*V = m*(a*T) = 1350*6.2*10^-3= 8.37 kg-m/s.
May 29, 2014

Physics
D=2m[270o] + 16m[180o] + 24m[90o]+36m[180o]. Add the two 180o vectors directly: D = 2[270o] + 52[180o] + 24[90o] X = 2*cos270+52*cos180+24*cos90 = -52 m. Y = 2*sin270+52*sin180+24*sin90 = 22 m. D^2 = (-52)^2 + 22^2 = 3188 D = 56.5 m.
May 29, 2014

Physics
a. d = V*T = 420 m. (12.5-2.70) * T1 = 420 T1 = 420/(12.5-2.70) = 42.9 s. b. T2 = 420/(12.5+2.7) = 27.6 s. T = T1+T2 = 42.9 + 27.6 = 70.5 s. c. T1 = 420/12.5 = 33.6 s. T2 = T1 = 33.6 s. T = 33.6 + 33.6 = 67.2 s.
May 29, 2014

physics
V=100mi/h * 1600m/mi * 1h/3600s = 44.44m/s V = Vo + a*t = 0 a = -Vo/t = -44.444/10^-3=-44,444 m/s^2 F = m*a = 0.145 * (-44,444) = - 6444 N.
May 28, 2014

physics
Da = 69.5*T Db = 84.3*T B will have to travel 394 m(0.394km) farther than A to catch up: Db = Da + 0.394km 84.3 * T = 69.5 * T + 0.394 84.3T-69.5T = 0.394 14.8T = 0.394 T = 0.02662 h. = 1.60 Min. to catch up.
May 28, 2014

math
Slope = Tan A = Y/X = 1/6 A = 9.46o
May 27, 2014

math
Slope = Y/x = 16 Y/3 = 16 Y = 48 m.
May 27, 2014

physics
W = F*d*cos A = 457 * 6.2 * Cos 8 = 2806 J.
May 26, 2014

college physics
mgh2 - mgh1 = mg(h2-h1) = mg(3.1) = 64.7*9.8(3.1) = 1966 Joules.
May 26, 2014

college physics
a. Always negative.
May 26, 2014

Physics
The force of the golf club acts in parallel with the motion of the ball which is 28o. So my answer is 1650 N. @ 28o. Since they did not ask for the direction of the force, I did not include the angle. Your answer is not the full force acting on the ball; it is the hor. ...
May 26, 2014

Physics
a=(V-Vo)/t a = (55-0)/1.5*10^-3=36670 m/s^2 F = m*a = 0.045 * 36,670 = 1650 N.
May 26, 2014

Business mat
7x + 3 = 7x + b b = 7x-7x+3 = 3
May 24, 2014

Math
Eq1: Y = x^2+3x-4 Eq2: Y = 2x+2 In Eq1, replace Y with 2x+2 and solve for X: 2x+2 = x^2+3x-4 x^2+3x-2x = 2+4 x^2+x = 6 x^2+x-6 = 0 C = -6 = -2*3. (x-2)(x+3) = 0 x-2 = 0, X = 2. x+3 = 0, X = -3. Solution: X = -3, and 2.
May 23, 2014

math
1. Y = 4x + 12 = $44. 4x = 44-12 = 32 X = 8 Months = Oct. of same yr. 2.C 3. 8 < x + 3 X > 8-3 X > 5. 7 > 5 Answer = b = 7.
May 23, 2014

Math
Bought X boxes. Sold (x-5) boxes. Cost = $Y per box Selling price = $(y+0.1) per box. P = $6 * 1.25 = 7.50 = Sale price. (x-5)(y+0.1) = 7.50 xy + 0.1x - 5y - 0.5 = 7.5 Eq1: xy + 0.1x - 5y = 8 Eq2: xy = $6.00 Y = 6/x In Eq1, replace Y with 6/x: 6 + 0.1x - 30/x = 8 0.1x - 30/x...
May 23, 2014

math
Martin is X yrs. old. Joan is (x-3) yrs. old. 4x/5 = x-3 Multiply both sides by 5: 4x = 5x-15 X = 15 (4/5) * 15 = 12 yrs. = Joan's age.
May 23, 2014

math
Answer = b.
May 23, 2014

math
I = 2.42*10^-5 watts/cm^2 = Intensity. Io = 1*10^-16 watts/cm2 = Reference. db = 10*Log(I/Io) db = 10*Log(2.42*10^-5/1*10^-16) db = 10*Log(2.42*10^11) = 114.
May 23, 2014

math
Thu sales = $X Sat sales = $2X Other 4 days = $X/2 X/(x+2X+X/2) = X/(3 1/2)x = X/(7x/2) = x * 2/7x = 2/7.
May 23, 2014

physics
KE = 0.5m*V^2 = 900,000 J. 0.5*2000*V^2 = 900,000. Solve for V in m/s.
May 21, 2014

Algerbra 2
V = Vo - Vo*r*T V = 16,400 - 16,400*0.24*2 = $8528
May 21, 2014

Math
Do you mean: A(7,3.-4), B(-3,1,0). If so, X = (7+(-3))/2 = 2. Y = (3+1)/2 = 2. Z = (-4+0)/2 = -2. (x,y,z) = (2,2,-2).
May 21, 2014

Math
See previous post.
May 21, 2014

Math
C(h,k), P(x,y). x - h = x+5 x-x-h = 5 -h = 5 h = -5 y-k = y-2 y-y-k = -2 -k = -2 k = 2 C(-5,2). r = sqrt(9) = 3 Units.
May 21, 2014

math
-15-(-4) + (-12) + -8 -9 = -15 + 4 -12 -17 = -44 + 4 = -40.
May 21, 2014

Science
B. 1.
May 21, 2014

Science
1d. 2a.
May 20, 2014

Math
Incomplete.
May 20, 2014

Science
W = F*d = 200 * 45.5
May 19, 2014

physics
T^2 = 4pi^2(L/g) = (2.45)^2 39.48(1.25/g) = 6.00 6g = 49.35 g = 8.23 m/s^2
May 19, 2014

Math
csc R = 13/12 = 1/sin R 1/Sin R = 13/12 sin R = 12/13 = Y/r. X^2 + Y^2 = r^2 X^2 + 12^2 = 13^2 X^2 = 13^2 - 12^2 = 25 X = 5. Tan T = Y/X = 12/5
May 19, 2014

Algebra
Tan A = 5.67 A = 80 Degrees.
May 19, 2014

Geometry
A(0,0), B(a,0). AB is a hor. line, because Y is constant. AB = a - 0 = a. D(0,b), C(a,b). DC is a hor. line. DC = a - 0 = a. AB = DC, Because quantities that are = to the same or = quantities are = to each other. A(0,0), D(0,b). AD is a Vertical line, because X is constant. AD...
May 19, 2014

algebra
h max = ho + (V^2-Vo^2)/2g h max = 80 + (0-(64^2))/-64 = 144 Ft above gnd.
May 19, 2014

maths
Multiply numerator and denominator by 2^-(1-n): 1/2^(1-n) = 2^-(1-n)/1 = 2^(-1+n) = 2^(n-1)
May 19, 2014

maths
a. 16 = 2^4 b. 2^m/8 = 2^m/2^3 = 2^(m-3)
May 19, 2014

Algebra
P = Po(1+r)^n P = $25,000 Po = ? = Initial principal. r = (8%/2)/100% = 0.04 = Semi-annual % rate expressed as a decimal. n = 2Comp./yr. * 3.5yrs. = 7 Compounding periods. P = Po(1.04)^7 = 25,000 Po = 25,000/1.04^7 = $18,997.95 Down.
May 19, 2014

Physics
a = (V-Vo)/t = (-46-30)/5*10^-3 = -15.2*10^3 m/s^2. F = m*a = 0.15 * (-15,200) = -2280 N.
May 18, 2014

Math
a. Bal = 739.65 - 0.05*739.65 + 179.39 = $882.06 b. P min = 0.05 * 882.06
May 18, 2014

math
Ab = Ab = (W*L)/2 = (6*9)/2 = 27 in^2 = Area of the base. V = (Ab*h)/3 = (27*4)/3 = 36 in^3.
May 18, 2014

math
As = 2(L*h) + 2(W*h) + 2(L*W) As = 2(2*12) + 2(9*12) + 2(2*9) =
May 18, 2014

math
I don't know how they came up with $5100; perhaps you should double check that number. In a discounted loan, the discounted amount(Int.) is paid up-front by deducting it from the amount borrowed: Ab = $2,000 = Amount borrowed = Face value. Ar = Amount received by borrower...
May 18, 2014

physics
Vo = 12m/s[50o] Xo = 12*Cos50 = 7.71 m/s. Yo = 12*sin50 = 9.19 m/s. Tr = -Yo/g = -9.19/-9.8 = 0.938 s. Tf = Tr = 0.938 s. = Fall time. Tr+Tf = 0.938 + 0.938 = 1.876 s. = Time to return to launching height. Range=Xo * (Tr+Tf) = 7.71 * 1.876=14.46m D max = 14.46 + 8m/s * 1.876s ...
May 17, 2014

physics
Incomplete.
May 17, 2014

Physics
P = (0.45m/3.6m) * 1s. = 0.125 s. = The period of the wave. Freq. = 1/P = 1/0.125 = 8 Cycles/s = 8 Hz.
May 17, 2014

Physics
d=V*T = 3*10^8 * (1.9*10^-3/2) = 2.85*10^5 m.
May 17, 2014

Geometry
As = 2*(W*h)) + 2*(L*h) + 2(L*W) a. As = Al + 2*(L*W) = 992 Ft^2 Al + 2*(20*12) = 992 Al = 992 - 480 = 512 Ft^2.=Lateral area. b. Al = 2(W*h) + 2(L*h) = 512 Ft^2 2(12*h) + 2(20*h) = 512 Solve for h.
May 17, 2014

physics
Circumference = pi*2r = 3.14 * 80 = 251.3 cm. = 2.513 m. V=300rev/min * 2.513m/rev * 1min/60s = 12.57 m/s. = Linear speed. Va = 12.57m/s * 6.28rad/2.513m=31.4rad/s = Angular speed.
May 17, 2014

physics
X = 100N Y = 100N Tan A = Y/X = 100p/100 = 1.0 A = 45o = Direction. Fr = X/Cos A = = 100/Cos45=141.4N[45o]= Resultant force. a=Fr/m=141.4[45o]/100kg=1.414m/s^2[45o].
May 16, 2014

math
Ans: D
May 15, 2014

Pre cal
1. AB+BC = 200km[110o] + 100km[37o] X = 200*cos110 + 100*cos37 = 11.46 km. Y = 200*sin110 + 100*sin37 = 248.1 km. D^2 = X^2 + Y^2 = (11.46)^2+(248.1)^2 = 61,685 D = 248.4 km 2. V = 530mph[N25oW] = 530mph[115o] CCW.
May 15, 2014

Pre cal
1. An airplane flies 200 km on course 110 degrees from point A to point B. At point B the pilot changes course to 37 degrees. The plane then flies 100 km to point C. Find the magnitude of the net displacement from A to C. 2. A plane is flying on a bearing of 25 degrees west of...
May 15, 2014

Physic
k = 50N/(25-20)cm = 10N/cm. L = 20cm + (100N/10N) * 1cm = 30 cm.
May 15, 2014

algebra
Po = $32,500 @ 69%? for 3 years. P1 = Po(1+r)^n. Compounded annually. P1 = 32,500(1+0.69)^3 = $156,871.29 P2 = 32,500(1+0.69/2)^6 = 192,405.32 P3 = 32,500(1+0.69/4)^12 = 219,400.48 P4 = 32,500(1+0.69/12)^36 = 243,207.46 P5 = 32,500(1+0.69/365)^1095=257,053.95 P6 = 32,500(1+0....
May 14, 2014

math
Assuming simple interest: A. Po = 2055.99-400 = 1655.99 P = Po + Po*r*t P = 1655.99 + 1655.99*0.0725*2 P = 1655.99 + 240.12 = $1896.11 1896.11/24mo = $79.00/Mo. B. P = 180/mo * 12mo = $2160. r = (p-Po)/Po = (2160-2055.99)/2055.99 = 0.0506 = 5.06% Per annum C. Option 1: $1896....
May 14, 2014

Math
(4/3)*Log(z+2) = Log 4 Log(z+2) = Log 4/(4/3) Log(z+2) = (3/4)*Log 4 = 0.4515 10^(0.4515) = z+2 z+2 = 2.828 Z = 0.828
May 14, 2014

Math
V(1,2), W(-2,-3) X = 1 + (-2) = -1. Y = 2 + (-3) = -1. (x,y) = (-1,-1).
May 13, 2014

math
A(-2,3),--B(4,3) C(-2,-2), D(4,y) AC = -2-3 = -5 BD = AC = -5 = y-3 y-3 = -5 Y = -2.
May 13, 2014

Algebra 1
post it.
May 13, 2014

Algebra 1
See previous post: Tue,5-13-14, 1:15 PM.
May 13, 2014

Algebra 1
2x^2 + 7x + 8 = 0 B^2 = 7^2 = 49 4AC = 4*2*8 = 64. Since B^2 is less than 4AC, there are no real solution. But there are 2 imaginary solutions: X = (-B +-sqrt(B^2-4AC))/2A X =(-7 +-sqrt(49-64))/4 X = (-7+-sqrt(-15))/4 X = (-7+-sqrt(15*-1))/4 X = (-7+-(3.87i))/4 X = -1.75 + 0....
May 13, 2014

Algebra 1 Answer Evaluation
V = Vo + g*Tr = 0 Tr = (V-Vo)/g = (0-64)/-32 = 2 s. = Rise time. Tf = Tr = 2 s. = Fall time. Tr+Tf = 2 + 2 = 4 s. = Time it takes to return to gnd.
May 13, 2014

Math - Proportion
a. I = P^2/V b. I = (2P)^2/2V = 4P^2/2V = 2P^2/V. Therefore, I is doubled.
May 13, 2014

Algebra 1
(x+2)(x-5) = 60 x^2-5x +2x - 10 = 60 x^2 - 3x - 70 = 0 C = -70 = 7*(-10). B = 7 + (-10) = -3. (x+7)(x-10) = 0 x+7 = 0, X = -7. x-10 = 0, X = 10.
May 13, 2014

Physical World Concepts
Fn = 250 - 120 = 130 N.
May 13, 2014

math
Compounded Daily? Monthly? Annually?
May 12, 2014

Algebra
Width = W Ft. Length = (W+2) Ft. Area = (W+2)*W = 15Ft^2 W^2 + 2W - 15 = 0 C = -15 = -3*5 (W-3)(W+5) = 0 W-3 = 0 W = 3 W+5 = 0 W = -5. The width can't be negative. Therefore, W = 3 Ft. Length = W+2 = 3 + 2 = 5 Ft.
May 12, 2014

Finance
P = Po(1+r)^n P = $3,800 r = (8.9%/12)/100% = 0.00742 = Monthly % rate expressed as a decimal. n = 12comp./yr. * 5yrs.=60 Compounding periods. P = Po(1+0.00742)^60 = 3800 Po*(1.00742)^60 = 3800 Po = 3800/(1.00742)^60 = $2438.65 = Present value.
May 12, 2014

Algebra 1 (Step-by-Step)
1. -7 = X^2 x^2 + 7 = 0 X =( -B +- sqrt(B^2-4AC))/2A X = (0 +- sqrt(0-28))/2 = sqrt(28*(-1))/2 = 5.29i/2 = +-2.65i
May 12, 2014

math
10. P1 = Po(1+r)^n Po1 = $5,000 r = (6%/2)/100% = 0.03 n = 2comp/yr. * 2yrs. = 4 Compounding periods. P1 = 5000(1.03)^4 = $5627.54 in 2 yrs. P2 = P1(1+r)^n r = (8%/4)/100% = = 0.02 n = 4comp/yr. * 1.5yrs. = 6 Compounding periods. P2 = 5627.54(1.02)^=$6337.53 in 3.5 yrs.
May 12, 2014

math
a. Ar = Ab - Ab*r*t Ar = Ab - Ab*(0.055/360)*(60-15)=997.77 Ab - Ab*0.006875 = 997.77 0.993125Ab = 997.77 Ab = $1004.68 = Amt. borrowed. Ac = Ab-Ar = 1004.68 - 997.77 = $6.91 = Amt. charged. b. Face Value = Ab = $1004.68
May 12, 2014

math
5. Ar = Ab - Ab*r*t = 2,000 Ab - Ab*(0.08/360)*120 = 2,000 Ab - 0.02667Ab = 2000 0.97333Ab = 2000 Ab = $2,054.79 = Amount borrowed.
May 12, 2014

math
Correction: My calculations was based on a 4-day loan; it should be for 4 months: 2. Pr = Po - Po*r*t = 12,000 Po - Po*(0.095/12)*4 = 12,000 Po - Po*0.03167 = 12000 0.96833Po = 12,000 Po = $12,392.46
May 12, 2014

math
1. P = Po - Po*r*t P = 5000 - 5000*(0.085/360)*180 P = 5000 - 212.50 = $4787.50 = Amt. received by Joanne(Proceeds). 2. P = Po - Po*r*t = 12,000 Po - Po*(0.095/360)*4 = 12,000 Po - Po*0.00106 = 12000 0.99894Po = 12,000 Po = $12,012.68
May 12, 2014

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